more proper divisors from Matt

Question:more proper divisors from Matt

Posted: Matt C Anderson 180 Product: Maple 13

June 11 2021

Hi all again,

Tried this.

Anyone know a theorem related to this?

My guess is (p1 -1) * (p2 -1) * ... * (pb -1) .

For p1, p2, ... pb all prime numbers.

Regards,

Matt

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