## 15 Reputation

0 years, 165 days

## @dharr  Is there no way to solve it...

@dharr  Is there no way to solve it with Maple?

## @dharr  Hi.   ...

@dharr  Hi.

 >
 > equation is:

 >
 >
 >
 (1)
 >
 (2)

condition: u(x,0)=,    u(0,t)=,

 (3)
 >
 (4)
 >
 (5)
 >
 (6)

Desired output is: U

U(,0)=πδ()

 (7)
 >

 >
 > equation is:

 >
 >
 >
 (1)
 >
 (2)

condition: u(x,0)=,    u(0,t)=,

 (3)
 >
 (4)
 >
 (5)
 >
 (6)

Desired output is: U

U(,0)=πδ()

 (7)
 >

Why not get the correct answer for the equation below?

## new question...

@Rouben Rostamian  You helped me earlier. Can you help Fourier transforms partial differential equations with initial and boundry condition? the equation and the it;s Fourier transform are in following. thanks alot

 >
 >
 (1)

condition: u(x,0)=x,    u(0,t)=t,

 >
 (2)
 >
 (3)
 >

I want to get this equation:

(,0)=i(i+π)/

id fourier transform of u

 >

@dharr Thank you

## @nm  Because I wanted to show the e...

@nm  Because I wanted to show the equation and the answer I want to make

 >
 >
 (1)

condition: u(x,0)=x,    u(0,t)=t,

 >
 (2)
 >
 (3)
 >

I want to get this equation:

(,0)=i(i+π)/

id fourier transform of u

 >

## @Rouben Rostamian   I encountered a...

@Rouben Rostamian   I encountered a problem. If the m1 changes to

m1 := (1/2)*b11*ro*Pi*R^2*exp(-my*cp1/(R*p1))*(my*cp2/(R*p1)-cp3)/p1;

, Maple can not integrate againcorrected2.mw

## @Rouben Rostamian  thank you so muc...

@Rouben Rostamian  thank you so much

## @Rouben Rostamian   Thank you so mu...

@Rouben Rostamian   Thank you so much . But a question.

for example in fact v[2] is a function of time and p1.  not defining it as a function of time and p1 does not create  problem? and do not need to be expressed as a function of time and p1 in the following command?
 dsolve({g, v[3](20)=0}, v[3](t));

for example dsolve({g, v[3](p1,20)=0}, v[3](t));

thank you

## @Rouben Rostamian   Oh, sorry, I f...

Oh, sorry, I forgot save Pi istead pi in sendenig file. m1(p1, my(t))  It is a part of my differential equation that is defined for simplicity separately as m1 that  which itself is a function of p1 and my(t). Thanks

## code...

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