Hi,

I obtain  curve pH = f(Vb) with following code but now, i would have tangent for two points near Veq. I don't know the procedure with implicitplot.

I think the best way is to attribute the points to a function but dn't know how to do

restart;with(plots);

 Vtot := V0+Vb+Vind;h := 10^(-ph);C0 := 10^(-2);Cind := .83;Vind := 0.1e-1;V0 := 10;Ka1 := 10^(-4.8);Ka2 := 10^(-9);Cb := 0.1e-1;Kaind := 10^(-8);

eq := h+Cb*Vb/Vtot = 10^(-14...

i have 6 non linear diff equation. for the quad copter i want to get its state space representation and its done in a master  but they didnot say how they did it ???

soo any one can help me?

Dear guys!

I have two expressions in terms of one variable. For example A(t) and B(t). Now, I want to plot A in terms of B. What should I do?

I cannot obtain this relation analytically because both expressions in terms of "t" are very complicated. But I can plot both of them. Now, I need to plot A in terms of B.

Thanks a lot.

> test1r := dsolve((Diff(f(x,y), t, t))*x+(Diff(f(x,y), t))*y = 0, f);

Error, (in dsolve) expected an ordinary differential equation. Received: 0 = 0

another question is

i do not know whether can 

 dsolve((Diff(f(x,y), (x,y), (x,y)))*x+(Diff(f(x,y), (x,y)))*y = 0, f);

Hello,

I want to report a strange behaviour when working with bras and kets from the physics package. Working in a discrete basis, Ket(Phi,m) and Ket(Phi,n) should be orthogonal as long as m neq n. At least this is said so in the Physics-Example document.

However when I enter Bra(Phi,0).Ket(Phi,4) Maple returns 1! Just with 4 - all other integer values n > 1 give zero, as it should be! Maybe I am completely misunderstanding something here or this result is...

I consider a PDE system (?pdsolve,numeric)

PDE := {diff(u(x,t),t)=-1/20*diff(v(x,t),x,x),
diff(v(x,t),t)=diff(u(x,t),x,x)}:

IBC := {u(x,0)=sin(Pi*x), u(0,t)=0, u(1,t)=0,
v(x,0)=1-x, v(0,t)=1, v(1,t)=0}:

pds := pdsolve(PDE, IBC, numeric, spacestep=1/50);

Suppose, I need to use the data diff(u(x,t),x,x)  or diff(v(x,t),x,x) at x=0.

Hi, i wouls lij=ke to see the consequences of damping on coupled oscillators.

I encounter no problem with

restart; m := 1; k1 := 1; k2 := 1; lambda := 0;

eq1 := m*diff(x1(t), `$`(t, 2)) = -k1*x1(t)+k2*(x2(t)-x1(t))-lambda*diff(x1(t), t);

eq2 := m*diff(x2(t), `$`(t, 2)) = -k2*(x2(t)-x1(t)); ICS := x1(0) = 1, x2(0) = 0, (D(x1))(0) = 0, (D(x2))(0) = 0; sol2 := dsolve({ICS, eq1, eq2}, {x1(t), x2(t)});

plot(eval(x2(t), sol2), t = 0 .. 20);

Hi,

Really, can't understand why there's a problem in the line desolve

restart;

eq1 := m*(diff(x1(t), t, t))-f = 0;

f := -k*x1(t)+k*(x2(t)-x1(t))-lambda*(diff(x1(t), t)) ;

g := -k*(x2(t)-x1(t)); eq2 := m*(diff(x2(t), t, t))-g = 0;

fcns := {x1(t), x2(t)};

ICS := {x1(0) = 1, x2(0) = 0, D(x1)(0) = 0, D(x2)(0) = 0};

sys := {eq1, eq2}; m := 1; k := 1; lambda := 1; sysdiff := sys union ICS;

Hi

1st, sorry, i did'nt find the "question" forum so i post here

2nd, difficulties in converting the maple code in text here

3rd : my problem of the day

retart :eq1 := m*(diff(x1(t), t, t))-f = 0; f := -k*x1(t)+k2*(x2(t)-x1(t))-lambda*(diff(x1(t), t));

eq2 := m*(diff(x1(t), t, t))-g = 0; g := -k2*(x2(t)-x1(t)); fcns := x1(t), x2(t);

ICS := {x1(0) = 1, x2(0) = 0, (D(x1))(0) = 0, (D(x2))(0) = 0};

sys := {eq1, eq2};...

I want to print     a_n   is  in  S .

Here are what I tried.

So here is what I need to do within Maple.  I have to define a piecewise function and then determine left and right hand derivatives at a certain x value.  Then determine the whole derivative and graph both parts.  I am just pretty new to Maple so it is still fairly confusing and I cannot determine the exact commands that I need.

hi,look at that. I obtain a curve. But when i do it again

I have a second order ODE, eq, that depends on a paramter p. Certain events take place when solving the ODE and I would like to study those events as a function of p. Here is a toy version of the command that yeilds the information I need.

>dsolve({eq, f(1)=1,D(f)(1)=0},f(t), numeric, events=[  [ [f(t)-Pi,t>0],halt   ]  ,

 [  [f(t) =-1, t>0],halt]  ])(15);

When f hits  -1 or Pi the solution stops and gives...

Hello,

I've got a recurrence equation system like:

fn:={f(x)=sum(f(k)*f(x-k-1),k=0..x-1),f(0)=1}

appearently

rsolve(fn,f(k))

doesn't work.

Is there a way to solve this with maple?

Actually I also would like to solve this step by step, by hand. Could you refer me to something that could help me, solve my problem?