Elzas

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3 years, 222 days

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These are replies submitted by Elzas

@acer 

Unfortunately, B(z) - is exprtimental data, which have to be interpolated

expt - this is mistake, this is exp, sorry

 

my F(t) is defined as int(expression)..

 

I understand correctly, that i can use evalf(Int()) to accelerate computation?

 

 

@acer 

My function look like this:

 

F(t)=int((C*B(z)/(C*B(z)+P))*(1-expt(-t*(B(z)+P))),z=0..900)

here C and P are constant

B(z) - is the linear interpolated function

 

About evalhf. 

If I use F(somenumeric value) - it works,

if I use evalf(F(somenumeric value)) - it works,

for the case of evalhf(F(somenumericvalue)) I get error: Error, unable to evaluate function 'int' in evalfh

 

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