Question: Building Arrays of Dynamic Dimension Count


I'm building my set of functions that will deal with geometries of different dimentions, thus I need to deal with/pass to my functions arrays of different dimentions count, I can't figure out how I can build arrays of, for example, n dimentions, where in each dimention m rows, currently I'm using if..elif on array dimention count that I'm retriving by using something lilke n=Size(Size(A),2) where A is the passed array, then I constracting my new arrays by B=Array(1..m,1..m... n-times), but it seems to be a wrong way, and there must be another clean way to build them dyanamicly, am I right?

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