Maple 2016 Questions and Posts

These are Posts and Questions associated with the product, Maple 2016

Good day house.

Please I don't know why the solve command does not display any results in the following code. Kindly assist. Thank you in anticipation.

restart;
omega := v/h;
t := sum(a[j]*x^j, j = 0 .. 6)+a[7]*cos(omega*x)+a[8]*sin(omega*x);
r1 := diff(t, x$2);
r2 := diff(t, x$4);
c1 := eval(t, x = q+2*h) = y[n+2];
c2 := eval(r1, x = q) = f[n];
c3 := eval(r1, x = q+h) = f[n+1];
c4 := eval(r1, x = q+2*h) = f[n+2];
c5 := eval(r1, x = q+3*h) = f[n+3];
c6 := eval(r2, x = q) = g[n];
c7 := eval(r2, x = q+h) = g[n+1];
c8 := eval(r2, x = q+2*h) = g[n+2];
c9 := eval(r2, x = q+3*h) = g[n+3];
b1 := seq(a[i], i = 0 .. 8);
`k≔solve`({c1, c2, c3, c4, c5, c6, c7, c8, c9}, {a[0], a[1], a[2], a[3], a[4], a[5], a[6], a[7], a[8]});

 

Please I found out that the MatrixInverse on the assignment statement P3 does not run for about three days now. Please kindly help to simplify the code. Thank you and kind regards.

restart; omega := v/h;
r := a[0]+a[1]*x+a[2]*sinh(omega*x)+a[3]*cosh(omega*x)+a[4]*cos(omega*x)+a[5]*sin(omega*x);
b := diff(r, x);

c := eval(b, x = q) = f[n];
d := eval(r, x = q+3*h) = y[n+3]; e := eval(b, x = q+3*h) = f[n+3];
g := eval(b, x = q+2*h) = f[n+2];
i := eval(b, x = q+h) = f[n+1];
j := eval(b, x = q+4*h) = f[n+4];
k := solve({c, d, e, g, i, j}, {a[0], a[1], a[2], a[3], a[4], a[5]});
Warning,  computation interrupted
assign(k);
cf := r;
s4 := y[n+4] = simplify(eval(cf, x = q+4*h));
s3 := y[n+2] = simplify(eval(cf, x = q+2*h));
s2 := y[n+1] = simplify(eval(cf, x = q+h));
s1 := y[n] = simplify(eval(cf, x = q));

with(LinearAlgebra);
with(plots);
h := 1;
YN_1 := seq(y[n+k], k = 1 .. 4);
A1, a0 := GenerateMatrix([s1, s2, s3, s4], [YN_1]);
eval(A1);
YN := seq(y[n-k], k = 3 .. 0, -1);
A0, b1 := GenerateMatrix([s1, s2, s3, s4], [YN]);
eval(A0);
FN_1 := seq(f[n+k], k = 1 .. 4);
B1, b2 := GenerateMatrix([s1, s2, s3, s4], [FN_1]);
eval(B1);
FN := seq(f[n-k], k = 3 .. 0, -1);
B0, b3 := GenerateMatrix([s1, s2, s3, s4], [FN]);
eval(B0);
ScalarMultiply(R, A1)-A0;
det := Determinant(ScalarMultiply(R, A1)-A0);
P1 := A1-ScalarMultiply(B1, z);
P2 := combine(simplify(P1, size), trig);
P3 := MatrixInverse(P2);
P4 := A0-ScalarMultiply(B0, z);
P5 := MatrixMatrixMultiply(P3, P4);
P6 := Eigenvalues(P5);
f := P6[4];
T := unapply(f, z);
implicitplot(f, z = -5 .. 5, v = -5 .. 5, filled = true, grid = [5, 5], gridrefine = 8, labels = [z, v], coloring = [blue, white]);

 

Hi all,

How to get the real and imaginary parts of this complex expression.

Thank you in advance

real_imag_parts.mw

Hello,

I want to sort the formulae to Psi and Beta, but I don't know how it works. I have tried it with sort, simplify, isolate, but that isn't what I'm searching.

It should looks like the simplier formula in the picture.

 

ab := (diff(Psii(t), t, t))*J-l[f]*(F[s, f, l]+F[s, f, r])+l[r]*(F[s, r, l]+F[s, r, r])-(1/2)*b[r]*(-F[s, r, l]*delta[l]+F[s, r, r]*delta[r]) = 0;
  / d  / d         \\                                   
  |--- |--- Psii(t)|| J - l[f] (F[s, f, l] + F[s, f, r])
  \ dt \ dt        //                                   

     + l[r] (F[s, r, l] + F[s, r, r])

       1                                                      
     - - b[r] (-F[s, r, l] delta[l] + F[s, r, r] delta[r]) = 0
       2                                                      
bc := (diff(betaa(t), t, t))*m*v*betaa(t)+F[s, r, l]*delta[l]+F[s, r, r]*delta[r]-(diff(Psii(t), t)) = 0;
    / d  / d          \\                                   
    |--- |--- betaa(t)|| m v betaa(t) + F[s, r, l] delta[l]
    \ dt \ dt         //                                   

                               / d         \    
       + F[s, r, r] delta[r] - |--- Psii(t)| = 0
                               \ dt        /    
cd := (diff(betaa(t), t))*m*v+F[s, r, l]+F[s, r, r]+F[s, f, l]+F[s, f, r]-(diff(Psii(t), t)) = 0;
   / d          \                                           
   |--- betaa(t)| m v + F[s, r, l] + F[s, r, r] + F[s, f, l]
   \ dt         /                                           

                     / d         \    
      + F[s, f, r] - |--- Psii(t)| = 0
                     \ dt        /    
F[s, f, l] := c[fl]*alpha[fl];
                        c[fl] alpha[fl]
F[s, f, r] := c[fr]*alpha[fr];
                        c[fr] alpha[fr]
F[s, r, l] := c[rl]*alpha[rl];
                        c[rl] alpha[rl]
F[s, r, r] := c[rr]*alpha[rr];
                        c[rr] alpha[rr]
alpha[fl] := (-v*betaa-l[f]*(diff(Psii(t), t)))/(-v+(1/2)*b[f]*(diff(Psii(t), t)));
                                 / d         \
                 -v betaa - l[f] |--- Psii(t)|
                                 \ dt        /
                 -----------------------------
                        1      / d         \  
                   -v + - b[f] |--- Psii(t)|  
                        2      \ dt        /  
alpha[fr] := (-v*betaa-l[f]*(diff(Psii(t), t)))/(v-(1/2)*b[f]*(diff(Psii(t), t)));
                                 / d         \
                 -v betaa - l[f] |--- Psii(t)|
                                 \ dt        /
                 -----------------------------
                       1      / d         \   
                   v - - b[f] |--- Psii(t)|   
                       2      \ dt        /   
alpha[rl] := delta[l]+(-v*betaa+l[r]*(diff(Psii(t), t)))/(-v+(1/2)*b[r]*(diff(Psii(t), t)));
                                       / d         \
                       -v betaa + l[r] |--- Psii(t)|
                                       \ dt        /
            delta[l] + -----------------------------
                              1      / d         \  
                         -v + - b[r] |--- Psii(t)|  
                              2      \ dt        /  
alpha[rr] := delta[r]+(-v*betaa+l[r]*(diff(Psii(t), t)))/(-v-(1/2)*b[r]*(diff(Psii(t), t)));
                                       / d         \
                       -v betaa + l[r] |--- Psii(t)|
                                       \ dt        /
            delta[r] + -----------------------------
                              1      / d         \  
                         -v - - b[r] |--- Psii(t)|  
                              2      \ dt        /  


ab;
                             /
                             |
/ d  / d         \\          |
|--- |--- Psii(t)|| J - l[f] |
\ dt \ dt        //          |
                             |
                             \

        /                / d         \\
  c[fl] |-v betaa - l[f] |--- Psii(t)||
        \                \ dt        //
  -------------------------------------
             1      / d         \      
        -v + - b[f] |--- Psii(t)|      
             2      \ dt        /      

           /                / d         \\\        /      /      
     c[fr] |-v betaa - l[f] |--- Psii(t)|||        |      |      
           \                \ dt        //|        |      |      
   + -------------------------------------| + l[r] |c[rl] |delta[
               1      / d         \       |        |      |      
           v - - b[f] |--- Psii(t)|       |        |      |      
               2      \ dt        /       /        \      \      

                       / d         \\
       -v betaa + l[r] |--- Psii(t)||
                       \ dt        /|
  l] + -----------------------------|
              1      / d         \  |
         -v + - b[r] |--- Psii(t)|  |
              2      \ dt        /  /

           /                           / d         \\\          /
           |           -v betaa + l[r] |--- Psii(t)|||          |
           |                           \ dt        /||   1      |
   + c[rr] |delta[r] + -----------------------------|| - - b[r] |
           |                  1      / d         \  ||   2      |
           |             -v - - b[r] |--- Psii(t)|  ||          |
           \                  2      \ dt        /  //          \
       /                           / d         \\         
       |           -v betaa + l[r] |--- Psii(t)||         
       |                           \ dt        /|         
-c[rl] |delta[l] + -----------------------------| delta[l]
       |                  1      / d         \  |         
       |             -v + - b[r] |--- Psii(t)|  |         
       \                  2      \ dt        /  /         

           /                           / d         \\         \   
           |           -v betaa + l[r] |--- Psii(t)||         |   
           |                           \ dt        /|         |   
   + c[rr] |delta[r] + -----------------------------| delta[r]| = 
           |                  1      / d         \  |         |   
           |             -v - - b[r] |--- Psii(t)|  |         |   
           \                  2      \ dt        /  /         /   

  0
bc;
 / d  / d          \\             
 |--- |--- betaa(t)|| m v betaa(t)
 \ dt \ dt         //             

            /                           / d         \\         
            |           -v betaa + l[r] |--- Psii(t)||         
            |                           \ dt        /|         
    + c[rl] |delta[l] + -----------------------------| delta[l]
            |                  1      / d         \  |         
            |             -v + - b[r] |--- Psii(t)|  |         
            \                  2      \ dt        /  /         

            /                           / d         \\         
            |           -v betaa + l[r] |--- Psii(t)||         
            |                           \ dt        /|         
    + c[rr] |delta[r] + -----------------------------| delta[r]
            |                  1      / d         \  |         
            |             -v - - b[r] |--- Psii(t)|  |         
            \                  2      \ dt        /  /         

      / d         \    
    - |--- Psii(t)| = 0
      \ dt        /    
cd;
 / d          \    
 |--- betaa(t)| m v
 \ dt         /    

            /                           / d         \\
            |           -v betaa + l[r] |--- Psii(t)||
            |                           \ dt        /|
    + c[rl] |delta[l] + -----------------------------|
            |                  1      / d         \  |
            |             -v + - b[r] |--- Psii(t)|  |
            \                  2      \ dt        /  /

            /                           / d         \\
            |           -v betaa + l[r] |--- Psii(t)||
            |                           \ dt        /|
    + c[rr] |delta[r] + -----------------------------|
            |                  1      / d         \  |
            |             -v - - b[r] |--- Psii(t)|  |
            \                  2      \ dt        /  /

            /                / d         \\
      c[fl] |-v betaa - l[f] |--- Psii(t)||
            \                \ dt        //
    + -------------------------------------
                 1      / d         \      
            -v + - b[f] |--- Psii(t)|      
                 2      \ dt        /      

            /                / d         \\                    
      c[fr] |-v betaa - l[f] |--- Psii(t)||                    
            \                \ dt        //   / d         \    
    + ------------------------------------- - |--- Psii(t)| = 0
                1      / d         \          \ dt        /    
            v - - b[f] |--- Psii(t)|                           
                2      \ dt        /                           
 

 

 

 

The sphere with radius 0.5 whose center has y coordinate = 0.5 and z coordinate = 0.5 is tangent internally to the ellipsoid centered on the origin with principal semi axes of 5, 3 and 2.

How can the x coordinate of the sphere's center be determined?

Imagine a brachistochrone shaped path made of a frictionless flexible metal strip which reacts to the force of a weighty sliding object.

Depending on its flexibility and the object's mass, what would be the strip's initial shape for fastest descent between its top and bottom? How would its shape change during the object's descent?

Perhaps an aircraft emergency escape slide or the fastest path for a slalom skier exemplify this kind of situation.

 

How can I draw a "regular looking" histogram where all the bars adjacent to each other?

I tried looking into the options for histograms with no luck. I included a picture of what kind of output I am looking for.

Thanks in advance.



I am just confused to be getting this error seeings FileTools does not encounter this error when I use it's ListDirectory command:

 

error_for_primes.mw
 

with(ImageTools):

FileTools:-ListDirectory(currentdir())

["IMG_20200116_015953.jpg", "magetools commands.mw"]

(1)

Read("H:\\MAPLE\\Image_Project", format = JPEG)

Error, (in readbytes) permission denied

 

NULL


 

Download error_for_primes.mw



I couldnt find this command in the number theory package, as far as what i am thinking of doing it should be straight forward but very long winded, so if I have missed this command throughout the packages up to Maple 2016 I would appreciate someone telling me otherwise I suppose it's what i am doing for the next few hours

https://en.wikipedia.org/wiki/Partition_(number_theory)
 

A flexible rope of constant linear density hangs from one fixed end.

The lower end is pulled aside and then released.

The rope swings back and forth with a whip-like action.

What equation of motion can be used to animate this action in Maple?

I cannot find any references through Google to the appropriate math. 

Please explain the logic used to construct the plot below.

plots:-implicitplot(r >= cos(theta), r = 0 .. 1/3, theta = 0 .. 2*Pi, filledregions, coords = polar, numpoints = 5000, scaling = constrained)

The help page for dsolve,numeric,events says that "A call to a procedure-form dsolve numeric procedure" can return the time that one or more events fired by coding the eventfire option.

I do not know how to code for this.

Please provide a simple example of a procedure-form dsolve numeric with an event that exhibits this feature.

 

Hello,

I want to write a code about numerical solving N(for example N=150) coupled differential equations (ODE ) with M boundary conditions in Maple but I do not know how to do it and I cannot find anything useful. in particular, I have trouble inserting boundary conditions which are a lot for N coupled difrential equations.

Does somebody have a code script on this matter? please let me know.

Thanks a bounch in advance.

For a spring hanging vertically from a fixed point, suppose the spring constant, k, is a function of the distance from the fixed point to the other (lowest) end of the spring (for example; the diameter of the spring's coils changes along the length of the spring) .

What ODE reflecting this situation will yield solutions for the harmonic motion of the spring after it is stretched from its equilibrium position?

I have to do a homework on the euler explicite and when I am trying to test it I get an erreor can someone help me please :)

restart;
eulerexp := proc (fin, condin, h, tmax)

local i, n, j, tab, N; N := tmax/h;

for j to 5 do

tab[1, j] := condin[1, j]

end do;

for n from 2 to N do

tab[n, 1] := tab[n-1, 1]+h;

tab[n, 2] = tab[n-1, 2]+h*fin[1](tab[n-1, 1], tab[n-1, 2], tab[n-1, 3], tab[n-1, 4], tab[n-1, 5]);

tab[n, 3] = tab[n-1, 3]+h*fin[2](tab[n-1, 1], tab[n-1, 2], tab[n-1, 3], tab[n-1, 4], tab[n-1, 5]);

tab[n, 4] = tab[n-1, 4]+h*fin[3](tab[n-1, 1], tab[n-1, 2], tab[n-1, 3], tab[n-1, 4], tab[n-1, 5]);

tab[n, 5] = tab[n-1, 5]+h*fin[4](tab[n-1, 1], tab[n-1, 2], tab[n-1, 3], tab[n-1, 4], tab[n-1, 5]);

end do;

return tab end proc;

condin := [25, 1, 2, 3, 4];
                        [25, 1, 2, 3, 4]


fin := proc (t, w, x, y, z) options operator, arrow; [2*t-4*w+5*x-6*y-z, x, z, t] end proc;
(t, w, x, y, z) -> [2 t - 4 w + 5 x - 6 y - z, x, z, t]

h := .1;
                              0.1
tmax := 20;
                               20


eulerexp(fin, condin, h, tmax);
Error, (in eulerexp) invalid subscript selector


 

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