@Carl Love I did Carl, but i again have this problem. As it is, you might like to check your self that for A=2, should compute anything but it does not (e.g cv). Actually i tried myself a simplest system and i again face this problem, which basically happens when one equation depends on other equation ... Is anything else i am missing ?  

@Carl Love I did Carl, but i again have this problem. As it is, you might like to check your self that for A=2, should compute anything but it does not (e.g cv). Actually i tried myself a simplest system and i again face this problem, which basically happens when one equation depends on other equation ... Is anything else i am missing ?  

I did Carl, but i again have this problem. As it is, you might like to check your self that for A=2, should compute anything but it does not (e.g cv). Actually i tried myself a simplest system and i again face this problem, which basically happens when one equation depends on other equation ... Is anything else i am missing ?  

Thank you Carl, but it seems that does not calculate some expressions. Do you know what is needed to calculate those too ? 

Thank you Carl, but it seems that does not calculate some expressions. Do you know what is needed to calculate those too ? 

You linearize the system, i.e (usually 1st order ) Taylor expansion around a steady state. I guess maple cannot handle this from what i looked so far. 

Sorry, I made a mistake with the system. This is itm wither (t+1) is one period forward  

2.097*k(t+1) = .9525000000*k(t)^.35-(2.097)*b(t+1) and

(2.097)*b(t+1) =(2.0955/k^.67)*b(t) -.2

I forgot something crucial further to my comment send before. The feasible region for my parameters are 0<alpha<=0.9 and 0.1<=beta<=0.99

So basically i am in search for parameters values that make my k positive in the first hand, and in the second hand in search of parameters values in that particular regions specified that might make K, let's say one. 

Many Thanks 

Thank you so much, helped me a lot. Although the if alpha = 0 then print(`No solutions`) , gives me an error. One more thing, Is it possible to find the set of my parameters, or values of my parameters (alpha,beta) that makes my k positive all the time, or when for example makes it exactly one?. Can Maple handle this ? 

Secondly, assume that this expression is a partial derivative (F[k]= my expression above) that depends on k (my main variable), given than k must be non-negative, how I can find for which parameter values my derivative will be positive and for which negative or zero ? Is this again feasible ? Of course beta must be different from -1, as you also mentioned.  

Any help on this will be much appreciated