## 5093 Reputation

16 years, 210 days
Munich, Germany

## hm...

@vv I think it is beta, not Pi/2 - beta (take beta=Pi/8 as example), no?

## JacobiSN...

Do both systems use the same definition for JacobiSN ?

## minus sign ?...

@vv but how to explain the minus sign?

## failed (2)...

Dito: For me that does not work (Maple 2017). In earlier days I used Excel on finacial data, because it worked and was more easy to use, especially for (embedded) tables

May be you try the sources at https://data.europa.eu/euodp/en/data/dataset/covid-19-coronavirus-data

## different functions, same names...

For example in C++: http://www.cplusplus.com/reference/cmath/round/

You may want to get used to that

## plotting shows it...

phi*W: subs(Zeta=zeta, %): [Re(%), Im(%)]:
plot(%, zeta = 0 .. 2*Pi, color=[red, blue]);

## a=0 is not in your domain...

a=0 is not in your domain

## "plain" worksheet as well ?...

Thank you - do you have a version as plain worksheet as well, containing meaning visible code instead of sliders?

## Thank you...

@tomleslie Thank you, now I see

## scaling ?...

Neat!

I wanted to scale it to have N = 1 = 100%, but the solutions do not scale - how to do that in your setting?

## 2F1...

1. You should consult Maple's help about hypergeom( [n1, n2], [d1], z) - the input for the parameters n1,n2,d1 as list is a convention only.

2. You also could search a bit on the web, https://en.wikipedia.org/wiki/Hypergeometric_function (not all languages have the same info), the case is often denoted by 2F1. Roughly this stands for a powerseries in z = cos(x)^2

## Re: Automatic simplification...

@Preben Alsholm : You are right, thank you.

## It works as expected...

evalf[2](1000 - 1); # preferred notation
1000.

evalf(1000 - 1, 2);
1000.

NB: For me the following is a bug:

evalf[2](1014 - 1007);
7.

## :-)...

neat - frohe Feiertage!

## sign (2)...

@Mariusz Iwaniuk : or in Maple notation you just forgot the minus sign of your trick

with(inttrans):
'fourier(diff(F(x), x)*I/k, x, k)':
'%' = %;

/d      \
|-- F(x)| I
\dx     /
fourier(-----------, x, k) = - fourier(F(x), x, k)
k

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