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Question: How do I interpret solutions which do not verify my equation ?

Question:How do I interpret solutions which do not verify my equation ?

FormatB 25 Maple 15
solve assumptions
November 19 2018
1

Hello Everyone,

First of all I want to thank you to pay attention to my post.

For some reasons I want to know when does the root of my solution is equal to 0 isolating α, which yields the following equation
 

(6*alpha^4*l^2-7*alpha^3*l^2+6*alpha^3*l+2*alpha^2*l^2-6*alpha^2*l+alpha*l+3*alpha-2*sqrt(alpha^3*l^2*(alpha*l-l+1)*(9*alpha^4*l-13*alpha^3*l+9*alpha^3+6*alpha^2*l-12*alpha^2-alpha*l+6*alpha-1))-1)*(-1+2*alpha)/(alpha^2*l-3*alpha+1)^2 = 0
``

  1/2, -1/l, (1/8)*(3*l+(9*l^2-16*l)^(1/2))/l, -(1/8)*(-3*l+(9*l^2-16*l)^(1/2))/l``

``

NULL

 

NULL

``

 

 

When I substitute 1/2 it verifies the equation, but when I substitute other solutions my equation is not verified. For instance substituting "α=-1/l" I get something different from 0 as you can see

``

``

(6*alpha^4*l^2-7*alpha^3*l^2+6*alpha^3*l+2*alpha^2*l^2-6*alpha^2*l+alpha*l+3*alpha-2*sqrt(alpha^3*l^2*(alpha*l-l+1)*(9*alpha^4*l-13*alpha^3*l+9*alpha^3+6*alpha^2*l-12*alpha^2-alpha*l+6*alpha-1))-1)*(2*alpha-1)/(alpha^2*l-3*alpha+1)^2
"(->)"(-2/l-2*(1/l^2)^(1/2))*(-2/l-1)/(4/l+1)^2"(=)"2*((1/l^2)^(1/2)*l+1)*(2+l)/(4+l)^2

``
My question is what are these "solutions" if they are not solutions ?

I attach the file in case you would take a look at it

Download Maple_question2.mw
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