I have an equation which i have differentiated twice and evaluated at eta=1.
F''(eta)=-3*eta+(3*eta^5/20-9*eta/140)*R+(eta^9/840-3*eta^7/140+9*eta^5/1400)*R^2+...
evaluated at 1 we get
F''(1)=-1+3*R/35-394*R^2/40425+4924*R^3/6131125-43969148*R^4/980274920625+...
This equation is derived by an iteration process. Each time it is iterated we add an extra term where the power of R increases by 1.
I want to write R in powers of (F''(1)+3).
How would i go about doing this with maple?
If it is easier to write

Write a procedure

input:a polygon and a linear transformation

output :applying the transformation to the polygon
 

Find the coordinates of the linear transformation that would have  the a larger square to the pink (smaller) square.Apply the transformation to the blue square.
 

please help with this, thnaks

Hello, it's been awhile since I've used maple and I'm a little stuck here.

I'm basically trying to model charging of a capacitor with a load dependant voltage source. Capacitor voltage depends on source voltage but source voltage depends on capacitor voltage, classic ode problem. Now I can define the entire ode in one statement and then solve but I'd like to define the components that the ode is made of and then solve for d(f(x))/dx and then dsolve. When I try to build an ode with multiple statements however, I get a 'too many levels of resursion' error.

Use a procedure that takes as input a positive integer and two real numbers a and b
and produces as output  a polygon centered at (a, b). Base on the procedure,  obtain a list of twenty decagons centered in (0, 0), (1, 1), ..(20, 20)

(I have no hint,please help, thanks)

hi, i am trying to show that the sum of (1/2 + 2/3 + 3/4 + 4/5 + ... +n*(n+1)+ ...) can be approximated by the following: sum(1/(exp(1))^(1/n), n = 1 .. infinity). e.g. > sum(1/exp(1/n), n = 1 .. 10); print(1/exp(1)+1/exp(1/2)+1/exp(1/3)+1/exp(1/4)+1/exp(1/5)+1/exp(1/6)+1/exp(1/7)+1/exp(1/8)+1/exp(1/9)+1/exp(1/10)); 1 1 1 1 1 1 1 1 1 ------ + ------ + ------ + ------ + ------ + ------ + ------ + ------ + ------ exp(1) /1\ /1\ /1\ /1\ /1\ /1\ /1\ /1\

I have tried the Physics package. First of all, how can I define a non-ortogonal basis (using kets)? Suppose I have a basis formed by linearly independt vectors. How to set them non-ortogonal?

Using plot3d I can obtain a plot of a function u:=f(x,y). Then I rotate the plot and find the view that I want by trial and error. However, If I run the plot again with different parameters, I have to again find the view I want by trial and error. Setting the plot3d orientation option by trial and error to achieve the required view is very tedious. My question is: Once I have found the view I like, is it possible to then obtain the orientation data so that it can be used in subsequent calls to plot3d? Any help appreciated.

Hi there, in this post http://www.mapleprimes.com/forum/howplot1 I asked one plotting question when Y[1] and Y[2] are independent what if they are not independnt? say I have f( y1, y2) for Y[1] in [a,b] and Y[2] in[c,d] then I have U[1] = f ( Y[1], Y[2] ) and U[2] f ( Y[1], Y[2] ) (different functions of Y[1] and Y[2]) How do I plot the mapping for U[1] and U[2]? to determine the range for u1 and u2? Thanks Casper =============================

Hi everyone!

I'm stuck with a problem, and I thought I might get some help here. Would be greatly appreciated. Anyway, here goes:

For a given function of two variables, say g(x,y), we can produce a 2d-contourplot (for example using the contourplot-command). No that's all swell as long as we actually have a closed expression for our function g (like, for example, sin(x^2 + y)).

Hi there, here are the commands: > y[1]:=exp(1)^(-(1/2)*(u[1]^2+u[2]^2)); > y[2]:=arctan(u[2]/u[1])/(2*Pi); > a:=diff(y[1],u[1]);b:=diff(y[1],u[2]);c:=diff(y[2],u[1]);d:=diff(y[2],u[2]); then it begins > a*d-c*b; g:=abs(simplify(%)); i got the funny "Re" thing in the expression why it didnt give me the answer as I would expected if I use the following command? > a*d-c*b; g:=-1*simplify(%); that's what I wanted the idea is I want the absolute value of the simplified answer ( simpify(%)) what's the difference here?

convert( (z)_n, GAMMA)  does not give the desired  GAMMA(z+n)/GAMMA(z).

Instead of Maple gives the answer   (z)_n.

How could I obtain the GAMMA form?

Thanks,

                   Sandor

Hi, I got to several funtions as follows: U[1]:= ( -2 * ln(Y[1]) )^(1/2) * cos(2*Pi* Y[2]) U[2]:= ( -2 * ln(Y[1]) )^(1/2) * sin(2*Pi* Y[2]) for Y[1] and Y[2] in (0,1) I want to find the range for U[1] andU[2] how do I plot them? Thanks Casper

In Maple11 odeadvisor does not know the Euler type differential equation.

For example, R(r)+ r R'(r)+r^2 R''(r)=0.

It is the same situation in Maple12?

Thanks, Sandor

We have the following situation.   An assignment whose finish date has passed is locked and if (for instance) one tries to edit it one is told that there is an active user taking it or credit.    We have force-graded all active assignments, and the gradebook now shows no  assignments in progress.      We can not find any way to unlock this assignment.     (And the assignment is not inherited from or to another class.)