Question: T(t) = 20 + 74e (-ln(.4t) / 2)


A hot piece of steel which is 94 degrees C is placed in a room that
is kept at a constant temperature of 20 degrees C. The steel begins to cool; its
temperature t hours after being placed in the room is given by
T(t) = 20 + 74e
(a) How long before the steel reaches 22 degrees?
(b) Graph T(t).

(c) What will be the ultimate temperature of the steel

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