Thanks for the response. I had no idea fsolve was the multivariate newton's method.

Do you know if there's anyway to limit the amount of iterations?  When I applied it to my functions, it output nine iterations; and that's probably because it just took a little longer for the solution to converge.

Also, just out of curiosity, what impact does the "2" have in this line:

infolevel[fsolve]:=2:


Thanks again, I appreciate you're time.

Thanks for the response. I had no idea fsolve was the multivariate newton's method.

Do you know if there's anyway to limit the amount of iterations?  When I applied it to my functions, it output nine iterations; and that's probably because it just took a little longer for the solution to converge.

Also, just out of curiosity, what impact does the "2" have in this line:

infolevel[fsolve]:=2:


Thanks again, I appreciate you're time.

f:= z-> z²;

complexplot3d(f,0+0*I..-10+10*I);

this gave me a plot where z = (-10 + 10i) gave me a value of 200, when in fact:

(-10 + 10I)(-10  + 10I) = 100 -200I -100 = ) -200i = f(z)

the graph looked like f(x,y) = x² + y² over the second quadrent but thats not the same as f(z) = z² in the second quadrent

f:= z-> z²;

complexplot3d(f,0+0*I..-10+10*I);

this gave me a plot where z = (-10 + 10i) gave me a value of 200, when in fact:

(-10 + 10I)(-10  + 10I) = 100 -200I -100 = ) -200i = f(z)

the graph looked like f(x,y) = x² + y² over the second quadrent but thats not the same as f(z) = z² in the second quadrent

Tried all three methods.