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syahirah rahimi

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finding average error in maple...

syahirah rahimi 15 Maple 2022
duplicate-question
May 30 2023
1 0

I desire to find the summation value of errors from EA1 to EA19. After finding the summation, i want to find the average error. Can any of experts show how the maple should be done?

> 

restart

ERROR COMPARISON

 

> 

n := [84, 83, 83, 81, 85, 86, 86, 83, 82, 83, 84, 83, 81, 80, 83, 79, 82, 81, 85]

[84, 83, 83, 81, 85, 86, 86, 83, 82, 83, 84, 83, 81, 80, 83, 79, 82, 81, 85]

 (1)
> 

nops(n)

19

 (2)
• 

-BBDF*FORMULA*FORWARD+PC
> 

A := [90.3333, 85.3636, 80.1313, 81.4518, 78.9241, 90.2078, 89.8305, 85.9949, 78.7198, 79.8495, 84.3264, 86.2465, 82.7222, 78.1001, 77.8260, 86.7687, 77.2371, 85.2345, 81.7439]

[90.3333, 85.3636, 80.1313, 81.4518, 78.9241, 90.2078, 89.8305, 85.9949, 78.7198, 79.8495, 84.3264, 86.2465, 82.7222, 78.1001, 77.8260, 86.7687, 77.2371, 85.2345, 81.7439]

 (3)
> 

``
> 

nops(A)

19

 (4)
> 

NULL
> 

for i to 19 do EA[i] := abs(A[i]-n[i]) end do

6.3333

  

2.3636

  

2.8687

  

.4518

  

6.0759

  

4.2078

  

3.8305

  

2.9949

  

3.2802

  

3.1505

  

.3264

  

3.2465

  

1.7222

  

1.8999

  

5.1740

  

7.7687

  

4.7629

  

4.2345

  

3.2561

 (5)
> 

``

 

> 

NULL

``

 (6)

Download error_pc-bbdf_forward_formula.mw

how to find answer by using previous an...

syahirah rahimi 15 Maple
syntax assignment
May 29 2023
1 3

 i’ve run the coding. The result is almost my expectation. However, why is the previous value not be substituted into the next one? As example, f4 should be submitted into f5 to evaluate its value

> 

restart:
> 

m := [80, 79, 83, 92, 74, 80, 87, 77, 103, 84, 87, 77, 88, 86, 83, 80, 79, 80, 93, 68, 106, 76, 103]

[80, 79, 83, 92, 74, 80, 87, 77, 103, 84, 87, 77, 88, 86, 83, 80, 79, 80, 93, 68, 106, 76, 103]

 (1)

 

> 

F := k -> `if`(
                k::even,
                2/3*m[k] + 2/3*f[k-1] - 1/3*f[k-2],
                2/11*f[k-3] - 9/11*f[k-2] + 12/11*f[k-1] + 6/11*m[k]
                ):
> 


f[2] := m[2];
f[3] := m[3];
for i from 4 to 23 do
  F(i):
end do;

79

  

83

  

271/3

  

-145/11+(12/11)*f[4]

  

160/3+(2/3)*f[5]-(1/3)*f[4]

  

(2/11)*f[4]-(9/11)*f[5]+(12/11)*f[6]+522/11

  

154/3+(2/3)*f[7]-(1/3)*f[6]

  

(2/11)*f[6]-(9/11)*f[7]+(12/11)*f[8]+618/11

  

56+(2/3)*f[9]-(1/3)*f[8]

  

(2/11)*f[8]-(9/11)*f[9]+(12/11)*f[10]+522/11

  

154/3+(2/3)*f[11]-(1/3)*f[10]

  

(2/11)*f[10]-(9/11)*f[11]+(12/11)*f[12]+48

  

172/3+(2/3)*f[13]-(1/3)*f[12]

  

(2/11)*f[12]-(9/11)*f[13]+(12/11)*f[14]+498/11

  

160/3+(2/3)*f[15]-(1/3)*f[14]

  

(2/11)*f[14]-(9/11)*f[15]+(12/11)*f[16]+474/11

  

160/3+(2/3)*f[17]-(1/3)*f[16]

  

(2/11)*f[16]-(9/11)*f[17]+(12/11)*f[18]+558/11

  

136/3+(2/3)*f[19]-(1/3)*f[18]

  

(2/11)*f[18]-(9/11)*f[19]+(12/11)*f[20]+636/11

  

152/3+(2/3)*f[21]-(1/3)*f[20]

  

(2/11)*f[20]-(9/11)*f[21]+(12/11)*f[22]+618/11

 (2)
> 

 

Download bbdf.mw

how to do loop with 2 formula...

syahirah rahimi 15 Maple
do-loop duplicate-question
May 23 2023
2 0


there’s few redundant values. I just want the positive values. How it can be done?

> 

restart
> 

NULL
> 

n := [80, 79, 83, 84, 83, 83, 81, 85, 86, 86, 83, 82, 83, 84, 81, 80, 83, 79, 82, 81, 85]

[80, 79, 83, 84, 83, 83, 81, 85, 86, 86, 83, 82, 83, 84, 81, 80, 83, 79, 82, 81, 85]

 (1)
> 

``
> 

nops(n)

21

 (2)
> 

for i from 3 to 17 do f[i] := n[i-2]-3*n[i-1]+3*n[i]; i = i+1; f[i+1] := n[i-2]+4*n[i-1]-6*n[i]+n[i+1] end do

92

  

3 = 4

  

-18

  

82

  

4 = 5

  

-10

  

80

  

5 = 6

  

4

  

84

  

6 = 7

  

-1

  

77

  

7 = 8

  

14

  

95

  

8 = 9

  

-17

  

84

  

9 = 10

  

-9

  

85

  

10 = 11

  

-4

  

77

  

11 = 12

  

14

  

83

  

12 = 13

  

9

  

86

  

13 = 14

  

-3

  

85

  

14 = 15

  

-9

  

74

  

15 = 16

  

13

  

81

  

16 = 17

  

11

  

90

  

17 = 18

  

-18

 (3)
> 

``
> 

NULL


 

Download fyp_2.mw

how to solve do- looping question in Map...

syahirah rahimi 15 Maple
May 19 2023
2 0

why the output wont appear eventhough I think the working is right?

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