ComputerUser

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8 years, 284 days

Social Networks and Content at Maplesoft.com

Seldom to ask question after retired math hobby Just waiting for beauty who born in 1994 And waited for her email to mavio@protonmail.com What is the difference in ownership among different universe?

MaplePrimes Activity


These are replies submitted by ComputerUser

@tomleslie 

how to change to output all possible set of a, b, c instead of maximise?

@Carl Love 

i would like to automate to change suspected pattern into a system equations to solve and then verify with sorting algorithm by comparing whether all data matched

@tomleslie 

error after run code

would like to test A+B <= 59  and A+B+C <= 57 too

errorinmaple2015.mw

@Carl Love 

is pattern Regex Solver equal math regex solver?

how to write a pattern regex Solver?

can accumulate function and sorting algorithm do pattern regex solver?

@acer 

will the result or accuracy different between cpu and GPU when doing numerical calculation?

@Kitonum

sorry , 

i discover missing equal operator 

it works now , please delete this question.

@acer 

I find distribution function

but still not work

I removed picture.

@Joe Riel 

I removed picture

@Carl Love 

difficult to express in screenshot

it is just my sense to test my observation hypothesis

i do not know how to use too

i think guess actual use is mark it as a change

@asa12 

sequence faster or for loop faster?

@Kitonum 

is there artificial intelligence work in this way?

@Kitonum 

thanks, i forget hashtable value  can use list too

yesterday my status is not well, today i am refresh to use python do below

chosen1 = {}
chosen2 = {}
chosen3 = {}
chosen4 = {}
chosen5 = {}
chosen1[1] = [2]
chosen1[2] = [3]
chosen2[2] = [3]
chosen2[2] = chosen2[2]  + [5]
chosen3[3] = [4]
chosen3[5] = [9]
chosen4[4] = [5]
chosen4[9] = [8]
chosen5[5] = [6]
chosen5[8] = [12]

for i0 in chosen1.keys():
    for i1 in chosen1[i0]:
        if i1 in chosen2.keys():
            for i2 in chosen2[i1]:
                if i2 in chosen3.keys():
                    for i3 in chosen3[i2]:
                        if i3 in chosen4.keys():
                            for i4 in chosen4[i3]:
                                if i4 in chosen5.keys():
                                    for i5 in chosen5[i4]: 
                                        print([i, i1, i2, i3, i4, i5]);
 

@tomleslie 

very good function

it seems not need accumulate function

@vv 

my notebook is faster to run web now.

i attached my code,

but the result different from table of the book photo

at orbit size 3 , only two number of each, but book photo show all are 3 numbers

restart:
with(combinat):
with(group):
FixPoints := (a,n) -> {seq(i,i=1..n)} minus {op(map(op,a))}:
a := [[seq(i,i=1..6)],[seq(i,i=7..9)]]:
b := a:
aa := []:
countlist := []:
for i to 6 do
tt := b;
if tt = [] then
 tt := permgroup(9, {[]}):
end if:
count := 1:
orbitlist := []:
continuerun := 0:
for j from 1 to 7 do
if continuerun = 0 then
if b = [] then
if orbit(tt,j) in orbitlist then
 continuerun := 1:
else
 orbitlist := [op(orbitlist), orbit(tt,j)]:
end if:
else
if orbit({tt},j) in orbitlist then
 continuerun := 1:
else
 orbitlist := [op(orbitlist), orbit({tt},j)]:
end if:
end if:
end if:
od:
if nops(orbitlist) in countlist then
 rr := 0:
else
 countlist := [op(countlist), nops(orbitlist)]:
 lprint('a'^i=b, "orbit size=",nops(orbitlist)):
end if:
aa := [op(aa), b]:
b := mulperms(b,a);
od:

 

@vv 

I have network security concern to not to use mobile carrier network

how about the next two questions?

start from a^2 , result different from book photo?

how to calculate the orbit result at orbit size 3 at bottom table of the book photo?

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