Find the quadratic polynomial which interpolates (2,0), (6,1), (8,0). Start by setting f(x)=ax^2+bx+c, for example, and the unknowns as a,b,c.

Hello,

I have the following system of equations to solve which is quite big.. Does anyone know how I can solve it faster or in a more simple way?

Thanks 

solve({(-(1/((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p))))*((0.002+0.001)*sin(-0.39)-(0.001+1*(e+p))*cos(-0.39)*(e*(-m+(0.68/d)+(0.599/g))+j*m)-(1/((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p))))*((0.001+1*(j+p))*sin(-0.39)-(0.002+0.001)*cos(-0.39))*(j*(-n+(0/i)+(-0.73/l))+e*n...

eqt := y^5+y^4 + -0.5109*y^3 + -0.0595*y^2 + 0.0000-(-3.1086e-015*u^4 + u^3 + -0.5109*u^2 + -0.0595*u) = 0;

solve({eqt, y=m*t+c, u=n*t+d}, {y, u}, 'parametric');

solve({y^5+y^4 + -0.5109*y^3 + -0.0595*y^2 + 0.0000-(-3.1086e-015*u^4 + u^3 + -0.5109*u^2 + -0.0595*u) = 0, u=t}, [x,y]);

solve(eqt, [y(t), u(t)])

algcurves[parametrization](eqt, y, u, t);

all trials i failed

Hi. I have a question it goes.

Find the equation f(x) which satisfies the following conditions. f'(x)= 1/(1+cot(x)) and f(pi/4)=1.

So I enter the following in Maple and this is what I end up with.

http://s5.postimg.org/eriq99rs7/Maple.jpg

This should work as far as I can tell. The final diff command should return the original f'(x), but it doesn't. Can anyone tell me why?

I have used this exact method before on similair problems and it...

Hi,

I have a linear problem A*X = B, with dimensions of A approximately 500*1300, and B is a vector with only one nonzero coordinate.

I feed it to LinearSolve, and there are a *lot* of solutions - presented as one vector with linear polynomial coordinates.

How can I get only one (hopefully with as many zeros as possible) ?

Thank you in advance.

NoThik

Hi,

Does anyone know why I cannot solve the following system of equations?

solve({(-(0.1e-2+e+p)*j*(e*(-m+.68/d+.599/g)+j*m)/(((0.2e-2+0.1e-2)^2+(0.1e-2+e+p)*(0.1e-2+j+p))*i)+(0.2e-2+0.1e-2)*j*(j*(-n+0*(1/i)-.73/l)+e*n)/(((0.2e-2+0.1e-2)^2+(0.1e-2+e+p)*(0.1e-2+j+p))*i)-j*m/i)/(2*10) = -0.3e-2, (-(0.1e-2+e+p)*j*(e*(-m+.68/d+.599/g)+j*m)/(((0.2e-2+0.1e-2)^2+(0.1e-2+e+p)*(0.1e-2+j+p))*l)+(0.2e-2+0.1e-2)*j*(j*(-n+0*(1/i...

HI,

I have a system of ODEs like

Good morning sir,

In  general, there are five ways to decide the nature of a given square matrix based on the signs of the eigenvalues, for example

1. If the eigenvalues are positive then the nature is positive definite.
2. If the eigenvalues are negative then the nature is negative definite.
3. If the eigen values are nonnegative then the nature is Positive semidefinite.
4. If the eigenvalues are nonpositive then the nature is negative semi definite.
5. If the eigenvalues are positive and negative then the nature is indefinite.

triangle(T, [[x1,y1], [x2,y2], [x3,y3]]);

area:=proc(1/2*[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]);

AA:=(T)->[area(T)];

Hi, 

Struggling to get my head round how to plot the results of the follwoing, as it seems I have 4 variables...

I have a data file containing the results of the following problem:

1) Consider a cube. Each side (a,b,c) has a length of 1 unit.

2) Place an ion (0,0,0) where [a,b and c intersect] and find the associated energy at that point.

3) Move the ion to a point 0.05 units along side a to (0.05,0,0) and re-find the associated energy.

I want to solve the inequality sqrt(8*16^x - 1/2* 9^x) <= 3*4^x - 3^x

I tried 

restart:

solve(sqrt(8*16^x - 1/2* 9^x) <= 3*4^x - 3^x,x);

And I got 

Error, (in evala/inv/heuristic) cannot allocate memory (size=117506048).

How to solve the above inequality?

i do not want maple to round off some terms , for example 1.7777777777 which is rounded off 1.7777777778 . i do not want maple to round off the result,what should i do ?

Hi,

I'm trying to solve the following system of differential equations:

x''=(-c/m)*((x')^2+(y')^2)^1/2)*x'

y''=(-c/m)*((x')^2+(y')^2)^1/2)*y'

I need to solve them numerically as I've found out that trying to solve them analytically is impossible, and I really don't know how to do this in maple, I have initial conditions:

x(0)=0, y(0)=0, y'(0)=V0 sin theta, x'(0)= V0 cos theta.

Any help would be great.

Thanks

http://en.wikipedia.org/wiki/Twisted_cubic

1.

How to find S^3 : S^2*T : S*T^2 : T^3

2.

How to find X*Z-Y^2, Y*W-Z^2, X*W - Y*Z

Let a,b and c be the three roots of the equation :2012x^3+2013x+2014=0.Find (a+b)^3+(b+c)^3+(c+a)^3?