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Question: powsolve with removable singularities

Question:powsolve with removable singularities

_Maxim_ 729
powseries formal-series
December 02 2017
0 
a := powseries:-powsolve(diff(f(z), z)-f(z)/z = 0);

seq(a(i), i = 0 .. 5);
                        0, 0, 0, 0, 0, 0

Seems that powsolve is constructing the relation k*a(k)-a(k) = 0 and solving it as a(k)=0. I think powsolve should detect such cases (regardless of whether or not they're supported).
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