Hi, 

I work with Maple as professional and I want to buy one tablet for convenient . Is there Maple for Tablet? which operating system? Android, ios or windows 8 tablet?  which one is better?

Thanks.

If I have spreadsheet data, x and y (velocity and time), I need to find distance.  I see numbers of ways to do this, however, I wonder what people would suggest as the fastest / easiest way.  I'm not needing a function really, just results.  Does Maple have tools to simplyify this process, and if not, what process(s) might yield results of determinable or selectable accuracy.  I will have many sets of data in the future that need to be manipulated...

How can I draw following piecewise closed function t in  3-dimensional cartesian space

D124:=max(-x+y+z,x-y+z,x+y-z)=1; 
D134:=max(-x+y+z,x-y+z,-x-y-z)=1;
D123:=max(-x+y+z,x+y-z,-x-y-z)=1;
D234:=max(x+y-z,x-y+z,-x-y-z)=1;

 

t:=piecewise(x>0 and y>0 and z>0,D124,x<0 and y<0 and z>0,D134,x<0 and y>0 and z<0,D123,x>0 and y<0 and z<0,D234);

Is it possible to install a 64-bit edition of Maple 17 linux version into a Windows 8 machine throughout the Cygwin64 interface?

When defining a polynomial as follows

p:=x->x^(r+1)-(r+1)*Sum((-1)^(r+k)*(r+k)!*(r+1)!*r!/((k!)^2*(r-k+1)!*(2*r+1)!)*x^k,k=0..r);

the result of

simplify((eval(p(1),r=1)));

is given as 1 whereas hand evaluation and also plotting the polynomial clearly shows that the result is 0. How can this behaviour be explained?

Hi,

How do I get ride of these Rootof?

I tried simplify,evala,value,Simplify and ect. Didnt really find anything useful.

Download rootof.mw

 

I dont care which root they actually take, all I want is one of the roots. So I can then use subs for substitution.

Casper

How can I draw following piecewise closed function in  3-dimensional cartesian space

t:=piecewise(x>0 and y>0 and z>0,D124,x<0 and y<0 and z>0,D134,x<0 and y>0 and z<0,D123,x>0 and y<0 and z<0,D234); 

 

         max(-x + y + z, x - y + z, x + y - z) = 1 ,  0 < x and 0 < y and 0 < z
         max(-x - y - z, -x + y + z, x - y + z...

Hi,

 

Another (hopefully) simple question that I can't work out the answer for. How can I write an if loop for which n things must be true? I need to have:

if thing[1]=true and thing[2]=true and thing[3]=true and ... and thing[n]= true then
...;
fi; 

 

n will change for different inputs, so I can't write out explicitly.

Hope that makes sense! Thanks.

Good day.

Reading the documentation on Physics package in Maple, I did not find information about how Maple handle dummy indices of tensorial expressions. For example, suppose I have the following tensorial expression in Maple: 

    A[mu] * B[~mu] 

with dummy index mu. Then I want to apply the following simple substitution rule:

    A[alpha] = C[alpha]*C[mu]*C[~mu]  

Here, free index alpha should be...

I would like to plot the following expression that I call W

>W:=tau*exp(C4)/C1-exp(C4)*(exp(C3-C3*eta)/C3^2-exp(C3)/C3^2+tau/C1+eta/C3)+exp(C4-C3*eta/2)*Sum(16*beta[m]*sin(beta[m]*eta/2)*exp(-(beta[m]*beta[m]+C3^2)*tau/(4*C1))/((beta[m]*beta[m]+C3^2)*( beta[m]*beta[m]-C3^2)^2),m=1..n)

Where C1, C3, C4 are constant, and  beta[m]satisfies the relationship  

C3*sin (beta/2) =beta*cos (beta/2)

I want to plot the W-eta curve and W-tau curve (eta at [0, 1...

Dear sir i  want the contour values  automatically display on the contour.

Hear is the code and sample contour plot. 

contourplot(x^5-y^3,x=-5..5,y=-4..3,axes=boxed,contours=10);

Hi all,

What else could I try if I encounter this error?

Warning:  Incomplete separation.

--------------------------------

 

I read the pdsolve help page, where it says I should have a solution with this warning, but I got nothing but the error.

 

Dear Maple users

I am working on a problem, which basicly is dealing with putting n identical marbles in k different boxes. I need to run through all possible combinations and do something with it. The latter is unimportant. Mathematics say there are binomial(n+k-1,k-1) different combinations. I have already produced a recursive procedure to solve the problem and it is displayed below. I have placed a counter in the procedure to control if the procedures get through...

Hello,

I would like to assign a value I got from using the command 'Maximize'. What I gained as an answer is of the following form:
test:=[1234124, [t=124124124]] 

Now my point is to assign both these values to variables, which I can do for the first like:
first:= test[1];

But I just can't find out how to assign the second value.
I was trying it out by using the command 'rhs' but that doesn't work (although, not for me).

Probably a silly question, but yeah..thanks for a reply.

Frank 

Dear all,

I'm trying to substitute a combination of variables in an equation that is partly covered in a summation.

For example consider the equation with two variables A and B, and two function W(t) and q(z):

now I want to do the substitution: