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Question: Why is orthopoly not seen as a package within a procedure?

Question:Why is orthopoly not seen as a package within a procedure?

mmcdara 6665 Maple 2015
package procedure orthopoly
August 26 2024
2


For years I observe that package orthopoly is not considered as a package within a procedure.
Finally I have decided to ask for clarifications: Can someone explain me why procedure f generates an error?
 

> 

kernelopts(version)

`Maple 2015.2, APPLE UNIVERSAL OSX, Dec 20 2015, Build ID 1097895`

 (1)


Without any procedure

> 

restart
> 

H(2, x)

H(2, x)

 (2)
> 

with(orthopoly):
> 

H(2, x)

4*x^2-2

 (3)


Within a procedure

> 

restart
> 

type(orthopoly, package)

true

 (4)
> 

f := proc(m)
  uses orthopoly:
  H(m, x)
end proc:

Error, `orthopoly` is not a module or member

  
> 

g := proc(m)
  orthopoly:-H(m, x)
end proc:

g(2)

4*x^2-2

 (5)
> 

 


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