445 Reputation

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6 years, 90 days
Maple is to me difficult. The first version I bought was Maple9, and it was more than 15 years ago. But, I couldn't use it, feeling it too difficult. But, three years ago, I thought Maple might be helpful to my study, and since then, I have continued to learn Maple. As I got able to read the Maple help, I think that I could get to use maple better now than before. But, I feel that I am a beginner yet.

MaplePrimes Activity

These are replies submitted by taro

@Markiyan Hirnyk 

Thank you for telling me how to repeat expand for a few times.

I will get to be able to use the way you showed me.

Best wishes 


@Alejandro Jakubi 


Thank you for telling me about your dividend. I will try to understand its procedure.


Best wishes




Thank you very much. I could do what I wanted to do owing to you!


@Adri van der Meer 


Thank you. I could understand what the point was owing to your comment.

taro yamada

@Adri van der Meer 

What I wanted to do is as follows.

Integral is like summation, just the integrand is continuous function of t as q(t).
In this case, I wanted to calculate


diff(u,q(k)), where q(k) is a value of q(i) for the specific i=k.

That is like 


@Adri van der Meer 

 Thank you for your reply. I m sorry to say that you might misunderstand the problem I wrote.

With the calculation you wrote, that is,
what I obtained was

2*Int(q^2, i = 0 .. M)*Int(2*q, i = 0 .. M)

This is not right, because the answer has to be

2*Int(q^2, i = 0 .. M)*2*q

 q is considered to be a vector with infinite dimension. And, for its particular element q(i), I wanted to differentiate the integral.

 Take care.




 I wanted to differentiated u with respect to q(i) with the particular i.
The reason I used q(i) not q[i] is that it is necessary for integration.
And, on the other hand, q(i) becomes variable, for a particular i.
I wanted to differentiate u with that q(i).

 Originally, I wanted to calculate this.


which shows an error message.

So, I modified this as

> v:=(Int(q(i)^2,i=0..M)+q[k]^2)^2;


4*(Int(q(i)^2, i = 0 .. M)+q[k]^2)*q[k]   (*)

appears. I don't like the expression of (Int(q(i)^2, i = 0 .. M)+q[k]^2) in the (*), and haven't been able to modify this to 4*(Int(q(i)^2, i = 0 .. M). And, with algsubs, q[k] which is in a expression outside of the original expression v, is modified, which is not good for me.

But, I think that my problem might have been settled down owing to you.

Thank you very much.




Thank you for your reply. I did as you kindly taught me.

But, the answer I could obtain through your codes was M not 1.

1 is the correct answer, which I couldn't obtain.


Take care.



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