Eq1 := 55200.0*(1+(3.20000000*10^7*a+1.200000*10^5*b+400*c+d)^2)^.5*(2.048000000*10^15*a+7.680000000*10^12*b+2.560000000*10^10*c+6.40000000*10^7*d)/((3.20000000*10^7*a+1.200000*10^5*b+400*c+d)*(4.800000*10^5*a+1200*b+2*c))-1.177600000*10^12*(1+(3.20000000*10^7*a+1.200000*10^5*b+400*c+d)^2)^1.5/((3.20000000*10^7*a+1.200000*10^5*b+400*c+d)^2*(4.800000*10^5*a+1200*b+2*c))-1.766400000*10^10*(1+(3.20000000*10^7*a+1.200000*10^5*b+400*c+d)^2)^1.5/((3.20000000*10^7*a+1.200000*10^5*b+400*c+d)*(4.800000*10^5*a+1200*b+2*c)^2) = 0

 

EQ1 := 55200.0*(1+(3.20000000*10^7*a+1.200000*10^5*b+400*c+d)^2)^.5*(2.048000000*10^15*a+7.680000000*10^12*b+2.560000000*10^10*c+6.40000000*10^7*d)/((3.20000000*10^7*a+1.200000*10^5*b+400*c+d)*(4.800000*10^5*a+1200*b+2*c))-1.177600000*10^12*(1+(3.20000000*10^7*a+1.200000*10^5*b+400*c+d)^2)^1.5/((3.20000000*10^7*a+1.200000*10^5*b+400*c+d)^2*(4.800000*10^5*a+1200*b+2*c))-1.766400000*10^10*(1+(3.20000000*10^7*a+1.200000*10^5*b+400*c+d)^2)^1.5/((3.20000000*10^7*a+1.200000*10^5*b+400*c+d)*(4.800000*10^5*a+1200*b+2*c)^2) = 0;

I need to integrate an ODE : I use dsolve.

As there is not an exact solution, I use numeric integration :

F := y''(x) + a(x)*y'(x) + b(x)*y(x) ;

EDF := {F = 0, y(t0) = y0, y'(t0) = dy0};

Snum := dsolve(EDF, y(x), type = numeric);

S  := x --> rhs(Snum(x)[2]) ;

I can now plot the graph of the solution S.

But suppose I need also the graph of the derivative S'.
As this function is solution of Y' + a*Y + b*S = 0,
I code

I have a large number of lists labelled L1, L2, L3 ...etc.

I want to determine the number of elements in each list.  If I had labelled my lists L(1), L(2), L(3) ... I would easily have been able to pull out the number of elements with sequence

seq(nops(L(i)),i=1..3);

nops doesn't allow multiple arguments.  Is there any way I can use seq on the lists L1, L2, L3, ... etc  In other words, how can I have a two letter variable and get maple to vary the 2nd variable?

hi, i have a set of roots, say [a,b,c,d]. how do i make them so that maple will give me the roots like this:  {m=a},{m=b},{m=c},{m=d} ?

 

thanks

I have already plotted the intersection of 5 surfaces but need to plot their intersections, is this possible and if so how? Cheers

What is the correct syntax for: 
java_args= - D entity ExpansionLimit = 1000000?
I get the following error:
Invalid option in launch.ini

I follow the instructions given in:

"There were problems during the loading process.
 Your worksheet may be incomplete."

http://www.maplesoft.com/support/help/view.aspx?sid=26039

Gracias

Dear All,

i am first time using maple for my cryptographic scheme i recently developed. I am wondering if there is any builtin package or library for AES Encryption/Decryption and SHA256 in MAPLE 11.

the "StringTools" can provide md5 hash of the message but i need SHA256 implementation and AES 256 bit encryption/decryption module in Maple.

any suggestions?

 

I was wondering if there is a way to compute the discriminant of a rank r quadratic form in maple? Alternatively, is there a way to diagonalize, via symmetric row and col operations, a symmetric matrix A over Z_p? For instance, modifying RowReduce in LinearAlgebra[Modular]. If I can do this then I can obtain the discriminant. Example: >with(LinearAlgebra[Modular]): >p:=5; >Matrix(4,4,[[0, 1, 1, 4], [1, 0, 1, 0], [1, 1, 0, 1], [4, 0, 1, 0]]); >RowReduce(p,A,4,4,0,0,0,0,0,0,0); # would like a symmetric row and column reduction

Hello.I could use some help to solve the folowing system, please.

Basically I have the 4 unknowns (A,P,C2,alfa)and I want to know their values by changing values to "a2" (eg. varying a2 from [0;80]).

With another software I solved matricially the EQ2;EQ3 and EQ4 for P,A and C2 with different values of a2 and then I replaced the P,C2 solutions (for each a2 value) on the EQ1 and tooked the value of "alfa" for each corresponding "a2". At the final I had the 4 unknows solved varying the "a2" value.

Can I get a box plot on an x-y-z graph?

How do you do this?; actually, for starters, how do you display 2 plots side by side?

Hi

I have a problem with an assumed real variable that are not inserted into equations if it is given an nummeric value. I have tried to make and example below:

> restart;
> with(plottools);
> with(linalg);
>with(plots);
> assume(theta, real);

>A := e^(I*theta)

hi, suppose

integers:=[`$`(-10..10)]; selectremove(`<`,integers,0);

so this separates +ve and -ve. But, if the range of values are complex, how do we separate them based on the +ve and -ve of the real part of the complex number? i.e I want to separate all a +- bi from all -a +- bi.

 

thanks

Hello,

My equation is the following:

Y = 1 - ( sin (2*theta)/ (X+cos(2*theta)))^2

where theta=20 degrees = pi/9  and X= 0..30. How can I numerically calculate Y as a function of X.  And also how can I plot Y(X),

Y(1/X)  and  Y(1/X^2). I like to do these for different theta values (i.e., theta=2*pi/9,  theta= 3*pi/9,,,,,, theta=4*pi/9 ).

Thank you in anvance

Bengu