Oliver K

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10 years, 327 days

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These are replies submitted by Oliver K

Here a way:

A:={1,2,4,6,7,10};
{$1..10} minus A;

Here a way:

A:={1,2,4,6,7,10};
{$1..10} minus A;

Are you sure your formula is correct ? The argument of the root becomes negative for some t.

You could add 2 plots to Roberts code, covering the axes, to change the appearance as you like. If necessary, you could do the same for the tickmarks.

restart:with(plots):
P1:=pointplot([[2,3],[-3,1],[-1.5,-2.5],[0,0]],colour=[green, red, blue, magenta],symbol=solidcircle,symbolsize=12):
P2:=plot([[[0,3],[2,3],[2,0]],[[-3,0],[-3,1],[0,1]],[[-1.5,0],[-1.5,-2.5],[0,-2.5]]],linestyle=dash,colour=[green, red, blue]):
P3:=textplot([[2.2,3.3,"(2,3)"],[-2.8,1.3,"(-3,1)"],[-1.8,-2.8,"(-1.5,-2.5)"],[.4,.4,"(0,0)"]],colour=[green,red,blue,magenta]):
P4:=plot([t,0,t=-5..5],thickness=2,colour=black):
P5:=plot([0,t,t=-5..5],thickness=2,colour=black):
display(P4,P5,P1,P2,P3,scaling=constrained,view=[-3.9..3.9,-3.9..3.9],labels=[x,y]);

You could add 2 plots to Roberts code, covering the axes, to change the appearance as you like. If necessary, you could do the same for the tickmarks.

restart:with(plots):
P1:=pointplot([[2,3],[-3,1],[-1.5,-2.5],[0,0]],colour=[green, red, blue, magenta],symbol=solidcircle,symbolsize=12):
P2:=plot([[[0,3],[2,3],[2,0]],[[-3,0],[-3,1],[0,1]],[[-1.5,0],[-1.5,-2.5],[0,-2.5]]],linestyle=dash,colour=[green, red, blue]):
P3:=textplot([[2.2,3.3,"(2,3)"],[-2.8,1.3,"(-3,1)"],[-1.8,-2.8,"(-1.5,-2.5)"],[.4,.4,"(0,0)"]],colour=[green,red,blue,magenta]):
P4:=plot([t,0,t=-5..5],thickness=2,colour=black):
P5:=plot([0,t,t=-5..5],thickness=2,colour=black):
display(P4,P5,P1,P2,P3,scaling=constrained,view=[-3.9..3.9,-3.9..3.9],labels=[x,y]);

@Wang Gaoteng 

 

http://www.guitar-list.com/download-software/convert-sketchup-skp-files-dxf-or-stl

@Wang Gaoteng 

 

http://www.guitar-list.com/download-software/convert-sketchup-skp-files-dxf-or-stl

Another approach is to plot the corresponding implicitly given function and restrict the view range.

 

restart:with(plots):
g:=(z-1)^2=4-x^2-y^2;
implicitplot3d(g,x=-2..2,y=-2..2,z=1..3,scaling=constrained,axes=framed,grid=[20,20,20]);

Sorry, can't open your msim file, I don't know why.

Rewriting those inequalities as a single one in product form does the trick, thanks

Rewriting those inequalities as a single one in product form does the trick, thanks

@Preben Alsholm 

yes, now I remember this convert subcommand. In my opinion, this is a point where Maple needs to be improved: Expression manipulation in an intuitive way. Maybe restructuring the context sensitive menu would help here, I don't know.

@Preben Alsholm 

yes, now I remember this convert subcommand. In my opinion, this is a point where Maple needs to be improved: Expression manipulation in an intuitive way. Maybe restructuring the context sensitive menu would help here, I don't know.

I don't think discont is to blame here. Maple has a mechanism that  "simplifies" terms like x/x to 1 immediately. discont just gets the simplified input in the latter case.

I don't think discont is to blame here. Maple has a mechanism that  "simplifies" terms like x/x to 1 immediately. discont just gets the simplified input in the latter case.

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