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Question: int( x/(a^2-x^2), x)

Question:int( x/(a^2-x^2), x)

maplelearner 100 Maple
integral
June 01 2013
1

Dear Users,

 

Maple is giving the result for the following integration as

 

int( x/(a^2-x^2), x)  = -ln(-a^2 + r^2)/2  

 

However, I presume the integral output should be -ln(a^2 -  r^2) /2 

 

Could any one comment on this issue.

 

Thanks for your attention.
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