## 261 Reputation

17 years, 217 days

## I've been able to make...

I've been able to make following sum: "for i from 1 to 4 do total:=total+i end do;" The result is logic: 1,3,6,10. Now I want to make the sum of some terms I've already calculated and named by opl[i]. With I a posint. Now I write the command: "for i from 1 to 4 do total:=total+opl[i] end do;" This gives me the error of to many levels of recursion. I am not able to see the problem in what I've programmed. Thank you in advance,

## Thank you. Problem is clear...

Thank you. Problem is clear now.

## Thank you. Problem is clear...

Thank you. Problem is clear now.

## Thank you! Where logic...

Thank you! Where logic thinking could bring you to... Now I have an extra method to check myself on my exam mathematics next week.

## Thank you! Where logic...

Thank you! Where logic thinking could bring you to... Now I have an extra method to check myself on my exam mathematics next week.

## It helped me a lot. Now I...

It helped me a lot. Now I just have to insert the values manually and calculate the solutions. It's nice I have came so far but maybe there is a way to substitute these paramters also with Maple. I tried this: >F1 := Pi*(0.5)^2*x(t)+Pi/3*(y(t)/2)^2*y(t)=Pi/3; >dF1 := diff( F1, t ); <\prev> As solution I've got: dF1 := .25*Pi*diff(x(t),t)+1/4*Pi*y(t)^2*diff(y(t),t) = 0 <\prev> Now I try to substitute some values: subs(x(t)=-0.5,y(t)=(5/2)^(1/3),diff(x(t),t)=-0.01,dF1); <\prev> As solution I get: .25*Pi*diff(-.5,t)+1/8*Pi*5^(2/3)*2^(1/3)*diff(1/2*5^(1/3)*2^(2/3),t) = 0 <\prev> As you see Maple substitutes the values for x(t) and y(t) perfectly but with substituting dx/dt he has a little problem. Is there a way to get around this? Edit: Have post a little picture to make my problem clearer. http://img120.imageshack.us/img120/1106/probsxs8.jpg

## It helped me a lot. Now I...

It helped me a lot. Now I just have to insert the values manually and calculate the solutions. It's nice I have came so far but maybe there is a way to substitute these paramters also with Maple. I tried this: >F1 := Pi*(0.5)^2*x(t)+Pi/3*(y(t)/2)^2*y(t)=Pi/3; >dF1 := diff( F1, t ); <\prev> As solution I've got: dF1 := .25*Pi*diff(x(t),t)+1/4*Pi*y(t)^2*diff(y(t),t) = 0 <\prev> Now I try to substitute some values: subs(x(t)=-0.5,y(t)=(5/2)^(1/3),diff(x(t),t)=-0.01,dF1); <\prev> As solution I get: .25*Pi*diff(-.5,t)+1/8*Pi*5^(2/3)*2^(1/3)*diff(1/2*5^(1/3)*2^(2/3),t) = 0 <\prev> As you see Maple substitutes the values for x(t) and y(t) perfectly but with substituting dx/dt he has a little problem. Is there a way to get around this? Edit: Have post a little picture to make my problem clearer. http://img120.imageshack.us/img120/1106/probsxs8.jpg

## They are in function of t. I...

They are in function of t. I have the numeric value of dx/dt. I want Maple do write something like dy/dt + dx/dt and not really solve dy/dt so I could substitute in that equation that dx/dt is for example 5 and that I could calculate dy/dt. I don't now really if its possible. Can Maple not solve something like that symbolic?

## They are in function of t. I...

They are in function of t. I have the numeric value of dx/dt. I want Maple do write something like dy/dt + dx/dt and not really solve dy/dt so I could substitute in that equation that dx/dt is for example 5 and that I could calculate dy/dt. I don't now really if its possible. Can Maple not solve something like that symbolic?

## Great. That's all I needed...

Great. That's all I needed to know. Thank you for the help and patience!

## Great. That's all I needed...

Great. That's all I needed to know. Thank you for the help and patience!

## I'm starting all over....

I'm starting all over. Problems in my worksheet: 1) How do I convert an integer to a sqrt-form? Things I want to do better: 1) When I need to calculate for which t value a function is zero and for which t value a function is one then I use two solve commando's. Now I want combine this in one commando (If possible). Something like solve(y=0 and y=1,t). So that I get something of the form t=.. for y(0) and t=.. for y(1) on one line. Is this possible? 2) Same as above but with the commando subs(...). Can I calculate the function value for two different values of the variable. Something like subs(t=2 and t=3,y). So that I get something of the form y=.. for t=2 and y=.. for t=3. I tought that in both examples you could make use of AND but it would not work. In these functions I have took as example something of the form y(t). I hope it is explained well :)

## I'm starting all over....

I'm starting all over. Problems in my worksheet: 1) How do I convert an integer to a sqrt-form? Things I want to do better: 1) When I need to calculate for which t value a function is zero and for which t value a function is one then I use two solve commando's. Now I want combine this in one commando (If possible). Something like solve(y=0 and y=1,t). So that I get something of the form t=.. for y(0) and t=.. for y(1) on one line. Is this possible? 2) Same as above but with the commando subs(...). Can I calculate the function value for two different values of the variable. Something like subs(t=2 and t=3,y). So that I get something of the form y=.. for t=2 and y=.. for t=3. I tought that in both examples you could make use of AND but it would not work. In these functions I have took as example something of the form y(t). I hope it is explained well :)

## In my worksheet I had...

In my worksheet I had calculated the two values of y (6 and -6). Normally I would now calculate subs(y=6,K) and subs(y=-6,K) to find my two x values. This does not result in the correct values because I had already substituted y=2y in the equation. Now was my question if there is some way to reset the function or something like that?

## In my worksheet I had...

In my worksheet I had calculated the two values of y (6 and -6). Normally I would now calculate subs(y=6,K) and subs(y=-6,K) to find my two x values. This does not result in the correct values because I had already substituted y=2y in the equation. Now was my question if there is some way to reset the function or something like that?
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