Sorry for the last post:

StandardDeviation not StandardVariation

with(Statistics);

L := [3, 2, 2];

W := [7, 5, 8];

StandardDeviation(L, weights=W);

The results by Maple 17 is 0.589345606817264

But the value of the standard deviation value must be : 0.489360484929593

What is the problem?

Thanks in advance!

I am trying to solve these equations:

eq1:=cot(theta[n])=(omega[a]^2 - omega[n]^2)/omega[n];

eq2:=cot(theta[n]+ omega[n])=-(omega[b]^2 - omega[n]^2)/omega[n];

for some values of omega[a] and omega[b]. I will in the end create two 3d plots for omega[n] and theta[n] as a funciton of ometga[a] and omega[b]

So for example for some particular values have:

eqs:=subs(omega[a]=0.2, omega[b]=1, [eq1, eq2]);

Then solving,

solve(eqs, [omega[n],theta[n]]);

gives:

I'm however only interested in solutions where omega[n]>=0, but doing this:

solve(eqs, [omega[n],theta[n]], UseAssumptions) assuming omega[n]>=0.0;

returns an empty list. Adding the condition omega[n]>=0.0 to the list of equations also does not work.

Is this a bug or am I missing something? Note, I realize that i can manually go through the entries myself and pick the right solutions, I am just asking how to force maple to do this automagically.

thanks

Here is the full code:

restart:

eq1:=cot(theta[n])=(omega[a]^2 - omega[n]^2)/omega[n];

eq2:=cot(theta[n]+ omega[n])=-(omega[b]^2 - omega[n]^2)/omega[n];

eqs:=subs(omega[a]=0.2, omega[b]=1, [eq1, eq2]);

solve(eqs, [omega[n],theta[n]]);

solve(eqs, [omega[n],theta[n]], UseAssumptions) assuming omega[n]>=0.0;

Let a(1)=916 , a(2)=935 , a(3)=713  , a(4)=845  , a(5)=274  , a(6)=914 ,a(7)=255 . Find formula a(n)= ? ,n=1,2,3,....

I cannot copy and paste into this site using the Google Chromium brower (v 32). Has anyone had this problem and know of a work-around? What I'd really like to do is use Edit-with-Emacs (a chromium extension). It works for other sites.  I can open it from this site, but nothing I enter gets transferred. I'm guessing this is related to the inability to cut/paste.

Hello everyone,

I'm having some trouble overlaying a set of complex plots. I follow the usual procedure 'display(p0,p1)' I only get p1...

If i try with plots the display command works fine, here's the piece of code I'm trying to get working (r is defined elswhere as function of x and phi):

i := 0;

p := Array(0 .. 10);

for x from 0 by .2 to 2

do p[i] := complexplot(r, phi = -(1/2)*Pi .. (1/2)*Pi);

i := i+1

end do;

display(p[1], p[10]);

Any hints?

Cheers,

Felipe

I am a new user of Maple. Could anyone help me to know how to call a Maple function/procedure from a Matlab program with a simple example? And conversely, how to call a Matlab function from Maple.

I have 20 datapoints in two groups. I may name them as f[1],...,f[10];g[1],...,g[10]. f[1]:=[1.2,3.5] etc

I would like to plot these 20 points

(1) in one plot

(2) f[1]~f[10] in one color; g[1]~g[10] in another color.

I checked http://www.maplesoft.com/support/help/Maple/view.aspx?path=plots%2fpointplot

and did not get the point :(

Do you any suggestion what can I do to realize the aims (1) and (2)?

Thank you very much in advance!

Hi, 

  I tried to use generated random as following

*** 

for j from 1 to 5 do
    c:=rand(0..1):
    d:=c();
    print(`random number`,c(),d);

    if c()=1 then

       print(`Y`)
    else
     print(`N`);
    end if;
  end do:

***

  The output is

****

                      random number, 1, 0

                               Y

                      random number, 1, 1

                               Y

                      random number, 1, 1

                               N

                      random number, 1, 1

                               N

                      random number, 0, 0

                               N

****

  Why the output numbers in one line are different? And Using "if" sentence seems do not correspond to the printed "c()" value..

Thank you very much in advance!

Say we solve numerically and ODE using Maple. Say ode1:= { diff(Q(x),x)= Q(x)/3x , Q(1)=1 }

The solution is a procedure so now suppose we have another ODE where the solution appears.Say  ode2:= { diff(f(x),x)= Q(x)*x , f(1)=4}.

To extract the solution of the first ODE I set sol1:=dsolve(ode1,numeric) and Q:=proc(x) local s: return rhs(sol(x)[2]): end proc:

But now I got an error message when I trying sol2:=dsolve(ode2,numeric).

Is it possible to use a procedure in the definition of the ODE one wants to solve?

Rewrite the code that counts the number of primes less than using an if-then statement.  Implement    your code where j goes from 2 to 15.

j:=1;
                               1
for i from 2 to 10
while ithprime(j)<2^i do
j:=j+1
end:
print(2^i,primes=j-1):
                        2048, primes = 9

I need to edit this code to satisfy a IF then Statement. can any one help me out?

\

regards "Geordi"

I have a rational function

R(s)=(s+21.2618806754099918582959684287)*(s+11.5825785765671047665686926962)*(s+2.32652929385663964079968631791)*(s+1.59184930187007023058678840475)*(s+.810126597053864402120805704729)*(s+.767936478999246633196341750975)*(s+.389728032793176474756405528288)*(s+.389709386740696868210134112440)*(s+.384534001672741409749016411776)*(s+.211738661184088496193941380283)*(s+.211735400886327624028116769728)*(s+0.123260440562617421046327062708e-1)*(s+0.749282759458414677904525855939e-2)*(s+0.129947118285955895103018704133e-2)*(s+0.128454333534479589397814117349e-2)*(s+0.342482256507583139104896521750e-3)*(s+0.342471571076865824849860353286e-3)/(s+21.2618806754099918582960530179)*(s+21.1471825573992794470615428324)*(s+2.32652929385663964079964525218)*(s+2.28350165975702233286000082419)*(s+.810126597053864402120855775248)*(s+.804997206582678244211665005890)*(s+.389728032793176474755312749208)*(s+.389718248252695846631246554139)*(s+.384534001672741409750430258543)*(s+.243633167007009257956784127718)*(s+.211735400886327624028133231990)*(s+.211726934369736929202050835884)*(s+0.749282759458414677904914554540e-2)*(s+0.555247691543530827690454070563e-2)*(s+0.128454333534479589395816020810e-2)*(s+0.126961222591792792857168643430e-2)*(s+0.342471571076865824866184397991e-3)*(s+0.342461825593204099734633561207e-3)

I want to cancell the roots which are equal up to 7 digits?

How to write a maple code for this problem?

In doing multiple linear regression with Statistics:-LinearFit, how do I get or compute the values commonly called R^2 and R^2[adjusted], also known as the coefficient of determination? I know that residualsumofsquares is part of it. I also need the "total sum of squares" to compute R^2. And how do I modify that to get R^2[adjusted]? These things do not seem to be among the numerous output options to LinearFit. These values (R^2 and R^2[adjusted]) are typically part of the output of other statistics software when doing multiple regression.

I'd also like the p - values for the significance of the individual parameters and the p - value for the global utility---also things that are standardly reported by statistics software.

Hi Mapleprimes community,

I am a maple novice and was trying to write a procedure but cannot tell what my syntax error is.  I would greatly appreciate if anyone can point out what I did wrong or any improvement in the code that I can make.  Thanks

SLRrepeatedsample_pr.mw

Henry

I am trying to create a procedure that can solve integrals using the Composite Simpson's 3/8 rule. However when I test my procedure against maple's ApproximateInt I am getting the wrong results.

Here is my attempt:

restart;

f:= x -> exp(x)*sin(4*x); # function I am using

simp := proc(a, b, n)
  local h, sum, i, single:
  h := (b-a)/n:
  sum := 0:
  single := (3*h/8) * (f(a) + f(b)): # this is the end points
    for i from a+h by h to b-h do
       sum := sum + (3*h/8) * (3*f(i)):
    end do:
print(evalf(sum + single));
end proc:

simp(0,1,12);
                                                                                0.6224486445
evalf(Student:-Calculus1:-ApproximateInt(f(x), 0..1, method = simpson[3/8], partition=12));

                                                                                0.5323516717

As you can see my answer is not very close to the answer given by Maple. I am not sure why my procedure simp is wrong.