fatyplus

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4 years, 61 days

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These are replies submitted by fatyplus

@Axel Vogt 

thank you for the answer

I did tell the sys that Z' is diff(Z,x)

and using evalc don't bring me to the right answer, I got this expression:

(cos((1/2)*theta)*cos((1/4-(1/4)*signum(r))*Pi)/sqrt(abs(r))-sin((1/2)*theta)*sin((1/4-(1/4)*signum(r))*Pi)/sqrt(abs(r)))*A0+((1/2)*cos((1/2)*theta)*sqrt(abs(r))*(1+signum(r))-(1/2)*sin((1/2)*theta)*sqrt(abs(r))*(1-signum(r)))*A1+(cos((3/2)*theta)*abs(r)^(3/2)*cos((3/4-(3/4)*signum(r))*Pi)-sin((3/2)*theta)*abs(r)^(3/2)*sin((3/4-(3/4)*signum(r))*Pi))*A2

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