@Heeka I don't know about it. But a Google search on "Homotopy perturbation method" (in quotes) turns up 407,000 hits. Note the correct spelling of "homotopy".

When the Asker uploads the Mathematica Notebook, it should be in plain text form.

When the Asker uploads the Mathematica Notebook, it should be in plain text form.

@digerdiga Your code above works for me (if I put a semicolon after forget(x)). Try giving a restart command.

@digerdiga Your code above works for me (if I put a semicolon after forget(x)). Try giving a restart command.

@Adri van der Meer Not a bug. There is a subtle distinction between sqrt(x) and x^(1/2): The former checks whether x is a perfect square and the latter does not. Since 234256 is a perfect square, the computation with sqrt reduces to pure floating point.

@Adri van der Meer Not a bug. There is a subtle distinction between sqrt(x) and x^(1/2): The former checks whether x is a perfect square and the latter does not. Since 234256 is a perfect square, the computation with sqrt reduces to pure floating point.

@N00bstyle Whether you include a 0 is insignificant. The important thing is the decimal point. So, you could just make that "22."

Without the decimal point (or usage of evalf), Maple uses exact and symbolic computation as far as possible.

@N00bstyle Whether you include a 0 is insignificant. The important thing is the decimal point. So, you could just make that "22."

Without the decimal point (or usage of evalf), Maple uses exact and symbolic computation as far as possible.

@acer I think that you meant to say "limit tutor" instead of "integration tutor". And since there are two, the CalculusI:-LimitTutor needs to be specified (although the Precalculus:-LimitTutor may be the same thing for all I know).

I am absolutely shocked that the current edition of Stewart's Calculus derives those two fundamental trig limits with reference to l'Hopital's rule. I've taught from that text, and I assure you that in earlier times those limits were derived by geometric proof and the squeeze theorem.

@Markiyan Hirnyk Thanks. Although, the mix of numbers with extremely small and extremely large magnitudes is highly suspicious to me.

@Markiyan Hirnyk Thanks. Although, the mix of numbers with extremely small and extremely large magnitudes is highly suspicious to me.

@digerdiga Well, that's quite surprising! You have 17.02, and you still have the bug, yet it is gone for Acer on his 17.02.

There is no attached file on your post.

@Markiyan Hirnyk I can only give a Wikipedia reference right now. See the article "Complex numbers", sections "Algebraic characterization" and "Characterization as a topological field". Basically, any algebraically closed field containing R as a proper subset is isomorphic to C. Hence, it is two-dimensional over R.