Axel Vogt

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16 years, 210 days
Munich, Germany

MaplePrimes Activity


These are replies submitted by Axel Vogt

Besides that I doubt you can still buy it:

Version 9.5 is dated, 15 years old. Once I tested it to use it on Windows 7 (~ 2010) and it did not work properly for that operating system.

@rookie 

No typo, it reminds me that I modified the original, https://svn.r-project.org/R/trunk/src/library/stats/src/zeroin.c 

@vv so you say the random number is added for each call of f ... hm. But the optimum is searched for the (guessed) f0 ? Then I got it wrong

@mmcdara

Find some examples from the package (which is free) in the attached pdf. Certainly it solves the example in the paper (at the end).

Examples_from_DirectSearch.pdf

@J F Ogilvie unfortunately not, I was trying to understand the task

Probably the best would be to use https://www.maplesoft.com/applications/view.aspx?SID=101333, stable and validated, instead of trying to translate a 40 year old code

Or more simple: you ask for the length of the graph of an oscillating (damped) function cos(x)*exp(r*x+s), yes?

@mmcdara yes, I meant something like that - and it may be quickly more complicated to write it down in Maple than writing down the Math (as far I understand you here: do a linear change of variables and re-arrange terms)

Essentially you have to write down the formal steps of the proof you know from lectures, now using Maple's notations

please post code (as text or uploading a Maple sheet), not images

and your assumptions on t should be stated

Even for a simple case you will get no answer, say Int(sqrt(1/(2*ln(t)+t)), t = 1 .. 2)

@JanBSDenmark 

I have installed 2020.0, which I do not want to change it for that test, so can not show it

@Carl Love I suppose that on Windows the filename can be catched from system libraries, since the dialog "save as" automatically provides the name

@tomleslie he is using Maple 2019, and in Maple 2020 I get your result without the Physics extension

u(x) = 1/10*piecewise(x < 0,(-1+I+(1+I)*3^(1/2))*5^(1/2)*(22*I*x+(16*x^2+44*x-1
)^(1/2)-I)^(1/6)*2^(1/3)/x^(1/3),x = 0,20,0 < x,2*(-1)^(1/12)*5^(1/2)*2^(5/6)/x
^(1/3)*(22*I*x+(16*x^2+44*x-1)^(1/2)-I)^(1/6))

@vv a neat elaboration!

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