## 7 Badges

3 years, 225 days

## Use...

Use ":=" not "=" defining sys.

sys := {1800*40 + 15*300*30 - 30*Biy = 0, -1800 + Biy + Ciy - 300*30 = 0};

solve(sys, {Biy, Ciy});

#{Biy = 6900, Ciy = 3900}

fsolve(sys);

{Biy = 6900, Ciy = 3900}

## Workaround....

In Maple fourier transform is weak and  Maple can't find it ,thats wee need a workaround.

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Download fourier.mw

## By numeric...

I doubt there's a closed form(symbolic solution) for the Inverse Laplace.

```I do not have the source of the code and the author who made it available,because I do not remember which web-page I copied from.
```

With numeric Inverse Laplace:

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Download INV-LAPLACE.mw

## Yes...

Yes,MAPLE have capabability to do multidimensional FTs,but is very weak.

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Download Fourier2D.mw

## simplify(evala(f))...

```simplify(evala(f)) assuming x>0

#1/(sinh(x)*cosh(x))```

## Another way:...

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Download plot-units.mw

## On Maple 2019...

Solution is not displayed in Maple 18,because pdsolve support for PDE's equations is still somewhat limited,
so don't be surprised if some things don't work yet.

Solution by Maple 2019:

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Download Laplace_annulardomain5.mw

## Maple 2019...

You're out of luck,probably version issue.

In Maple 2019 solve command is updated and solve your problem.

restart;

eq := 0.1 = 23.714*(-0.93205)^2/(20.3 + 61.4*0.884^x);

solve(convert(eq, rational), x);

#ln(1955501/646542)/ln(221/250)

Or using fsolve:

f := a -> fsolve(eq, x = a);
map(f, -10});

#-8.976314317

## Maple 2019...

On Maple 2019;

int(1/(1 + x + y + z)^3, z = 0 .. 1 - x - y, y = 0 .. 1 - x, x = 0 .. 1);

#-5/16 + ln(2)/2

## Similar way:...

The following code returns all pairs  [a,b]  for which a solution exists.

restart;

f := (a, b) -> irem(b*a, 10000):

N := 5000:# (Increase it if necessary)

L := []:

for a to N do

for b from a to N do

if f(a, b) = 2391 then L := [op(L), [a, b]];

end if; end do; end do;
L;

## From here, we have: Download Matrix...

From here, we have(An example):

with(LinearAlgebra);

A := Matrix([[2, -1], [-1, 2]]);

eigenvalues := Eigenvalues(A);

#Vector[column](2, [3, 1])

spectralradius := max(abs(eigenvalues));

#spectralradius := 3

See attached file for more information.

Matrix.mw

## Workaround...

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Download integral.mw

## dsolve with no error...

It should be: L[z](0)=0(I assume,of course) not  L[z](0).

Adjustment:

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Download dsolve_no-error.mw

## Hard for symbolic, easy for numerics....

For symbolic solver is hard to find a solution. With numerics it's easy.See attached file.

_equations.mw

## with(IntegrationTools):...

More info in file:

Download integral.mw

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