## WHERE CAN I FIND CLICKABLE PHYSICS CLASSES IN ENGL...

You have clickable calc. Today I saw in your email that you have clickable physic but in french. Do you have it in english too>?

Thank you

manolo

## mtaylor expanssion...

Hello,

I have this expression on image below and I would like to do multi taylor in these variables. The maple says that the expansion is not possible to do. Does somebody know where the problem could be ? Thank you very much for help.

Equation:

Taylor series:

## How to plot a graph...

i solve 4 ODE with boundary condition.. i try to plot a graph F(eta) with different value of M.. but it doesnt comeout.. anyone can help me please??

 (1)

 (2)

 (3)

 (4)

 (5)

 (6)

 (7)

 (8)

 (9)

 (10)

 (11)

## I am so close to plot what I need but......

Hi everybody,

In quantum mechanics, I want to draw the wave  of the electron in the hydrogen atom.  So in 3D, you will have a cricle and along the circle, there will be a cosine function that will meet after a full cercle (the standing wave that is possible).  The blue one and the red one at the same time.  But in 3D

The closest that I come to succes is with this commands:

But as you will see, the wave end at the same place as it started.  But instead of going in a cercle, is as a funny shape.

Thank you in advance for you trouble.

--------------------------------------
Mario Lemelin
Maple 18 Ubuntu 13.10 - 64 bitsMaple 18 Win 7 -  64 bits
messagerie : mario.lemelin@cgocable.ca
téléphone :  (819) 376-0987

## Components of speed and acceleration.

Maple 18

With the package VectorCalculus we can study the speed and acceleration to their respective components. Considering the visualizaccion and algebraic calculations and to check with their respective commands. Both 2D and 3D.

Lenin Araujo Castillo

Physics Pure

Computer Science

## An integral that cause probel with Maple...

Hi Everybody.

Doing some calculation in quantum mechanics, I stuble on that integral:

I see immediately that the answer is 1/2.  But Maple 18 cannot give an answer other than a limit that he cannot evaluate.  I even try assumption that p and hbar are realcons.  I get infinity.

Any idea?

--------------------------------------
Mario Lemelin
Maple 18 Ubuntu 13.10 - 64 bitsMaple 18 Win 7 -  64 bits
messagerie : mario.lemelin@cgocable.ca
téléphone :  (819) 376-0987

## Matrix and parallel computing / multicore...

Hi,

Is there any difference between

Matrix(4,5,(K,C)->K+C);

and

Array(1..4,1..5,(K,C)->K+C);

Say if I have a very 'complicated' procedure myfunc(K,C) that takes two options, but it runs all dependently.

Matrix(4,5,(K,C)->myfunc(K,C));

and

Array(1..4,1..5,(K,C)->myfunc(K,C));

Which one is more efficient? The final ouput of each run from myfunc is just a integer value.

The reason I am asking it that i think both runs on a 'single' thread (core) as CPU usage is always very low, around 15-20%.

If I look at the task manager, some cores (threads) arent doing anything.

Is there anyway to speed things up?

Thanks,

by: Maple 18

## Getting a value of a constant...

Hello everybody,

While doing a document about quantum mechanics, I stumble on this strange behaviour.

>with(ScientificConstants);
>GetConstant();
>GetValue()

Error message:

Error, (in ScientificConstants:-GetValue) a[0] is not a scientific constant object

But in the Assistant Scientific Constant, the value is there: 5.291772e-11m

Why is it not directly available like I did the first time?

--------------------------------------
Mario Lemelin
Maple 18 Ubuntu 13.10 - 64 bitsMaple 18 Win 7 -  64 bits
messagerie : mario.lemelin@cgocable.ca
téléphone :  (819) 376-0987

## Division of maple worksheet...

Hello,

I would like to ask if one can divide the maple worksheet (mw) to multiple files like series of command. It could be simillar to include in C++. I have found only save and read command but they can be use only for variables or they can be use in other way ?

Thank you for any possible solution,

vidocq

## cat a subscript also as an input from a function...

f:=C->sum(x[cat(new,c)],c=1..C);

f(4) # does not give me what i want , which is

x[cat(new,1)]+x[cat(new,2)]+x[cat(new,3)]+x[cat(new,4)];

seq(x[cat(new,c)],c=1..4);
convert([%],+);

This works. But it's just a simple example to illustrate my problem.

Is there a way to fix this 'cat' problem in the procedure 'f'?

Thanks,

casper

## A tiny latex (from Maple) superscripts problem...

v1:=[seq(tau[lambda,i]^2,i=1..5)];

latex(v1);

gives:

[{\tau_{{\lambda,1}}}^{2},{\tau_{{\lambda,2}}}^{2},{\tau_{{\lambda,3}}
}^{2},{\tau_{{\lambda,4}}}^{2},{\tau_{{\lambda,5}}}^{2}]

which produces a non natural output in latex, see below.

I wonder it could be improved in the future release?

'latex' command is really useful when i have large algebric output. But having to change this tiny thing at many places is just very time consuming. I'd really appreciate if this can be fixed in updates or future versions of Maple.

Casper

## simplify and function with arguments...

Hi all,

I will use the following dummy example.

with function,f

f:=(xid,yid)->sum(x[i],i=1..xid)*sum(y[i],i=1..yid);

and a complicated term, myterm

myterm:=(f(3,4)+f(2,2))*f(1,1):
myterm:=expand(myterm);

'if' i have some previous knowledge, or know a bit of the term, i can find the structure by doing this

repar:=[f(1,1),f(2,2),f(3,4)];  # Or with more f(xid,yid) terms

tmp:=seq(repar[i]=ff[i],i=1..3);
simplify(myterm,{tmp});          # This is fine, gives me what i want

But, can we go further, and more 'obvious'

Given the fucntion f, same as before, and the same 'myterm'

can I have this
restart:
iwant:=(f(3,4)+f(2,2))*f(1,1);  # as a result, straightforward

so I dont have to go back to 'repar' and find that the terms exactly are.

Thanks,

## return the indicis of a value from list...

Hi, with a list

l:=[1,1,1,2,3,3,4];

What's the best way to get the index(s) for the values equal to '1'?

Say for x=1, we want

[1,2,3]

for x=2, we want

[4]

ect.

## How to take away each element in a Vector in turn...

Hi say I have the vector V1.

V1:=Vector([a,b,c,d,e,f,g]):

and function myfun.

how do i use it as the input to the function my fun, by taking away each element in turn?
myfun(V1[2..]);              # 1st element removed
myfun(V1[[1,3..]]);         # 2nd element removed
myfun(V1[[1,2,4..]]);      # 3rd element removed

and so go

is there a more efficient way?

Many thanks,

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