In this example, solve gives

solve({(1+x1)*(1+x3)>=0.966,(1+x1)*(1+x3)<=1.026,
(1+x2)*(1+x3)>=0.9975,(1+x2)*(1+x3)<=0.9987},{x1,x2});
 

  {           0.002000000000 (17. + 500. x3)
  { [{x1 <= - ------------------------------,
  {                      1. + x3

                0.002500000000 (1. + 400. x3)
        x2 <= - -----------------------------,
                           1. + x3

          0.002000000000 (-13. + 500. x3)
        - ------------------------------- <= x1,
                      1. + x3

          0.0001000000000 (13. + 10000. x3)
        - --------------------------------- <= x2}] , x3 < -1.
                       1. + x3

                  0.002000000000 (-13. + 500. x3)
        [{x1 <= - -------------------------------,
                              1. + x3

                0.0001000000000 (13. + 10000. x3)
        x2 <= - ---------------------------------,
                             1. + x3

          0.002500000000 (1. + 400. x3)
        - ----------------------------- <= x2,
                     1. + x3

          0.002000000000 (17. + 500. x3)
        - ------------------------------ <= x1}] , -1. < x3
                     1. + x3

Alec

In this example, solve gives

solve({(1+x1)*(1+x3)>=0.966,(1+x1)*(1+x3)<=1.026,
(1+x2)*(1+x3)>=0.9975,(1+x2)*(1+x3)<=0.9987},{x1,x2});
 

  {           0.002000000000 (17. + 500. x3)
  { [{x1 <= - ------------------------------,
  {                      1. + x3

                0.002500000000 (1. + 400. x3)
        x2 <= - -----------------------------,
                           1. + x3

          0.002000000000 (-13. + 500. x3)
        - ------------------------------- <= x1,
                      1. + x3

          0.0001000000000 (13. + 10000. x3)
        - --------------------------------- <= x2}] , x3 < -1.
                       1. + x3

                  0.002000000000 (-13. + 500. x3)
        [{x1 <= - -------------------------------,
                              1. + x3

                0.0001000000000 (13. + 10000. x3)
        x2 <= - ---------------------------------,
                             1. + x3

          0.002500000000 (1. + 400. x3)
        - ----------------------------- <= x2,
                     1. + x3

          0.002000000000 (17. + 500. x3)
        - ------------------------------ <= x1}] , -1. < x3
                     1. + x3

Alec

Thus far, neither Global (or whatever it was called) network on Linkedin, nor this one provided anything that I was aware of.

That is helpful for LinkedIn - in particular, I woudn't join it otherwise. The same as Facebook. But it seems as if neither Facebook nor Linkedin networks are especially helpful for Maplesoft. At least at this particular moment.

Creating a separate from MaplePrimes blog on the Maplesoft web site also seems strange. Those blog posts would be much more effective being posted here.

Alec

solve can be used, but it is buggy and may give a wrong answer.

For questions like that, examples would help - if you gave an example, somebody would show how to do it.

Alec

solve can be used, but it is buggy and may give a wrong answer.

For questions like that, examples would help - if you gave an example, somebody would show how to do it.

Alec

Looks better at the moment here, too, and searching worked OK just now (but not earlier.) Perhaps, they fixed something.

Alec 

My connection is OK (it is 10Mb cable), and all the other sites that I access appear momentarily - but not this one. I just tried searching for "digits" again, and again didn't get a response.

Alec

Searching Google, I didn't find the explanation of using Iota in this context.

The following seems interesting,

The Greek alphabet is the foundation of our written and spoken language. And it is the foundation of our mathematical system. And God embedded His Word through the Greek alphabet system. For in them we can understand who God is. For in the beginning, God was alpha, for He was the Maker. And Christ is pi, for He is the narrow Gate. And iota is the Holy Spirit for He penetrates the hearts of all men. And omega is the consolidation of the three, for omega is the end and the completion of all things.

Alec

It's a greek letter name, and looks like I in the display.

Alec

It is worth to notice also that, as acer mentioned in the recent nth digit of pi thread, the environmental variable Rounding should be set to 0 to get all the digits correct in the approxPi.

That would work for base 10. For other bases, some additional tricks, probably, should be used to ensure the correctness of the last few digits.

Alec

StringTools:-Iota also can be used,

basesymbols:=cat(map(StringTools:-Iota,["0".."9","A".."Z"])[]);

        basesymbols := "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"

Alec

Frankly, I don't understand why the community can't be reached on this site.

Alec

The derivative looks more simple - close to the generating function for Bernoulli numbers. So the similar formulas can be derived similarly - the recurrence (of length n) and the asymptotic, in particular.

I' was pretty busy yesterday and am going to be busy today, but I'll look into that in more detail during the weekend.

Alec

The derivative looks more simple - close to the generating function for Bernoulli numbers. So the similar formulas can be derived similarly - the recurrence (of length n) and the asymptotic, in particular.

I' was pretty busy yesterday and am going to be busy today, but I'll look into that in more detail during the weekend.

Alec

It looks as if less than 10000 digits of Pi are stored in Mathematica, and others are calculated,

In[4]:= Timing[RealDigits[Pi, 10, 1, -1000]]

Out[4]= {8.94467*10^-19, {{9}, -999}}

In[5]:= Timing[RealDigits[Pi, 10, 1, -10000]]

Out[5]= {0.016, {{8}, -9999}}

Alec