> X:=Vector(100,(i)->i):
> X[61]:=X[60]:

> for i from 1 to 100 do
>   if X[i]=X[i+1] then
>     k := i;
>     break;
>   end if;
> end do:

> k;
                                      60

> i;
                                      60

acer

One way in which this sort of behaviour can arise is if expressions with beta are created each with different assumptions on beta. That is to say, distinct beta~ instances can be created. In such a case, such distinct instances may not cancel (and rightly so, if they have differing assumptions). For example,

> restart:
> assume(beta>0);
> a:=beta;
                                  a := beta~
 
> assume(beta>=0);
> c:=beta;
                                  c := beta~
 
> a-c;
                                 beta~ - beta~
 
> map(convert,a-c,`global`);
                                       0

acer

Could you post the values of A,B,C,D,E, and F? acer

Does this work for you? sol1:=fsolve(h(x)=h1(x),x,1..10); fsolve(h(x)=h1(x),x,avoid={x=sol1},1..10); acer

u:=[1,2,5]; op(u); max(op(u)); acer

Here's the default, usual situation in Maple,

> restart:

> about(x);
x:
  nothing known about this object

> is(sin(x),real);
                                     false

You can put assumptions on x, which is a sort of restriction of the domain when x is used as an argument of a function.

> assume(x::nonnegint);

> about(x);
Originally x, renamed x~:
  is assumed to be: AndProp(integer,RealRange(0,infinity))
 
> is(sin(x),real);
                                     true

acer

simplify( sqrt(4) ); assume(d>0); sqrt(d^2); acer

Have a look at ?LinearAlgebra,GenerateMatrix acer

To find the indeterminates, f := x^2*y + 10*z*w + 2*a*t; indets(f); nops(indets(f)); acer

This was in Maple 11.02, > e := (1+b)*x^2+a*(1+b)*x+b*(b-1)+2*b: > factor(expand(e)): > lprint(%); (1+b)*(b+x^2+a*x) Knowing the factor (b+1) in advance, this next was also possible for this example, > e := (1+b)*x^2+a*(1+b)*x+b*(b-1)+2*b: > (b+1)*simplify(e/(b+1)): > lprint(%); (1+b)*(b+x^2+a*x) acer

Plotting `xtba` vs `ytba` for a range of `T`, with fixed `press`.

ytba:=(press-exp(14.7569-2895.6078/(T+140.7459)))*exp(14.7569-2895.6078/(T+140.7459))/((exp(16.5270-3026.8900/(T+168.1400))-exp(14.7569-2895.6078/(T+140.7459)))*press);

xtba:=(press-exp(14.7569-2895.6078/(T+140.7459)))/(exp(16.5270-3026.8900/(T+168.1400))-exp(14.7569-2895.6078/(T+140.7459)));

plot(eval([xtba,ytba,T=30..50],press=100));

acer

Here's a couple of ideas. # replace with your procedure... `#mo("∇")`:=proc(V::Vector) map(sin,V); end proc: `#mo("∇")`:=`#mo("∇")`: Then after each time you grab the nabla from the Common Symbols palette (or cut and paste it) you would have to select the inserted symbol (only) with the mouse, and use the Context Menu action, 2D Math -> Convert To -> Atomic Identifer In this way, I was able to get it to look like a Del/nabla and act like a function on a Vector. I had to use round brackets though, like for any other procedure. Another way that worked for me was to issue, unprotect(VectorCalculus:-Nabla); After that, I could use the symbol from the palette without having to do Context Menu toggling each time. But even this way I couldn't get it to work without using brackets in order apply it, without receiving the error, Error, (in Typesetting:-delayGradient) unable to compute gradient until a co-ordinate system has been defined (see ?VectorCalculus:-SetCoordinates) I don't know if there's a clever workaround for that. acer

1) with(LinearAlgebra): A:=RandomMatrix(2): B:=RandomMatrix(2): X:=Vector(2,(i)->convert(cat("x",i),name)): Y:=LinearSolve(B,A.X); A.X-B.Y; 2) LinearAlgebra[GenerateMatrix]([x1-x3,x1+x2-x4, x1+x2, x3+x4],[x1,x2,x3,x4]); 3) evals:=Eigenvalues(evalf(A)); `+`( seq(`if`(Im(x)=0.0,signum(Re(x)),NULL),x in evals) ); acer

Here's my exam tip. When you do indefinite integrations, don't forget to add the constant (+ C). Those docked half-points add up. Do it like Maple does dsolve({diff(f(x),x)=x}) , not like it does f(x)=int(x,x) . acer

The colon at the end of a statement will instruct maple to suppress the printed or displayed output. A semicolon will not suppress the output. Your last three assignments ended with colons. acer