Question: Evaluation gone wrong


Why does "eval(c, [b=1,l=1])" turn out to be "1" not "1/1+x"??? its driving me cracy. THX

restart

 

a:=(1/(1+x/l))

1/(1+x/l)

(1)

eval(a, [l=1])

1/(1+x)

(2)

eval(a, [x=2,l=1])

1/3

(3)

c:=(1/b(1+x/l))

1/b(1+x/l)

(4)

eval(c, [b=1,l=1])

1

(5)

 



 

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