Hello everyone!

i want to make a triangle which height's is a. Sorry, my English is not very good!

And I writed it by C language, but It is not right in maple. and I don't know. Can you help me? thank you very much! triangle.mw

Hi all,

How can the black circle be visible?

Visible also below the 3D graph?

Best, perr7

B := spacecurve( [R*cos(t),R*sin(t),0] ,t=0..4*Pi,thickness=1, style=line, color=black);

animate( plot3d, [     P_Pi2(x,y,t)  ,  x=-4000..4000,y=-4000..4000 ], t=0..1, frames=10, transparency=0, style=surfacewireframe, labelfont=[times, roman, 25], orientation=[45,60,0], view=[-4000..4000, -4000..4000, 0..0.006], caption=typeset( theta=Pi/2 ) , axesfont=[times, 15], axes=frame, background=B   );

It's my first post on this forum so Hi everyone from Poland!

I have the following question.

Is it possible to force the Maple to obtain a result in a particular form? For example instead (a+b)³ I wan to have the result of the form: a³+3a²b+3ab²+b³. And I want to multiply the red brackets to receive a quadratic forms.

Below is a sample result that I get and I want it in a different form.

http://i65.tinypic.com/28k29hk.png

[IMG]http://i65.tinypic.com/28k29hk.png[/IMG]

with sin(x) and cos(x). how to draw  this graph:

question.mw

thanks you!!!

Download question.mw

Iam a newbie, just two weeks into my 30-days trial. I have been exploring the symmetry aspect of PDEtools, gone through materials in the help section but still having problem in some of my analysis. The answer to the titled question "Symmetry analysis with parameters" was really helpful but did not work out for me when the parameters are more than one. Attached is a sample question.

sample_question.mw

Download inf2.mw

hello

i write this set of differential equation in maple and get the following error?

Can anyon help me with this?

thanks

hi.for linear coupling equation

dsys3 := {-72.49829200*(diff(f1(x), x, x))+0.8377580411e-2*(diff(f2(x), x))-8.873545400*10^9*(diff(f3(x), x))+2.114533515*10^18*f1(x), -878.8477313*(diff(f2(x), x, x))+1.590065471*10^20*f2(x)-7.353421206*10^(-26)*(diff(f3(x), x, x))+4.891459762*10^10*f3(x), 4.027667395*10^(-20)*(diff(f3(x), x, x, x, x))-0.6274394007e-2*(diff(f3(x), x, x))+8.873545401*10^9*(diff(f1(x), x))-7.352113720*10^(-26)*(diff(f2(x), x, x))+4.904509456*10^10*f2(x)+1.208381068*10^19*f3(x)-2.499990383*10^26*omega*(diff(f3(x), x, x))}

by assuming and to expand these functions(f1-f2-f3) in polynomial form(e.g. Chebyshev, power polynomials, Legendre and etc).:

f1(x):=(∑)H[i] *(e)^(lambda[i] *x); f2(x):=(∑)alpha[i]*H[i] *(e)^(lambda[i] *x);f3(x):=(∑)GAMMA[i]*H[i] *(e)^(lambda[i] *x)

how i detemine lambda[i] which are roots of the  characteristic equations?in other word how i can build characteristic relation for coupling equation?

2)how i can gain value for alpha[i] and GAMMA[i]

by using equation

Q1 := subs(x = 0, sum(H[i]*exp(lambda[i]*x), i = 1 .. 8)); Q2 := subs(x = L, sum(H[i]*exp(lambda[i]*x), i = 1 .. 8)); Q3 := subs(x = 0, sum(alpha[i]*H[i]*exp(lambda[i]*x), i = 1 .. 8)); Q4 := subs(x = L, sum(alpha[i]*H[i]*exp(lambda[i]*x), i = 1 .. 8)); Q5 := subs(x = 0, sum(GAMMA[i]*H[i]*exp(lambda[i]*x), i = 1 .. 8)); Q6 := subs(x = L, sum(GAMMA[i]*H[i]*exp(lambda[i]*x), i = 1 .. 8)); M := diff(sum(GAMMA[i]*H[i]*exp(lambda[i]*x), i = 1 .. 8), x); Q7 := subs(x = 0, M); Q8 := subs(x = L, M)

????

thanks...

chebyshev.mw

   1*  printf("degree = %f\n",a);

end proc

   2   printf("radian = %d\n",evalf(1/180*a*Pi))

When executing the following orders,

a:=0.006:

convert(a, symbol);

the result is .6e-2.

How to make Maple return the form 0.006, just as the original?

I downloaded Maple Player, and I don't know how can I use it resolve Maths problems. Kindly, could you explain to me the procedure I shall follow for the reason to use it?

How I can watch the direction of current in electric circuit?For example in AC also plot value on maplesim how do it do?(I need a solution with example arrow or animation).thank

Hello

I want to plot in semilog graph the attached function.where b from 1 to 5 and R from 1 to 100000(in logR)I tried with the plot builder but i think i am doing smthing wrong

Download re.mw

I want to obtain polynomial representation of my data:

with(Statistics):

X:=Vector([huge data package-X],datatype=float):

Y:=Vector([huge data package-Y],datatype=float):

NonlinearFit(c*t^2+b*t+a, X, Y, t)

but I can't see any result. What's the problem?

My worksheet: He_p=f(t).mw

How plot two functions of two variables to (2-dimension)?

restart;
approximate := exp(-2*t)+x*exp(-2*t)+(1/2)*exp(-2*t)*x^2+(1/6)*exp(-2*t)*x^3+(1/24)*exp(-2*t)*x^4+(1/120)*exp(-2*t)*x^5+(1/720)*exp(-2*t)*x^6+(1/5040)*exp(-2*t)*x^7+(1/40320)*exp(-2*t)*x^8+(1/362880)*exp(-2*t)*x^9+(1/3628800)*exp(-2*t)*x^10+(1/39916800)*exp(-2*t)*x^11+(1/479001600)*exp(-2*t)*x^12+(1/6227020800)*exp(-2*t)*x^13+(1/87178291200)*exp(-2*t)*x^14+(1/1307674368000)*exp(-2*t)*x^15+(1/20922789888000)*exp(-2*t)*x^16+(1/355687428096000)*exp(-2*t)*x^17+(1/6402373705728000)*exp(-2*t)*x^18+(1/121645100408832000)*exp(-2*t)*x^19+(1/2432902008176640000)*exp(-2*t)*x^20+(1/51090942171709440000)*exp(-2*t)*x^21;
apr := unapply(approximate, x, t);
Exact := (x, t)-> exp(x-2*t) ;
plot3d(exp(x-2*t)-approximate, x = 0 .. 5, t = 0 .. 5);

plot.mw

Suppose I have the parametric equations of a circle

x=cost

y=sint

where t runs from 0 to 2*pi. How can I show the orientation of this parametric curve on a plot?