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Question: Roots of a quadratic

Question:Roots of a quadratic

pallav 90 Maple
quadratic simplification
March 05 2024
0

Suppose I have to solve _Z^2 + (epsilon - 1)*_Z - epsilon + theta=0. If I use the code

solve(_Z^2 + (epsilon - 1)*_Z - epsilon + theta, _Z)

I get the solutions  as -epsilon/2 + 1/2 + sqrt(epsilon^2 + 2*epsilon - 4*theta + 1)/2, -epsilon/2 + 1/2 - sqrt(epsilon^2 + 2*epsilon - 4*theta + 1)/2

But I need them as (1 - epsilon)/2 + sqrt((epsilon + 1)^2 - 4*theta)/2, (1 - epsilon)/2 - sqrt((epsilon + 1)^2 - 4*theta)/2

How to modify the code so that I get the roots in the more simplified form, as I have mentioned above. 

Please help. 
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