## 390 Reputation

4 years, 229 days
i would also not like to ask, but if not ask, what should i do?

## @Kitonum  A := Matrix([[-2,1,1],[0...

A := Matrix([[-2,1,1],[0,2,0],[-4,1,3]]);

A:=[<-2,1,1>, <0,2,0>, <-4,1,3>];
S1 := LinearAlgebra:-Basis(A);

A:=[<-2,0,-4>, <1,2,1>, <1,0,3>];
S1 := LinearAlgebra:-Basis(A);

and

A:=`<|>`(`<,>`(-2, 0, -4), `<,>`(1, 2, 1), `<,>`(1, 0, 3));
S1 := LinearAlgebra:-NullSpace(A);

what is wrong with maple 12?

but output are not [1,4,0],[1,0,4],[1,0,1]

## @AmusingYeti  moreover, how to tra...

moreover, how to translate this condition statement?

if op(Expr)==indets(Expr3,{string,name})[countvar2-ii+1]:

i tried

if Expr.args==list(Expr3.free_symbols)[countvar2-ii]:

but not correct

## @AmusingYeti   i use this exp...

i use this expression in maple is easy

test1 := OO(AA(A,B),C)

but in python and sympy

need

from sympy.abc import x,y,z,a,b,c

but OO and AA these kind of expression can not be used

how to do?

## @Kitonum actually I am finding geom...

actually I am finding geometry axioms of newton equations

is this correct?

or is it possible?

as I have a sense that there are many possible

systems that can embedded in newton equation

## @vv  slope is tangent of angle a ...

slope is tangent of angle

a right triangle with total 180 degree of 3 interior angles

## @Ramakrishnan  actually i would li...

actually i would like to find a system which after solve this system will return v=u+at  and  s=u*t+1/2*a*t^2

solution := solve(unknownsys, [...]);

solution := [ v=u+at , s=u*t+1/2*a*t^2 ];

but there is only 2 equations for 5 variables,

is there some equations missing?

and

is there any function input these solution set that can return an invariant?

## @tomleslie  it really works  ...

it really works

this prove that there is no need to use the most

simplified logic , this intermediate result can also

work

And consider wildcard bit as 1 in summation

Is correct method

Thank you very much

## @eilers  following the doing of ex...

following the doing of exponential, it should have a sum,

i do not understand why remove sum

## @eilers  if specify limit on integ...

if specify limit on integral, which range is correct?

i choose from 0 to 1, then does it mean that it can remove sum(..., x=0..infinity)?

hoyeung1:= sum((Int(exp(LambertW(1/(-1+x))*(-1+x)), x=0..1)), x=0..infinity);

## @Axel Vogt  when using maple 12 W...

when using maple 12

Warning, unable to evaluate the functions to numeric values in the region; see the plotting command's help page to ensure the calling sequence is correct

no graph

then i try

Digits:=15:
f:= x ->
evalf( Int('t -> Re(exp(-t*LambertW(-1/t)))', 1 .. x, method=_d01ajc) )
+evalf( Int('t -> Im(exp(-t*LambertW(-1/t)))', 1 .. x, method=_d01ajc) )*I:
g:= (-1)/f+1;
g:= f;
[Re@g, Im@g]:
plot(%, 0 .. 2, -10 .. 10, color=[red,blue, grey]);

still no graph

which version of maple can plot?

thank you

## @tomleslie sorry i use a wrong form...

sorry i use a wrong formula from googled result

after refer from

https://en.wikipedia.org/wiki/List_of_representations_of_e

exponential1 := sum((1/n!), n=0..infinity);
exponential1 is not a decimal number, it is exp(1)

hoyeung1:= sum((Int(exp(LambertW(1/(-1+x))*(-1+x)), x)), x=0..infinity);

hoyeung2:= sum((Int(exp(LambertW(1/(-1+x!))*(-1+x!)), x)), x=0..infinity);

how to evalute hoyeung1 or hoyeung2 as a decimal number?

how to evalute hoyeung^x as a decimal number function is func1 := proc(x) return hoyeung^x end proc:

but i do not know whether
sum((Int(exp(LambertW(1/(-1+x))*(-1+x)), x))*m^x, x=0..infinity) = hoyeung^x
or

sum((Int(exp(LambertW(1/(-1+x!))*(-1+x!)), x))*m^x, x=0..infinity) = hoyeung^x

if not, using hoyeung^1 , then enough to calculate hoyeung^x just using power

can limit(1+(Int(exp(LambertW(1/(-1+x))*(-1+x)), x)))^x, x=infinity) = hoyeung^1 ?

## @eilers  power of something or dif...

power of something or differential of power such diff(y(x), x) ^ n

i do not know so want to find it

## @Markiyan Hirnyk  i use reasoning ...

i use reasoning to guess two equations and dsolve, this is what i got. hope you are clear.

sol := dsolve(ln(diff(y(x),x)) = diff(y(x),x)^(1/(1-x)), y(x));
ma := subs(_C1=1, rhs(sol));
Int(exp(LambertW(1/(-1+x))*(-1+x)), x)+1;
with(plots):
complexplot(evalf(subs(x=m, ma)), m = -Pi .. Pi);

sol := dsolve(ln(diff(y(x),x)) = diff(y(x),x)^(1/(1-y(x))), y(x));
ma := subs(_C1=1, rhs(sol));
x-Intat(1/exp((-1+_a)*LambertW(1/(-1+_a))), _a = y(x))-_C1 = 0;
with(plots):
complexplot(evalf(subs(x=m, ma)), m = -Pi .. Pi);