I have a procedure that gets two lists A and B, I want to restore the name of the entry lists as string. How can I do that?

f(A,B) [procedure]

e.g. a(MyList,LL)

I want to restore a:="MyList" and b="LL"

TIA

Hi,

I would like to animate the solution to

x'(t)=y(t)

y'(t)= -4x(t)

that passes through x(0)=2, y(0)=1 as it orbits (0,0). I need to include the phaseportrait as the background. Any ideas on how to accomplish this?

Thanks!

Hey guys,

Really struggling with computing an algorithm on maple for the Stable Marriage Problem? Would be so appreciative for any help. Thanks Claudio

Does anyone know how to create one in maple? please see the example attached..

Compute the coefficients of
> a:=`@@`(D,6)(u)^3; 
#and
> b:=`@@`(D,5)(u)*`@@`(D,6)(u)*`@@`(D,7)(u);
#in the differential polynomial
> c:=`@@`(D,18)(u^3);.

Helppppppp :) TIA

Oops! you are right, thanks. How if the equations like these

f11:=conjugate(1/Pi*I*f1)=0:

f22:=conjugate(1/Pi*I*f2)=0:

fsolve({f11,f22})

where f1 and f2 are same as in the previous post.

The results are not explicit. How can we fix it?

Thanks again

I have two equations with weierstrass functions and got problem with fsolve: 

f1:=WeierstassZeta(z1-z2,0.1,2.)+z1=0:

f2:=WeierstrassZeta(z2-z1,0.1,2.)+z2=0:

fsolve({f1,f2});

results are like Weierstrass (z1-z2,....) which are not simplified even I add 'simplify' in fsolve. I want the values of z1 and z2 explicitly, i.e. z1= ,z2 . How can I fix this. Please help.

Thanks

Dear all,

I'm currently facing the following problem. I am trying to solve an expression for 4 variables: Fe11, Fe12, Fe21, Fe22. Actually these variables come from a 'deformation gradient tensor' Fe that is used in continuum mechanics.  This tensor actually appears in two equations in tensor-form. Since these tensorial equations contains 'inverse' and 'transpose' operators, the only thing I could think of to solve for a particular tensor (Fe), is to do this component-wise....

Is there a way to have filled or coloured regions in a polarplot?

I am just learning Maple, but have plotted several parametric curves.  However, the attached code is giving me an error message that seems to be saying that my indices for the two elements of the curve vector are out of range.  I don't see why.  Can you explain?

Here's the file:  NewtonLeastResistanc.mw

Thanks for any help!

It's a simple question, but I could not find a hint in the help system.

In economics it is very common to name variables like Y*, π* etc. They are unique, e.g. Y* ≠ Y

How can I enter them? If I just do it, it is interpreted as a vector function.

From time to time, you even need variables that have an overline (or bar),  above the character in addition to the asterisk, or variables like Â*.

A similar problem are variables that are named y' ...

piecewise not suitable to sum:

restart;
with(codegen):
H:=proc(y,a,b) y+piecewise((y>0), a,b); end proc;
prep2trans(H);
Error, (in intrep/StatSeq) invalid terms in sum: if 0 < y then a else b end if

Any walkarounds?

Hi

I have 2 functions here and I want to study their graphic. I never used Maple for that kind of things but this is probably the fastest and more precise way to see what happens graphically when it comes to those functions:

y1(t) = -rDirac(t) + t^2* summation (from n=0 to infinite) (r^(2n-1) * Dirac(t-2*n*Tau))

y2(t) = t^2* summation (from n=1 to infinite) (r^2n*Dirac(t-(2n+1)*Tau)

Hello. I need to solve a problem where:

  A is defined over a real inteval [c...d]   and   B is defined over another real interval [d....e]. 

I want maple  to take max(A,B) and tell me which interval is larger( asume no intersection)

For example

A=[0....1] and B=[2...3]

Answer should be max(A,B)=B

Thank you

For given expression expr it's known that  type(expr, function) returns true. How to grab name of that function in fast way?

Unserstood that in slow way could be transform to string done and after that could be found substring till 1st '(' symbol. But i'm sure that name somewhere 'sits' directly.