Question: polylog vs. dilog

This is not a problem per se, but more to understand the background.


f := polylog(2, -x);

int(f/(x+1), x);

convert(f, dilog);

int(%/(x+1), x)


The integration of the polylog maple is not capable of doing, but after converting to dilog it finds an anti derivative.

That leads to the question, why is dilog as a separate to polylog(2,*) implemented anyway? Why couldn't it all be done with the more general polylog function?


I'm also wondering why maple has difficulties to integrate


for general a.

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