vv

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These are replies submitted by vv

Do you think that Maplesoft should invest a so much effort for typesetting?
Typesetting is a nice feature but I think that an excessive fine-tuning is too expensive.
I'd prefer these efforts be directed towards maths.
And anyway, Maple is not going to compete with LaTeX.
By the way, wouldn't it be more natural a LaTeX convention in the case of atomic variables?
It is not comfortable to use names like  `#msub(mi("x"),mn("1"))`  (in 1D notation)
(of course a macro() can be used here but even so...).

 

I also did not noticed the square. But Kitonum posted already a nice and complete solution.

P.S. It will be better in the future to post code instead of pictures.

@sajad 

 

Yes, Im(...) is strange. But here is something more strange:

 

evalc(RootOf(_Z^3-_Z-1));

RootOf(64*_Z^9-96*_Z^7-48*_Z^6+36*_Z^5+12*_Z^4-19*_Z^3+3*_Z-1)+I*RootOf(64*_Z^9+96*_Z^7+36*_Z^5-23*_Z^3)

(1)

Re(RootOf(_Z^3-_Z-1));

RootOf(_Z^3-_Z-1)

(2)

@_Maxim_ 

I think you forgot index=1 in RootOf. Then it works as expected.
(It's only evalf which takes index=1 by default.)


It seems that for rtables the procedure names are not correctly printed.

restart;

f:=x->x;

proc (x) options operator, arrow; x end proc

(1)

V:=Vector([f,`+`,7,`or`]);

_rtable[18446744074325918774]

(2)

V;

_rtable[18446744074325918774]

(3)

W:=Vector(4,i->V[5-i]);

_rtable[18446744074330358238]

(4)

%;

_rtable[18446744074330358238]

(5)

V+W;

_rtable[18446744074330360998]

(6)

%;

_rtable[18446744074330360998]

(7)

 

@Mariusz Iwaniuk 

You cannot obtain this conclusion! The series could be divergent. for some c's.
As it is easy to check, the equation has at most 3 real roots,

@asa12 

Consider the row operation Eij of adding the row i to row j.
If  Eij . X = X  for each i,j (i<>j) then obviously X = O.

@asa12 

Your definition of "invariant matrix" is missing. For the standard definition, the only matrix is zero.

@_Maxim_ 

But if f is just absolutely integrable (in the Lebesgue sense) then the series could be divergent at any point! And anyway the side limits f(x0+0), f(x0-0) may not exist.

@sand15 

It works for me.

Have you loaded plots?
Or, use plots:-display

@tomleslie 

For Digits:=21 the imaginary part is still present.

@asa12 

You have successfully found what? The zero matrix or something else?

@asa12 

If you are considering row additions E, then a matrix X is invariant under them (i.e. E.X = X, for each E)
iff X = 0. Probably this is not what you need.

@asa12 

You should explain what you are trying to do. Code only (which does not work correctly) does not say much.

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