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Question: Why does the -> operator behaves like this?

Question:Why does the -> operator behaves like this?

taro 495 Maple
August 26 2015
4

Hello people in mapleprimes,

I have a question.

f1:=1+x:

unapply(f1,x);

returns x->1+x , with maple realizing 1+x is assigned to f1.

But, its short form

x-> f1;

returns

x->f1;

Why does this occur, and how can I have maple return the former result with x->f1 being input?

Thank you in advance for your help.

taro

 
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