Question: How to find six integer numbers a, b, c, d, e, m sastifying the following conditions

I know that, the function f(x) = (5x^2 + 8x+ 2)/(2x^2 + 6x + 5) sastifying the conditions:

  1. The solutions of the f'(x)=0 are -2 and -1;
  2. f(-2) = 6 and f(-1) = -1.

How can I find six integer numbers a, b, c, d, e, m from 1 to 10 so that the function
f(x) = (a*x^2 + b*x + c)/(d*x^2 + e*x + m)
so that the equation f'(x)= 0 has two integer solutions x1, x2 and f(x1); f(x2) are also  two integer numbers?

Please Wait...