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Question: what is the proplem

Question:what is the proplem

yasir 72 5 Maple 15
student
April 27 2012
0


> 

eq1 := `&x`(c^2, a0)-`&x`(3/2*(b+k), a0^2)+`&x`(a, c(`&x`(2*a2, mu^2)+`&x`(`&x`(a1, lambda), mu))) = 0

c^2*a0-((3/2)*b+(3/2)*k)*a0^2+a*c(2*a2*mu^2+a1*lambda*mu) = 0

 (1)
> 

eq2 := `&x`(c^2, a1)-`&x`(`&x`(3*(b+k), a0), a1)+`&x`(a, c(`&x`(`&x`(6*a2, lambda), mu)+`&x`(2*a1, mu)+`&x`(a1, lambda^2))) = 0

c^2*a1-(3*b+3*k)*a0*a1+a*c(6*a2*lambda*mu+2*a1*mu+a1*lambda^2) = 0

 (2)
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eq3 := `&x`(c^2, a2)-(3/2)*(b+k)(`&x`(2*a0, a2)+a1^2)+`&x`(a, c(`&x`(8*a2, mu)+`&x`(3*a1, lambda)+`&x`(4*a2, lambda^2))) = 0

c^2*a2-(3/2)*b(2*a0*a2+a1^2)-(3/2)*k(2*a0*a2+a1^2)+a*c(8*a2*mu+3*a1*lambda+4*a2*lambda^2) = 0

 (3)
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eq4 := -`&x`(`&x`(3*(b+k), a1), a2)+`&x`(a, c(2*a1+`&x`(10*a2, lambda))) = 0

-(3*b+3*k)*a1*a2+a*c(2*a1+10*a2*lambda) = 0

 (4)
> 

eq5 := -`&x`(3/2*(b+k), a2^2)+`&x`(`&x`(a, c)*6, a2) = 0

-((3/2)*b+(3/2)*k)*a2^2+6*a*c*a2 = 0

 (5)
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solve({eq1, eq2, eq3, eq4, eq5}, {a0, a1, a2, c, k})

Warning, solutions may have been lost

  
> 

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