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Question: Explore, and plot involving fsolve

Question:Explore, and plot involving fsolve

Hullzie16 428 Maple 2025
procedure explore fsolve plotting
18 hours ago
0

I am trying to plot a function where one of the variables is determind via a procedure that uses fsolve and depends on some parameters. When I go to try and make a plot using Explore to vary the parameters I get the following error:
"in fsolve  S  is in the equation, and is not solved for"
My worksheet is seen below:

> 

restart;

 

> 

T := 2^(2/3)*(16*CC(S,mu,Z,Pr)^2*Pi^2 + 2*Pi^2*Z^2 + 16*Pi*S*CC(S,mu,Z,Pr) + 3*S^2)*Pr^(1/3)/(4*(4*CC(S,mu,Z,Pr)*Pi + S)^(2/3)*(2*Pi^2*Z^2 + 4*Pi*S*CC(S,mu,Z,Pr) + S^2)^(2/3)*CC(S,mu,Z,Pr)^(1/3)*Pi^(2/3))

(1/4)*2^(2/3)*(16*CC(S, mu, Z, Pr)^2*Pi^2+2*Pi^2*Z^2+16*Pi*S*CC(S, mu, Z, Pr)+3*S^2)*Pr^(1/3)/((4*CC(S, mu, Z, Pr)*Pi+S)^(2/3)*(2*Pi^2*Z^2+4*Pi*S*CC(S, mu, Z, Pr)+S^2)^(2/3)*CC(S, mu, Z, Pr)^(1/3)*Pi^(2/3))

 (1)

 

> 

mu = 2^(2/3)*S*(16*C^2*Pi^2 - 2*Pi^2*Z^2 - S^2)*Pr^(1/3)/(4*(4*C*Pi + S)^(2/3)*(2*Pi^2*Z^2 + 4*C*Pi*S + S^2)^(2/3)*C^(4/3)*Pi^(2/3))

mu = (1/4)*2^(2/3)*S*(16*C^2*Pi^2-2*Pi^2*Z^2-S^2)*Pr^(1/3)/((4*C*Pi+S)^(2/3)*(2*Pi^2*Z^2+4*C*Pi*S+S^2)^(2/3)*C^(4/3)*Pi^(2/3))

 (2)
> 

CC:=proc(S,mu,Z,Pr)
fsolve((2),C,C=0.01..100)
end proc;

proc (S, mu, Z, Pr) fsolve(mu = (1/4)*2^(2/3)*S*(16*C^2*Pi^2-2*Pi^2*Z^2-S^2)*Pr^(1/3)/((4*C*Pi+S)^(2/3)*(2*Pi^2*Z^2+4*C*Pi*S+S^2)^(2/3)*C^(4/3)*Pi^(2/3)), C, C = 0.1e-1 .. 100) end proc

 (3)
> 

CC(1,0,0.5,0.2)

.1938622552

 (4)
> 

Explore(plot(T,0..15),parameters=[[mu=0 .. 1,minorticks=0.25],[Z=0..0.5,minorticks=0.1],[Pr=0..1,minorticks=0.25]])


When I try to move the sliders on my parameters this is where I get the error. I want to plot over S, but I can only get CC once I have all the other values including S. I assume it has something to do with the fact that my plotting variable is in the procedure?

Any help would be greatly appreciated, thanks. 

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