Hello,

I am looking for an explanation for the following behavior :

> f := proc(x) somefunc(x) end proc:

> a := table([variable=z]):

> f(a);

somefunc(a)

> f(a) assuming z::real;

somefunc(table([variable=z]))

Why is 'a' replaced with its corresponding table in the second case? And is it possible to use the name 'a' in the return value?

-- Thanks for any reply,

Franky.

Hello!

I´m Trying to do numerical integration for a function defined by a product of characteristic functions. I either receive the message " Error, (in unknown) too many levels of recursion " or "error, (in evalf/int) unable to handle singularity". What should I do?

f_1:=(x,y,z,w)->piecewise(x+w > 0 , 1);

f_2:=(x,y,z,w)->piecewise(x*w - y*z > 0,1);

f_3:=(x,y,z,w)->piecewise((x+w)^2 - 4*(x*w - y*z)<0,1);

prod:=(x,y,z,w)->f_1(x,y,z,w)*f_2(x,y,z,w)*f_3(x,y,z,w);

I want to integrate prod, with all four variables ranging from -1 to 1.

Thank you, Bernardo

Hi, I am trying to call a Matlab function from Maple. The Matlab function requires 33 input variables, but when I call this function with this many variables I get the following error message:
"Error, (in ExecuteCommand) Matlab command string is too long"
My objective is to maximize this function using GlobalSOlve but first I want to just call it. I would appreciate if someone can help me with this.
Cheers
Saqib

Hi!
I have a two part question:
I am plotting a matrix as multiple graphs: column1 v column2, column1 v column3 etc
I have a worksheet set up so that some of the graphs can be completely equal to 0. I am plotting all the graphs on the one set of axes for comparison, and so the null graphs don't appear. However, I am having problems getting a legend. I only want to display a coloured legend (each plot is a different colour) for each graph that is non zero. How can I do this?
Second part, I have created a text box next to the graph that displays the names of the non zero graphs as strings. Can I make these strings the same colour as their respective graphs?

Hi everyone!
I would like to create a worksheet witb multiple worksheets, and I would like to use sections and subsections. Can anyone please tell me how to lock certain sections/subsections closed so users cannot open then?
Thanks :)

Hi dear members of this Forum,

I want to generate a list which depend on "n";

for n=2 I would like to generate the following list

>[[p1>q1, p2>q2],

>[p1>q1, p2<q2],

>[p1<q1, p2>q2],

>[p1<q1, p2<q2]]

for n = 3 I would like to generate the list:

>[ [p1+p2>q1, p1+p3>q2, p2+p3>q3],

[p1+p2>q1, p1+p3>q2, p2+p3<q3],

[p1+p2>q1, p1+p3<q2, p2+p3>q3],

[p1+p2>q1, p1+p3<q2, p2+p3<q3],

[p1+p2<q1, p1+p3>q2, p2+p3>q3],

[p1+p2<q1, p1+p3>q2, p2+p3<q3],

[p1+p2<q1, p1+p3<q2, p2+p3>q3],

[p1+p2<q1, p1+p3<q2, p2+p3<q3]]

for n=4

[ [p1+p2+p3>q1, p1+p2+p4>q2, p1+p3+p4>q3, p2+p3+p4>q4],..

is it possible to implement a package so that the documentation and the help files will be automatically extracted from the sources?

As a newbie to maple, I was wondering how do I find the maximum of a equation under contraint. i can find some but for this one I can't ... and it's getting to me
f=1000*x+7500*y
under constraint:
g=10000000-(20000*x^0.8)*y^1.2
and for
f=(20000*x^0.8)*y^1.2
under constraint:
g=125000-1000*x-7500*y
Who do I find the maximum using MAple 10 !!!????

We have an automated grading system and sometimes students assign values to variables that are useful in grading their assignments. In order to get around this I've been tinkering with the anames() command (specifically, anames(user)), but I cannot seem to get a usable list of "in use" variable names: Every time I try to get Maple to use the list that anames(user) returns, I get the evaluated variable and not the variable name.
Example:
>a:=4;
>anames(user)[1];
4
Does anyone know how I can get a usable list of variable names that have been assigned values?

Hi,
I would like to be able to plot a 3d surface of one variable, with another variable in colour on that surface. This plot should have a legend for the colour variable.
At a stretch, I would also like to have all of this in polar co-ordinates, with polar axes and without having to write a transform myself.
Is all this possible!
cheers

Hi,
I am using the global optimization toolbox to minimize a matlab function as follows:
restart;
> (Matlab:-evalM)("cd 'C:/Documents and Settings/user/Maple'");
> mat2map1 := proc(a, b)
local Res,res;
Matlab:-setvar(\"a\",a);
Matlab:-setvar(\"b\",b);
Matlab:-evalM(\"result = mat2map1(a,b)\");
Res:=Matlab:-getvar(\"result\");
res:=convert(Res,float);
return res;
end proc;
> with(GlobalOptimization):
> infolevel[GlobalOptimization] := 3:
> GlobalSolve(mat2map1, a = 0 .. 5, b = 0 .. 5);
When I run this I get the following error message:

I have two small questions: 1. Given a list L: L:=[false, false, true, true, FAIL,false]; and I want to get the positions of "FAIL" (in this case 5) and false (1,2,6). HOW could I get that? 2. Now, given another list Z with the same number of elements: Z:=[z1,z2,z3,z4,z5,z6]; I would like to replace the values of FAIL by 0 (zero). (in the way that Z became: Z:=[z1,z2,z3,z4,0,z6];) It is possible to do that without using "for do" commands? Thanks in advance, JJacques

Hi dear Maple's gurus.
I have the lists a and b:
a:=[A, B, C]
b:= [[K1,L1][K2,L2][K3,L3]]
I want to add the each term of "a" in the intervals given in "b":
sum(A from L1 to K1)+ ..+sum(C from L3 to K3).
I tried with this procedure:
> sums:= proc(a,b)
local j,tot;
tot:=0;
for j from 1 to nops(a) do
tot:=tot+sum(a[j], k=b[j,2]..b[j,1]);
end do:
end proc:
>sums([a1,a2,a3],[[ku1,kl1],[ku2,kl2],[ku3,kl3]]);
1. Is there some more efficient way to do the same?
2. I would like also that the sums on a[j] under the following 2 join conditions:
2.1. assuming that a[j] is real and positive, and

Simple question: I can't seem to use a negative number as a minimum value for a slider control (in Maplet Builder)...
Is this not possible?
Thanks!
Bryan

Create new document (or worksheet) with content below and execute it step by step: ** > restart;** ** > Eval(diff(v(z),z),z=H)==eval(diff(v(z),z),z=H);** Eval(diff(v(z),z),z=H)=diff(v(H),H) ** > v:=z->z*H;** v:=z->z*H ** > value((1));** H=2H As you can see, result of eval, which in this case is equivalent to subs(z=H,diff(v(z),z)), at the right side of first equation leads to wrong final result :( This...