MechMan

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These are questions asked by MechMan


I tried to solve this double integral in Maple but didn't get the solution so how can I solve this?

Please help

restart

a := .5

.5

(1)

b := .6

.6

(2)

R := 0.1e-1

0.1e-1

(3)

E := 210000000000/(1-.3^2)

0.2307692308e12

(4)

h := a/(2*sqrt(-2*y^2+1))

.2500000000/(-2*y^2+1)^(1/2)

(5)

F1 := sqrt(tan((1/2)*Pi*h)/((1/2)*Pi*h))*[.752+2.02*h+.37*(1-sin((1/2)*Pi*h))^3]/cos((1/2)*Pi*h)

2.828427125*(tan(.1250000000*Pi/(-2*y^2+1)^(1/2))*(-2*y^2+1)^(1/2)/Pi)^(1/2)*[.752+.5050000000/(-2*y^2+1)^(1/2)+.37*(1-sin(.1250000000*Pi/(-2*y^2+1)^(1/2)))^3]/cos(.1250000000*Pi/(-2*y^2+1)^(1/2))

(6)

F4 := sqrt(tan((1/2)*Pi*h)/((1/2)*Pi*h))

2.828427125*(tan(.1250000000*Pi/(-2*y^2+1)^(1/2))*(-2*y^2+1)^(1/2)/Pi)^(1/2)

(7)

C1 := (1/2)*u*(F1^2+1.3*F4^2)/(Pi*E*R)

0.2166666666e-9*u*(8.000000001*tan(.1250000000*Pi/(-2*y^2+1)^(1/2))*(-2*y^2+1)^(1/2)*[.752+.5050000000/(-2*y^2+1)^(1/2)+.37*(1-sin(.1250000000*Pi/(-2*y^2+1)^(1/2)))^3]^2/(Pi*cos(.1250000000*Pi/(-2*y^2+1)^(1/2))^2)+10.40000000*tan(.1250000000*Pi/(-2*y^2+1)^(1/2))*(-2*y^2+1)^(1/2)/Pi)/Pi

(8)

B := int(int(C1, u = 0 .. a), y = -b .. b)

int(0.2195292312e-10*tan(.3926990817/(-2.*y^2+1.)^(1/2))*(-2.*y^2+1.)^(1/2)*[.7520000000+.5050000000/(-2.*y^2+1.)^(1/2)+.3700000000*(1.-1.*sin(.3926990817/(-2.*y^2+1.)^(1/2)))^3]^2/cos(.3926990817/(-2.*y^2+1.)^(1/2))^2+0.2853880005e-10*tan(.3926990817/(-2.*y^2+1.)^(1/2))*(-2.*y^2+1.)^(1/2), y = -.6 .. .6)

(9)

evalf(B)

int(0.2195292312e-10*tan(.3926990817/(-2.*y^2+1.)^(1/2))*(-2.*y^2+1.)^(1/2)*[.7520000000+.5050000000/(-2.*y^2+1.)^(1/2)+.3700000000*(1.-1.*sin(.3926990817/(-2.*y^2+1.)^(1/2)))^3]^2/cos(.3926990817/(-2.*y^2+1.)^(1/2))^2+0.2853880005e-10*tan(.3926990817/(-2.*y^2+1.)^(1/2))*(-2.*y^2+1.)^(1/2), y = -.6 .. .6)

(10)

 

(11)

``


 

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