Question: Solving Power extensions

Regards,

I need help with solving an equation. I have the following equation:

24*b[0]+24*b[1]*xi+24*b[2]*xi^2+(2*(-12+24*xi))*(b[1]+2*b[2]*xi)+(2*(-12*xi+12*xi^2))*b[2]+P[cl]*L^2*(-12*xi+12*xi^2)

to this equation I applied the comand: series(%,xi) and as a result obtained:

24*b[0]-24*b[1]+(72*b[1]-72*b[2]-12*P[cl]*L^2)*xi+(144*b[2]+12*P[cl]*L^2)*xi^2

My question is: the way to solve this equation in the manner I need is setting the coefficients in front of xi^n equal to zero for example:

24*b[0]-24*b[1] = 0 and solving for either b[1] or b[2] or

144*b[2]+12*P[cl]*L^2 = 0 and solving for P[cl].

I would like to know there is a way to do this other than pulling the expresions by hand setting them to zero and solving. 

Thanks.