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Is it possible to import questions from Maple TA i...

Asked by: mathstutor 35
export import
February 06 2017
0  4

Hi, I'd like to know if is it possible to import questions from Maple TA into Maple and use them in quizes, for example. Your help will be highly appreciated. Thank you.

I can't get solve to work...

Asked by: TheGamingEngineer 0
solve
February 06 2017
0  1

i have these commands:

restart;
with(plots);
with(VectorCalculus);
with(LinearAlgebra);
f := A-B+x^y/y;

g := x^y-y;
Solve({f = 0, g = 0}, {x, y});
              / /                     y    \         \
              | | y                  x     |         |
         Solve|< x  - y = 0, A - B + -- = 0 >, {x, y}|
              | |                    y     |         |
              \ \                          /         /

restart; with(plots); with(VectorCalculus); with(LinearAlgebra); f := A-B+x^y/y; g := x^y-y; Solve({f = 0, g = 0}, {x, y});

 

but I can't get it to actually solve the equations. what do I do  ?

solve ode srm motor...

Asked by: lucaud 40
February 06 2017
0  1

How I can solve it for P?

P=i^(2)r+(&DifferentialD;)/(&DifferentialD; t) (1/(2)l(tetha)i^(2))+1/(2)i^(2)(&DifferentialD;l(tetha))/(&DifferentialD; theta) w

attach i(t) "corrente", l(t) "induttanza", theta "angular", w "rotary speed"graph of funtions

thanks

Symbolic cut-off of high-order terms...

Asked by: illuminates 65
polynomial
February 05 2017
0  4

Hi! I have a variable polynomial expression and I want to cut off all the terms of order 3 and more, for every product of variables.

For example consider the polynomial P = x + y + a*x^2 + b*x^3 + c*x*y + d*x^2*y + e*x*y^2 + y^2, I want an operation who returns me a*x^2 + c*x*y + y^2

(terms for which the sum of exponents in x and y exceeds or less two are being deleted)

Is it possible?

 

how i can write this line ''for'' in maple?...

Asked by: 9009134 110
February 04 2017
0  2

hi..

how i can write this line ''for'' in maple?

thanks..

for.mw
 

TopEdge = "C";
BottomEdge = "C";
LeftEdge = "C";
RightEdge = "C";

"For[i = 1, i < m + 2, i++, w[i, 1] = 0; w[i, n + 1] = 0]; For[j = 1, j < n + 2, j++, w[1, j] = 0; w[m + 1, j] = 0]; If[TopEdge == "C", For[i = 1, i < m + 2, i++, w[i, 0] = w[i, 2]], If[TopEdge == "S", For[i = 1, i < m + 2, i++, w[i, 0] = -w[i, 2]], "Invalid Input Data!"]] If[BottomEdge == "C", For[i = 1, i < m + 2, i++, w[i, n + 2] = w[i, n]], If[BottomEdge == "S", For[i = 1, i < m + 2, i++, w[i, n + 2] = -w[i, n]], "Invalid Input Data!"]] If[LeftEdge == "C", For[j = 1, j < n + 2, j++, w[0, j] = w[2, j]], If[LeftEdge == "S", For[j = 1, j < n + 2, j++, w[0, j] = -w[2, j]], "Invalid Input Data!"]] If[RightEdge == "C", For[j = 1, j < n + 2, j++, w[m + 2, j] = w[m, j]], If[RightEdge == "S", For[j = 1, j < n + 2, j++, w[m + 2, j] = -w[m, j]], "Invalid Input Data!"]] w[0, 0] = w[2, 2]; w[0, n + 2] = w[2, n]; w[m + 2, 0] = w[m, 2]; w[m + 2, n + 2] = w[n, m];"

``


 

Download for.mw

 

Error, (in eval/diff) invalid input: diff received...

Asked by: 9009134 110
diff
February 04 2017
0  7

hi .in substuting in ode equation i encounter with error

Error, (in eval/diff) invalid input: diff received (f1[i+1, i]-2*f1[i, i]+f1[i-1, i])/h^2, which is not valid for its 2nd argument

please help me

thanksh_2.5_eq4.mw
 

 

restart; with(DEtools); with(plots); interface(rtablesize = 25); ode1 := -P1*(diff(f1(x, y), x, x, x, x, x, x)+diff(f1(x, y), y, y, y, y, y, y)+3*(diff(f1(x, y), x, x, x, x, y, y))+3*(diff(f1(x, y), x, x, y, y, y, y)))+P2*(diff(f1(x, y), x, x, x, x)+diff(f1(x, y), y, y, y, y)+2*(diff(f1(x, y), x, x, y, y)))-N_x*(diff(f1(x, y), x, x))-N_y*(diff(f1(x, y), y, y)); F1xx := i, proc (j) options operator, arrow; (f1[i+1, j]-2*f1[i, j]+f1[i-1, j])/h^2 end proc; F1yy := i, proc (j) options operator, arrow; (f1[i, j+1]-2*f1[i, j]+f1[i, j-1])/hy^2 end proc; F1xxxx := i, proc (j) options operator, arrow; (f1[i+2, j]-4*f1[i+1, j]+6*f1[i, j]-4*f1[i-1, j]+f1[i-2, j])/h^4 end proc; F1yyyy := i, proc (j) options operator, arrow; (f1[i, j+2]-4*f1[i, j+1]+6*f1[i, j]-4*f1[i, j-1]+f1[i, j-2])/hy^4 end proc; F1xxxxxx := i, proc (j) options operator, arrow; (f1[i+3, j]-6*f1[i+2, j]+15*f1[i+1, j]-20*f1[i, j]+15*f1[i-1, j]-6*f1[i-2, j]+f1[i-3, j])/h^6 end proc; F1yyyyyy := i, proc (j) options operator, arrow; (f1[i, j+3]-6*f1[i, j+2]+15*f1[i, j+1]-20*f1[i, j]+15*f1[i, j-1]-6*f1[i, j-2]+f1[i, j-3])/hy^6 end proc; F1xxyyyy := i, proc (j) options operator, arrow; (f1[i-1, j-2]-4*f1[i-1, j-1]+6*f1[i-1, j]-4*f1[i-1, j+1]+f1[i-1, j+2]-2*f1[i, j-2]+8*f1[i, j-1]-12*f1[i, j]+8*f1[i, j+1]-2*f1[i, j+2]+f1[i+1, j-2]-4*f1[i+1, j-1]+6*f1[i+1, j]-4*f1[i+1, j+1]+f1[i+1, j+2])/(hy^4*h^2) end proc; F1yyxxxx := i, proc (j) options operator, arrow; (f1[i-2, j-1]-2*f1[i-2, j]+f1[i-2, j+1]-4*f1[i-1, j-1]+8*f1[i-1, j]-4*f1[i-1, j+1]+6*f1[i, j-1]-12*f1[i, j]+6*f1[i, j+1]-4*f1[i+1, j-1]+8*f1[i+1, j]-4*f1[i+1, j+1]+f1[i+2, j-1]-2*f1[i+2, j]+f1[i+2, j+1])/(h^4*hy^2) end proc; eq := simplify(eval(ode1, {diff(f1(x, y), x, x) = F1xx(i, j), diff(f1(x, y), y, y) = F1yy(i, j), diff(f1(x, y), x, x, x, x) = F1xxxx(i, j), diff(f1(x, y), y, y, y, y) = F1yyyy(i, j), diff(f1(x, y), x, x, x, x, x, x) = F1xxxxxx(i, j), diff(f1(x, y), x, x, x, x, y, y) = F1yyxxxx(i, j), diff(f1(x, y), x, x, y, y, y, y) = F1xxyyyy(i, j), diff(f1(x, y), y, y, y, y, y, y) = F1yyyyyy(i, j)}))

Error, (in eval/diff) invalid input: diff received (f1[i+1, i]-2*f1[i, i]+f1[i-1, i])/h^2, which is not valid for its 2nd argument

  

NULL

 

expand(%)

i

 (1)

simplify(4*h^4*f3[i]*f4[i]*%)

4*h^4*f3[i]*f4[i]*i

 (2)

diff(f1(x, y), x, x, y, y, y, y)

diff(diff(diff(diff(diff(diff(f1(x, y), x), x), y), y), y), y)

 (3)

``

``

NULL


 

Download h_2.5_eq4.mw

 

nonlinear fit gives the right fit, but wrong param...

Asked by: shesia 20
parameters
February 03 2017
1  4

hello im currently working on a project and im fitting some non-linear data with the follwing model:

model:= 1.*10^5*exp(-t*k-*t/B)

where B and k are the unkown parameters.

i have the following data:

X=<0,2,4,6,8,10>

Y := <100000, 86089.76983, 74114.4849, 63804.98946, 54929.56828>

if i do the fit like this: fit(model,X,Y,t) i get a fit that looks like this:

100000*exp(-0.520664970792415e-1*t) which i alright. however when i try to get the parameters i get something like this

fit(model,X,Y,t,output=[parametervalues])

[B = .999563650781966, k = -.948370042622550] - when i define k=0.05 however i get [B = 483.910474528817], which is the right parameter.

insereting the two different sets yields:

1) k=0.05, B = 483.910474528817 -> 100000*exp(-0.520664970792415e-1*t) (good aprox to the fit)

2) B = .999563650781966 and k = -.948370042622550 -> 100000*exp(-0.5206649794e-1*S) (way off)

how is this possible anyone able to help, been sitting with this for days now?

 

 

Maple 2016 not starting...

Asked by: FadiBunni 10
February 02 2017
2  4

Hallo,
I got problem with starting maple 2016, when I click on the app files, it thinks for a second then nothing happens, I have tried to uninstall and install again, but no defference. I am not getting any error at any point, that is why it is hard to fix. maybe it has to do with java, jre or PATH?

Thanks for your help.  

Corrupt Maple document (I know that this exact pro...

Asked by: andreasamdisen 10
worksheet corruption
February 02 2017
2  8

https://www.dropbox.com/s/zpj7kudgn3gikfa/INS%20-%20Bygninger%20energibehov.mw?dl=0

https://www.dropbox.com/s/vj0t0p3r9stoy3c/INS%20-%20F%C3%B8ringsveje%20og%20indeklima.mw?dl=0

"There were problems during the loading process. Your worksheet may be incomplete."

I have seen threads where this has been solved, but i do not know how to do it.

It happened to both files, after restarting my computer.

Are anyone willing to help me?

complex tensor expression with Pauli matrices...

Asked by: illuminates 65
physics tensor
February 02 2017
0  0

I attempt to understand is it possible whether to calculate the next expression by means of mathematica:

where

{,}- anti-communicator;

 a=0,1,2,3;

\tau^{0}-unity matrix; \tau^{i} - Pauli matrix;

and:
 

 

 


 
finally - Levi-Civita symbol; -Hermitian conjugation.

 

Thank you for your kind replies .

How to obtain accurate rotation matrices?...

Asked by: Lhunatic 15
tensor rotation
February 01 2017
0  4

Hey guys,

I'm trying to build up some program to manage my composites data. But I am struggling with my compliance/stiffness in the global coordinates:

-Basically, I have the lamina's properties in local coordinates.

-When I make walls out of them with 30degress fibers orientation, I need to rotate the local stiffness several times to get the the stiffness of that particular wall.

-While I do understand the concept and manage to get the final rotation matrix correctly, I often find myself making mistakes regarding the sense of rotation of my local axis relatively to the global one.

I try to stick with one direction of rotation but if Maple has a smart way whereas I can plug in the initial configuration of the local coords relatively to the global one, show the final configuration (local aligned to the global), and get the rotation matrix that made it happen, it would be more helpful.

Thank you

Update:

I enclosed an example of the kind of operations I do:

And here is the kind of code I'm using:

PB2_W1.mw
 

NULL

> 

restart:
> 

with(LinearAlgebra):
> 

Stiffness:=Matrix(6,6): Stiffness:=Matrix(6, 6, {(1, 1) = 20.4, (1, 2) = .537, (1, 3) = 1.01, (1, 4) = 0., (1, 5) = 0., (1, 6) = -0., (2, 1) = .537, (2, 2) = 1.59, (2, 3) = .73, (2, 4) = 0., (2, 5) = 0., (2, 6) = -0., (3, 1) = 1.01, (3, 2) = .73, (3, 3) = 2.86, (3, 4) = 0., (3, 5) = 0., (3, 6) = -0., (4, 1) = 0., (4, 2) = 0., (4, 3) = 0., (4, 4) = 1.5, (4, 5) = 0., (4, 6) = -0., (5, 1) = 0., (5, 2) = 0., (5, 3) = 0., (5, 4) = 0., (5, 5) = 2., (5, 6) = -0., (6, 1) = 0., (6, 2) = 0., (6, 3) = 0., (6, 4) = 0., (6, 5) = 0., (6, 6) = .8});

Stiffness := Matrix(6, 6, {(1, 1) = 20.4, (1, 2) = .537, (1, 3) = 1.01, (1, 4) = 0., (1, 5) = 0., (1, 6) = -0., (2, 1) = .537, (2, 2) = 1.59, (2, 3) = .73, (2, 4) = 0., (2, 5) = 0., (2, 6) = -0., (3, 1) = 1.01, (3, 2) = .73, (3, 3) = 2.86, (3, 4) = 0., (3, 5) = 0., (3, 6) = -0., (4, 1) = 0., (4, 2) = 0., (4, 3) = 0., (4, 4) = 1.5, (4, 5) = 0., (4, 6) = -0., (5, 1) = 0., (5, 2) = 0., (5, 3) = 0., (5, 4) = 0., (5, 5) = 2., (5, 6) = -0., (6, 1) = 0., (6, 2) = 0., (6, 3) = 0., (6, 4) = 0., (6, 5) = 0., (6, 6) = .8})

 (1)
> 

Q1:=Matrix(3,3): Q1[1,1]:=sin(Pi/4); Q1[1,2]:=0; Q1[1,3]:=cos(Pi/4); Q1[2,1]:=cos(Pi/4); Q1[2,2]:=0; Q1[2,3]:=-sin(Pi/4); Q1[3,1]:=0; Q1[3,2]:=1; Q1[3,3]:=0;

(1/2)*2^(1/2)

  

0

  

(1/2)*2^(1/2)

  

(1/2)*2^(1/2)

  

0

  

-(1/2)*2^(1/2)

  

0

  

1

  

0

 (2)
> 

Q1;

Matrix(3, 3, {(1, 1) = (1/2)*sqrt(2), (1, 2) = 0, (1, 3) = (1/2)*sqrt(2), (2, 1) = (1/2)*sqrt(2), (2, 2) = 0, (2, 3) = -(1/2)*sqrt(2), (3, 1) = 0, (3, 2) = 1, (3, 3) = 0})

 (3)
> 

Q2:=Matrix(3,3): Q2[1,1]:=0; Q2[1,2]:=0; Q2[1,3]:=1; Q2[2,1]:=1; Q2[2,2]:=0; Q2[2,3]:=0; Q2[3,1]:=0; Q2[3,2]:=1; Q2[3,3]:=0;

0

  

0

  

1

  

1

  

0

  

0

  

0

  

1

  

0

 (4)
> 

Q2;

Matrix(3, 3, {(1, 1) = 0, (1, 2) = 0, (1, 3) = 1, (2, 1) = 1, (2, 2) = 0, (2, 3) = 0, (3, 1) = 0, (3, 2) = 1, (3, 3) = 0})

 (5)
> 

Q3:=Matrix(3,3): Q3[1,1]:=0; Q3[1,2]:=-1; Q3[1,3]:=0; Q3[2,1]:=1; Q3[2,2]:=0; Q3[2,3]:=0; Q3[3,1]:=0; Q3[3,2]:=0; Q3[3,3]:=1;

0

  

-1

  

0

  

1

  

0

  

0

  

0

  

0

  

1

 (6)
> 

Q3;

Matrix(3, 3, {(1, 1) = 0, (1, 2) = -1, (1, 3) = 0, (2, 1) = 1, (2, 2) = 0, (2, 3) = 0, (3, 1) = 0, (3, 2) = 0, (3, 3) = 1})

 (7)
> 

S1:=Transpose(Q1); S2:=Transpose(Q2); S3:=Transpose(Q3);

S1 := Matrix(3, 3, {(1, 1) = (1/2)*sqrt(2), (1, 2) = (1/2)*sqrt(2), (1, 3) = 0, (2, 1) = 0, (2, 2) = 0, (2, 3) = 1, (3, 1) = (1/2)*sqrt(2), (3, 2) = -(1/2)*sqrt(2), (3, 3) = 0})

  

S2 := Matrix(3, 3, {(1, 1) = 0, (1, 2) = 1, (1, 3) = 0, (2, 1) = 0, (2, 2) = 0, (2, 3) = 1, (3, 1) = 1, (3, 2) = 0, (3, 3) = 0})

  

S3 := Matrix(3, 3, {(1, 1) = 0, (1, 2) = 1, (1, 3) = 0, (2, 1) = -1, (2, 2) = 0, (2, 3) = 0, (3, 1) = 0, (3, 2) = 0, (3, 3) = 1})

 (8)
> 

S4:=Multiply(S3,S2);

S4 := Matrix(3, 3, {(1, 1) = 0, (1, 2) = 0, (1, 3) = 1, (2, 1) = 0, (2, 2) = -1, (2, 3) = 0, (3, 1) = 1, (3, 2) = 0, (3, 3) = 0})

 (9)
> 

S5:=Multiply(S4,S1);

S5 := Matrix(3, 3, {(1, 1) = (1/2)*sqrt(2), (1, 2) = -(1/2)*sqrt(2), (1, 3) = 0, (2, 1) = 0, (2, 2) = 0, (2, 3) = -1, (3, 1) = (1/2)*sqrt(2), (3, 2) = (1/2)*sqrt(2), (3, 3) = 0})

 (10)
> 

R:=Matrix(6,6): R[1,1]:=S5[1,1]^2; R[1,2]:=S5[1,2]^2; R[1,3]:=S5[1,3]^2; R[2,1]:=S5[2,1]*S5[1,1]; R[2,2]:=S5[2,2]*S5[1,2]; R[2,3]:=S5[2,3]*S5[1,3]; R[3,1]:=S5[2,1]^2; R[3,2]:=S5[2,2]^2; R[3,3]:=S5[2,3]^2; R[1,4]:=2*S5[1,2]*S5[1,3]; R[1,5]:=2*S5[1,1]*S5[1,3]; R[1,6]:=2*S5[1,1]*S5[1,2]; R[2,4]:=S5[2,2]*S5[1,3]+S5[2,3]*S5[1,2]; R[2,5]:=S5[2,1]*S5[1,3]+S5[2,3]*S5[1,1]; R[2,6]:=S5[2,1]*S5[1,2]+S5[2,2]*S5[1,1]; R[3,4]:=2*S5[2,2]*S5[2,3]; R[3,5]:=2*S5[2,1]*S5[2,3]; R[3,6]:=2*S5[2,1]*S5[2,2];
> 

R[4,1]:=S5[3,1]*S5[1,1]; R[4,2]:=S5[3,2]*S5[1,2]; R[4,3]:=S5[3,3]*S5[1,3]; R[4,4]:=S5[3,2]*S5[1,3]+S5[3,3]*S5[1,2]; R[4,5]:=S5[3,1]*S5[1,3]+S5[3,3]*S5[1,1]; R[4,6]:=S5[3,1]*S5[1,2]+S5[3,2]*S5[1,1]; R[5,1]:=S5[3,1]*S5[2,1]; R[5,2]:=S5[3,2]*S5[2,2]; R[5,3]:=S5[3,3]*S5[2,3]; R[5,4]:=S5[3,2]*S5[2,3]+S5[3,3]*S5[2,2]; R[5,5]:=S5[3,1]*S5[2,3]+S5[3,3]*S5[2,1]; R[5,6]:=S5[3,1]*S5[2,2]+S5[3,2]*S5[2,1];R[6,1]:=S5[3,1]^2; R[6,2]:=S5[3,2]^2; R[6,3]:=S5[3,3]^2; R[6,4]:=2*S5[3,3]*S5[3,2]; R[6,5]:=2*S5[3,1]*S5[3,3]; R[6,6]:=2*S5[3,1]*S5[3,2];

1/2

  

1/2

  

0

  

0

  

0

  

0

  

0

  

0

  

1

  

0

  

0

  

-1

  

(1/2)*2^(1/2)

  

-(1/2)*2^(1/2)

  

0

  

0

  

0

  

0

  

1/2

  

-1/2

  

0

  

0

  

0

  

0

  

0

  

0

  

0

  

-(1/2)*2^(1/2)

  

-(1/2)*2^(1/2)

  

0

  

1/2

  

1/2

  

0

  

0

  

0

  

1

 (11)
> 

print(R);

Matrix(6, 6, {(1, 1) = 1/2, (1, 2) = 1/2, (1, 3) = 0, (1, 4) = 0, (1, 5) = 0, (1, 6) = -1, (2, 1) = 0, (2, 2) = 0, (2, 3) = 0, (2, 4) = (1/2)*sqrt(2), (2, 5) = -(1/2)*sqrt(2), (2, 6) = 0, (3, 1) = 0, (3, 2) = 0, (3, 3) = 1, (3, 4) = 0, (3, 5) = 0, (3, 6) = 0, (4, 1) = 1/2, (4, 2) = -1/2, (4, 3) = 0, (4, 4) = 0, (4, 5) = 0, (4, 6) = 0, (5, 1) = 0, (5, 2) = 0, (5, 3) = 0, (5, 4) = -(1/2)*sqrt(2), (5, 5) = -(1/2)*sqrt(2), (5, 6) = 0, (6, 1) = 1/2, (6, 2) = 1/2, (6, 3) = 0, (6, 4) = 0, (6, 5) = 0, (6, 6) = 1})

 (12)
> 

RTrans:=Transpose(R);

RTrans := Matrix(6, 6, {(1, 1) = 1/2, (1, 2) = 0, (1, 3) = 0, (1, 4) = 1/2, (1, 5) = 0, (1, 6) = 1/2, (2, 1) = 1/2, (2, 2) = 0, (2, 3) = 0, (2, 4) = -1/2, (2, 5) = 0, (2, 6) = 1/2, (3, 1) = 0, (3, 2) = 0, (3, 3) = 1, (3, 4) = 0, (3, 5) = 0, (3, 6) = 0, (4, 1) = 0, (4, 2) = (1/2)*sqrt(2), (4, 3) = 0, (4, 4) = 0, (4, 5) = -(1/2)*sqrt(2), (4, 6) = 0, (5, 1) = 0, (5, 2) = -(1/2)*sqrt(2), (5, 3) = 0, (5, 4) = 0, (5, 5) = -(1/2)*sqrt(2), (5, 6) = 0, (6, 1) = -1, (6, 2) = 0, (6, 3) = 0, (6, 4) = 0, (6, 5) = 0, (6, 6) = 1})

 (13)
> 

Stiff1:=Matrix(6,6): Stiff1:=Multiply(Stiffness, RTrans);

Stiff1 := Matrix(6, 6, {(1, 1) = 10.46850000, (1, 2) = 0., (1, 3) = 1.01, (1, 4) = 9.931500000, (1, 5) = 0., (1, 6) = 10.46850000, (2, 1) = 1.063500000, (2, 2) = 0., (2, 3) = .73, (2, 4) = -.5265000000, (2, 5) = 0., (2, 6) = 1.063500000, (3, 1) = .8700000000, (3, 2) = 0., (3, 3) = 2.86, (3, 4) = .1400000000, (3, 5) = 0., (3, 6) = .8700000000, (4, 1) = 0., (4, 2) = .7500000000*sqrt(2), (4, 3) = 0., (4, 4) = 0., (4, 5) = -.7500000000*sqrt(2), (4, 6) = 0., (5, 1) = 0., (5, 2) = -1.000000000*sqrt(2), (5, 3) = 0., (5, 4) = 0., (5, 5) = -1.000000000*sqrt(2), (5, 6) = 0., (6, 1) = -.8, (6, 2) = 0., (6, 3) = 0., (6, 4) = 0., (6, 5) = 0., (6, 6) = .8})

 (14)
> 

StiffnessW1:=Matrix(6,6): StiffnessW1:=Multiply(R,Stiff1); evalf(StiffnessW1,3);

StiffnessW1 := Matrix(6, 6, {(1, 1) = 6.566000000, (1, 2) = 0., (1, 3) = .8700000000, (1, 4) = 4.702500000, (1, 5) = 0., (1, 6) = 4.966000000, (2, 1) = 0., (2, 2) = 1.750000000, (2, 3) = 0., (2, 4) = 0., (2, 5) = .2500000000, (2, 6) = 0., (3, 1) = .8700000000, (3, 2) = 0., (3, 3) = 2.86, (3, 4) = .1400000000, (3, 5) = 0., (3, 6) = .8700000000, (4, 1) = 4.702500000, (4, 2) = 0., (4, 3) = .1400000000, (4, 4) = 5.229000000, (4, 5) = 0., (4, 6) = 4.702500000, (5, 1) = 0., (5, 2) = .2500000000, (5, 3) = 0., (5, 4) = 0., (5, 5) = 1.750000000, (5, 6) = 0., (6, 1) = 4.966000000, (6, 2) = 0., (6, 3) = .8700000000, (6, 4) = 4.702500000, (6, 5) = 0., (6, 6) = 6.566000000})

  

Matrix(6, 6, {(1, 1) = 6.57, (1, 2) = 0., (1, 3) = .870, (1, 4) = 4.70, (1, 5) = 0., (1, 6) = 4.97, (2, 1) = 0., (2, 2) = 1.75, (2, 3) = 0., (2, 4) = 0., (2, 5) = .250, (2, 6) = 0., (3, 1) = .870, (3, 2) = 0., (3, 3) = 2.86, (3, 4) = .140, (3, 5) = 0., (3, 6) = .870, (4, 1) = 4.70, (4, 2) = 0., (4, 3) = .140, (4, 4) = 5.23, (4, 5) = 0., (4, 6) = 4.70, (5, 1) = 0., (5, 2) = .250, (5, 3) = 0., (5, 4) = 0., (5, 5) = 1.75, (5, 6) = 0., (6, 1) = 4.97, (6, 2) = 0., (6, 3) = .870, (6, 4) = 4.70, (6, 5) = 0., (6, 6) = 6.57})

 (15)
> 

 

 

NULL


 

Download PB2_W1.mw

It is decent enough to get results if human mistakes don't happen when it comes to rotation orientation (which tends to happen more often than not). 

I am aware though that it is not written with wits or in an efficient format. If you have a suggestion, Im all ears.

 

Thanks again

 

 

Scientific output...

Asked by: amelscape 5
numeric
January 31 2017
1  0

Is there a way to change the numeric formatting of 'Scientific' to use a cdot instead of a cross to represent multiplication?

How do I integrate a large set of datapoints....

Asked by: Qwinzzi 10
plot integration
January 31 2017
2  23

Hello! 

I got a set of data imported from excel which is of the size 2001x2. I've use DataPlot to plot the graph of this data but I can't seem to find a way to integrate it. I've used BSplineCurve to make the discreate values continious but I cant seem to integrate this new curve. Can someone please give me a solution or an alternative way to find an approximative way to find the area under the curve.

Thanks

animating a cylinder bounded by a sphere...

Asked by: brian bovril 914
animate
January 30 2017
0  6

Guys

I can't seem to work out how the cylinder in my animation won't extend to of the bottom of the sphere initially. and how to make it stop at the maximum volume coordinates.

cylinder_in_sphere_ani.mw

 

 

How do I factor a vector out of a matrix...

Asked by: Lhunatic 15
matrix linearalgebra
January 29 2017
1  2

Hey guys,

I have this (6x1) matrix:

And I wish to factor a vector of the recurring terms out of it, this particular vector:

So that I end up with a (6x6) Matrix multiplied to that vector.

 

Thank you

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