Kitonum

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18 years, 23 days

MaplePrimes Activity


These are answers submitted by Kitonum

move all terms to the left and take the numerator of the resulting fraction. In this case, the  expand  command is not required:

van_der_Waals := (p + a / V[m]^2) * (V[m] - b) = R * T:
numer((lhs-rhs)(van_der_Waals));
sort(%, V[m]);

 

restart;
Expr:=-a2/3 + a3 - (2*a4)/3 - (2*a5)/3:
Expr1:=-``(-Expr*3)/3; # The desired form
expand(Expr1); # The original form

 

Use functional notation:

restart

with(LinearAlgebra)

with(PDEtools)

with(Physics)

with(plots)

Setup(mathematicalnotation = true)

[mathematicalnotation = true]

(1)

``

U := proc (i, t) options operator, arrow; Matrix([[1+I*(q(i+1, t)-q(i, t))/lambda, I*(r(i+1, t)-r(i, t))/lambda], [I*(r(i+1, t)-r(i, t))/lambda, 1-I*(q(i+1, t)-q(i, t))/lambda]]) end proc

proc (i, t) options operator, arrow; Matrix([[1+I*(q(i+1, t)-q(i, t))/lambda, I*(r(i+1, t)-r(i, t))/lambda], [I*(r(i+1, t)-r(i, t))/lambda, 1-I*(q(i+1, t)-q(i, t))/lambda]]) end proc

(2)

``

V := proc (i, t) options operator, arrow; Matrix([[-((1/2)*I)*lambda, -r(i, t)], [r(i, t), ((1/2)*I)*lambda]]) end proc

proc (i, t) options operator, arrow; Matrix([[-((1/2)*I)*lambda, -r(i, t)], [r(i, t), ((1/2)*I)*lambda]]) end proc

(3)

NULL

z := diff(U(i, t), t)+U(i, t).V(i, t)-V(i+1, t).U(i, t)

Matrix(%id = 18446746137203957622)

(4)

NULL

Download CD_new.mw

2 errors in your code. In the EqBIS procedure, P, U, V must be Vectors, not lists. Also remove the space after the procedure name in your example (which Maple interprets as a multiplication sign). I also removed the unnecessary command RETURN:

EqBIS := proc(P, U, V)
local a, eq1, M1, t, PU, PV, bissec1;
a := (P - U)/LinearAlgebra:-Norm(P - U, 2) + (P - V)/LinearAlgebra:-Norm(P - V, 2);
M1 := P + a*t;
eq1 := op(eliminate({x = M1[1], y = M1[2]}, t));
op(eq1[2]); end proc;

EqBIS(<4, 5>, <11, 7/3>, <11, 5>);

 

restart;
F:=2*y*sin(beta*x)+6*z*cos(beta*x)+24*sin(beta*x)*cos(beta*x):
coeff(select(t->has(t,sin) and not has(t,cos),F), sin(beta*x));                              

                                              

In Maple gamma is Euler's constant, not a symbol. When you write  gamma(t) , this is a constant function, which equals  gamma  for any t .

restart;
simplify([3(t), gamma, gamma(t)]);
evalf(%);

                                            [3, gamma, gamma]
                               [3., 0.5772156649, 0.5772156649]
 

In the second example  gamma  is a symbol  (`&gamma;`)

The procedure checks for a match in the rows of matrices  A  and  B  and returns a list of lists  L , in which the 1st element is the matching row, and the 2nd element is a list of two numbers (how many times this row occurs in each of the matrices).
 

restart;
CheckRowsUniquie:=proc(A::Matrix,B::Matrix)
local m1, m2, A1, B1, A11, B11, k, a, b, L;
uses LinearAlgebra, ListTools;
m1,m2:=ColumnDimension(A),ColumnDimension(B);
if m1<>m2 then error "Should be ColumnDimension(A)=ColumnDimension(B)" fi;
A1:=convert(A,listlist); B1:=convert(B,listlist);
A11:=Collect(A1); B11:=Collect(B1);
k:=0;
for a in A11 do
for b in B11 do
if a[1]=b[1] then k:=k+1; L[k]:=[a[1],[a[2],b[2]]] fi;
od; od;
convert(L,list);
end proc:

A:=<1,2; 3,4; 1,2; 5,6>; B:=<0,1; 1,2; 1,2; 3,4; 7,8>;
CheckRowsUniquie(A,B);

Matrix(4, 2, {(1, 1) = 1, (1, 2) = 2, (2, 1) = 3, (2, 2) = 4, (3, 1) = 1, (3, 2) = 2, (4, 1) = 5, (4, 2) = 6})

 

Matrix(%id = 18446746714869442310)

 

[[[1, 2], [2, 2]], [[3, 4], [1, 1]]]

(1)

 


 

Download CheckRowsUniquie.mw

Just use the  RelabelVertices  command as in the example below:

restart; 
with(GraphTheory): 
G := Graph({{1, 2}, {1, 3}, {1, 4}}); 
V := Vertices(G); 
V1 := subs([1, 2]=~[a, b], V); 
H := RelabelVertices(G, V1); 
DrawGraph(H);

 

Just specify the ranges for the variables  x  and  y  and the error will disappear:

restart;
plots:-implicitplot(x-y-Pi, x=-1..5, y=-4..1);

 

Or use the  eval  command:

restart;
dgdx := (x,T)->diff(g(x, T), x);
g := (x,T)->T*x + x^2;
eval(dgdx(x,T), [x=1,T=2]);

                              

The reason for the error in OP's approach is that Maple first substitutes  x  and  y  with the numbers 1 and 2 and the result is differentiation not with respect to the variable  x , but with respect to the constant  1 .

restart;
A := <<true, false, true> | <true, false, true> | <false, false, false>>;
B := <<1, 2, 6> | <3, 4, 7> | <22, 33, 44>>;
zip((u,v)->`if`(u=true,v,`( )`), A,B);

                             

 

 

I don't know why Student:-Calculus1:-VolumeOfRevolution command distorts the colors. You may get better results if you use the  plot3d  command to draw surfaces. I also selected the edges of the cylinder (2 circles) using the  plots:-spacecurve  command:

restart;
A:=plot3d([x,4*cos(t),4*sin(t)], t=0..2*Pi, x=1..2, style=surface, color="Blue"):
B:=plot3d([[1,r*cos(t),r*sin(t)],[2,r*cos(t),r*sin(t)]], t=0..2*Pi, r=0..4, style=surface, color="Blue"):
C:=plots:-spacecurve([[1,4*cos(t),4*sin(t)],[2,4*cos(t),4*sin(t)]], t=0..2*Pi, color=black, thickness=2):
plots:-display(A,B,C, transparency=0.6, scaling=constrained, view = [0 .. 3, -5 .. 5, -5 .. 5], axes=normal, orientation = [-94,-18,11], labels = [x, y, z]); 

                     

See the following toy example:

A:=<1,2; ``,3>;
map(t->`if`(t=``,``,f(t)), A);

 

Look at these 2 graphs. We see that on a part of the range  0..2*Pi , the function takes negative values. Therefore, the square root on these intervals will take on complex values.

plot(c^2-a^2*cos(theta)^2, theta = 0 .. 2*Pi); 
plot(b^2-(a*sin(theta)+sqrt(c^2-a^2*cos(theta)^2))^2, theta = 0 .. 2*Pi);

 

You must use the  solve  command for this:

restart;
eq:=5*a^2 + 2*b - 7 = 0;
a:=1;
b=solve(eq, b);

 

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