Maple Questions and Posts

These are Posts and Questions associated with the product, Maple

Hi, I am currently creating a procedure so that i can input two matrices and a vector and multiply them together in different patterns, I want the result to be either one of the vectors {4,0,0,0} or {0,4,0,0} or {0,0,4,0} or {0,0,0,4}, I am trying to create an if loop that says is one of the S's is equal to one of these print ("Synchronising"), I have decalred these vectors inside the procedure and all the S's but my if statement is still not working. I think S needs to be decalred more clearly inside but i'm unsure what to do, any help would be much appreciaited! Here is my procedure:

 

proc_cerny1:=proc(A::Matrix,B::Matrix,C::Vector)
local s, s1, s2, s3, s4, s5, s6, s7, s8, s9, s10, s11, s12, s13, s14, e, f, g, h;
s:=C.A;
s1:=C.B;
s2:=C.A.B;
s3:=C.B.A;
s4:=C.A.A;
s5:=C.B.B;
s6:=C.A.A.A;
s7:=C.B.B.B;
s8:=C.A.B.B;
s9:=C.A.B.A;
s10:=C.B.B.A;
s11:=C.B.A.A;
s12:=C.A.A.B;
s12:=C.B.A.B;
s13:=C.B.A.A;
s14:=C.B.A.A.A;
e:=Vector([4,0,0,0],orientation=row);
f:=Vector([0,4,0,0],orientation=row);
g:=Vector([0,0,4,0],orientation=row);
h:=Vector([0,0,0,4],orientation=row);
g:=Vector([0,0,4,0],orientation=row);
if (s7 = e)then
print("Synchronising")
elif (s7 = g) then
print ("Synchronising")
elif (s7 = h) then
print ("Synchronising")
elif (s7 = g) then
print("Synchronising")
else
print("Not Synchronising");
end if;

return s, s1, s2, s3, s4, s5, s6, s7, s8, s9, s10, s11, s12, s13, s14;
end proc:

 

Thanks 

Dears 

I want to sum some series by Maple and plotting. The problem is the sum of series are known like

serer.pdf

the problem is the difference between two graphs at the intersection x-axis and y-axis.

Is there any solution for this problem.

Amr

I am trying to work with a for do loop with a while component. I have the error but I am not sure what the desired error should be. I know it has to be small but how small?

 

Thanks

I have noticed that Maple's command isolve doesn't always seem to work for me. An example would be solving

x^2 + y^2 +z^2 =3 over the integers. Maple does not return any solutions.

I have found that isolve work for two variables, so I have just been iterating the third variable and applying isolve. However what if I want to solve  something with negative coefficients like : x^2 +y^2 +2*z^2 +x*y -y*z, then I have to be careful about which variable I iterate and the bounds are not always obvious.

Is there an easy fix to solve a homogeneous degree 2 polynomial in three variables over the integers ? Thanks!

Please have a visit of this qestion `http://math.stackexchange.com/q/574843/8581`. I did a very elementary attempt there for example for a function:

 > with(plots):
      h := x->piecewise(x < -2, x+3, x <= 2, 5-x^2, 3-x):
      t:=x->h(-x):
      a:= plot(h(x), x = 0 .. 10, color = red, thickness = 3):
      b:= plot(t(x), x = -10 .. 0, color = green, thickness = 3):
      display(a,b);

But  I am eager to know  the formal codes if they exists. Thanks for your time.

First I know that the Newton-Raphson formula gives N(z)=z-(f(z))/(f'(z)). If f(z)=z^+1, then N(z)=(z^2-1)/2z

 

Then the Question asks me to first define two important functions which I did:

1)T(z)=z-i/z+i where is i is imaginery number, 2)N(z)=z^2-1/2z. Hence, I wrote the following in maple:

>T:=z->(z-i)/(z+i)

>N:=z->(z^2-1)/(2z)

Then I was asked to show that T(N(z))=(T(z))^2, so I wrote the following commands:

>z:=2

>T(N(z))-(T(z))^2 (I got zero for their difference, so they are equal)

next, the question said the same wave verify that T(N^2(z))=(T(z))^4, so i wrote:

>T(N^2(z))-(T(z))^4 (but I got 0.3239121662-1.392199407I which is a complex number, not zero but WHY?)

and the rest of the questions are as follow:

1) What will be the general result? <-I don't what does it mean by general result :S

2) T(N^k(z)) will be what power of T(z)? <-Is it power of 2k?I have no ideas.

3) Try T(N^3(z)).<-which I know that T(N^3(z))=T(N^2(N(z))), so does T(N^2(N(z)))=(T(z))^6 then?

 

It would be appreciated If anyone could help me with this/clear up my confusion with questions. thanks.

 

 

 

I have a statistics task that is very complicated to me, and I would really appretiate some help!

I believe that I have completed task a, but task b and c seems to be too hard for me to grasp.

Here is a presentation of the task text:

 

xi 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
yi 12.3 12.8 16.8 17.9 20.5 22.7 24.9 27.5 26.9 29.4 30.3 34.2 36.4 36.7 41.1

Assume that the data represents independent realizations of a "linearlnormal" model.

Yi = α + β xi + ei i = 1..15,

where ei˜N(0,σ), where sigma is unknown.

 

(a) create a scatterplot of the data {f(xi,yi)}15 ; i=1
Then calculate the empiric correlation coefficient.

(b) Find the minimum least square estimate for α & β.

(c) Create a 95% confidence interval for the parameter β. What does this confidence interval express?

Is there anyone out there who are able to help me with some maplecode?


thanks in advance,

Soeta

I was successful in getting the Maple add-in to load into Excel 2013 but the help file accessed in the Add-In Ribbon is not found.  Does anyone know where in Excel that file can be loaded?

I've been given a question:

Let pn denote the nth prime number. Then p1 = 2, p2 = 3, p3 = 5, p4 = 7, p5 = 11, . . . .

It is known that the infinite sum 1/p1 + 1/p2 + 1/p3 + · · · + 1/pn + · · · = infinity.

Find the smallest positive integer N so that 1/p1 + 1/p2 +1/p3 + · · · + 1/pN−1 + 1/pN > e. [Hint : ithprime(n) generates the nth prime number.]

How do I start off?

Many thanks!

Usually maple returns the behaviour about the expansion point, but now I get a series in terms of weird powers...

I think the behaviour is logarithmic, but thats not what maple reproduces.

What results in this behaviour of maple?

limitxkl.mw

restart; with(MultiSeries); assume(omega > 0, s > 0, s < 1); x := arctanh(sqrt((1-s)/(1+s))*tanh((1/2)*omega*t)); xinf := limit(x, t = infinity)

arctanh(((1-s)/(1+s))^(1/2))

(1)

y := solve(.9*xinf = x, t)

2.*arctanh(tanh(.9000000000*arctanh(((1.-1.*s)/(1.+s))^(1/2)))/((1.-1.*s)/(1.+s))^(1/2))/omega

(2)

y := 2*arctanh(sqrt((1+s)/(1-s))*tanh(.6*arctanh(sqrt((1-s)/(1+s)))))/omega

2*arctanh(((1+s)/(1-s))^(1/2)*tanh(.6*arctanh(((1-s)/(1+s))^(1/2))))/omega

(3)

series(y, s = 0)

23.71899812/omega-0.1319507911e11*s^.6000000000/omega+0.1000000000e11*s^1./omega+0.8705505636e20*s^1.200000000/omega-0.1319507911e21*s^1.600000000/omega-0.7657989038e30*s^1.800000000/omega+O(s^2.000000000)

(4)

NULL



Download limitxkl.mw

 

I have a set of 19 different items I need randomize, lets call them A-S. I tried the Random command, Random(19,A-S) listing all of the possiblities. I want each letter to be used once in that 19 times and using this way does not do that. Is there another command I can use to achieve this?

Hey 

I'm trying to fit a spacecurve onto some points I have. 

I know, I can use Spline to do this in 2D, but it doesn't work in 3D.

What command(s) can I use to fit a spacecurve onto my points? 

Thanks in advance

I have to plot 4 vectors in one graph. I have the following structure:

plot(Vector([12, 12.5, 13, 13.5, 14, 14.5, 15]), Vector([1.622712644, 1.265443137, 1.028604736, .8605013333, .7352916667, .6386248233, .5618945274]), style = line, symbol = asterisk, color = blue)

and 

plot(Vector([12, 12.5, 13, 13.5, 14, 14.5, 15]), Vector([5.483608580, 4.289400489, 3.496793877, 2.933480578, 2.513320599, 2.188469637, 1.930230220]), style = line, symbol = asterisk, color = blue)

Could you help me to plot these two curves in one graph.

 

please help me to find a solution for this issue...

I would like to thank you in advance

Best regards,

D.L.

Hi, I have encountered a difficult question.

 

My answer is A=151,B = 47.

Could anyone tell me whether this answer is correct?

 

The question is as follow:

Pi=∑((120n2+An+B)/(16n((512n4 + 1024n3 + 712n2 + 194n + 15))  (n starts from 0 to infinity)

 

Thanks in advance.

Hi,

I need to solve following problem, but i m facing memory allocation problem in code. I dont know where memory is consuming.

Download nonlinearx.mw

Thanx in advance.

Regards

Sunit

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