I have downloaded MaplePlayer on my iPad.   I see that it comes with a number of "pre-recorded" programs that it can run.  Is there a way to have it run a Maple worksheet that I have written?   If so, how do I use this app to open an existing worksheet? 

Also, are there any plans for this app on the Android platform any time soon?

I have written a program and I would like to embed a check near the beginning to see if input data was entered correctly.  I have written an "if statement" to check on this and I would like the program to stop execution at this point if the "if statement" criteria are met.   I get an error saying that this command is disabled.   I have tried "stop", "end" and "quit," as I understand that they are all the same.

TwoEquations.mw

Download TwoEquations.mw

Hi all,

I have a simple transfer function like

I want to calculate the amplitude ratio and the phase shift.

Without maple I would set s=I*omega and solve for real and imaginary part to obtain the phase shift and amplitude ratio.

Is there any possibility to do that in Maple more easily?

Hi,

When I run a maple program which take a long time (in command line), I have this kind of message every second:

"memory used=43867.3MB, alloc=147.3MB, time=856.28"

Does there exist any way to avoid this display ?

Thanks in advance.

I would be grateful if anyone would comment on the compatibility of Maple 18 and MacOS 10.10 (Yosemite).

How do I get values out of solved augmented matric in 2D math input? I cannot simply assign the solutions to a value by x:=A[1,5}, because it's an augmented matrix.

http://uknowledge.uky.edu/cgi/viewcontent.cgi?article=1001&context=math_etds

Example 3.23 in page 24

degree(2*z^2 + z + 2); #2

how to convert rational function to into (something) - (something) + (something) like in the example

the example 's rational function is 2*z^2+z+2

if rational function is has denominator how to calculate?

2z^2 + z + 2 =

z+2
3


−

z−2
3


+

z+1
2


−

z−4
2


+

z
1


−

z−8
1

when calculate delta p1, what is bi? how to calculate like the example's one?

(z+i-1 i+1-j) - (z+i-bi-1 i+1-1)

sum(d,i=j) (z+i-1 i+1-j) - (z+i-bi-1 i+1-1)

3.23
(z 1) - (z-bi 1)

how to do the expansion in step 3, as i use right shift that can not calculate the same result as in the example.

x0*x1/x0 = x1; # not same as in the example for I

x1^4*x2/x1 = x2*x1^3;  # not same as in the example for I

finally would like to apply to hilbert series 1/((1+z)*(1+z^2))

Joe Riel,

I am interested in making some adjustments to the Syrup package to help tailor it to my needs (expanded error descriptions, variable partial differentiations, and others).   A little over a year ago I had some dialog about how to make Syrup changes, but the program I was working on at the time, cancelled the Maple effort...

I need guidance on (1) how the Maple code is structured so I may explore modest changes, (2) what suggestion do you have on the easiest/smartest code development environment, (3) how to compile the changed code, then (4) how to rerun the revised Syrup.

Thank you and happy holidays.
Jeff Belue

Hi, I am using Maple 18 and struggling with plotting Newton's Method.

I am wanting use the function f(x)=x^3 +cx + 1 where c is a parameter and uses 100 parameter values between -2 and 0, with 100 iterations of each parameter.

Any help would be brilliant.

Thanks in advance,

Neil

deqn4 := {4*eta^4*(diff(f(eta), eta, eta, eta))*(diff(f(eta), eta))-12*eta^3*(diff(f(eta), eta, eta, eta))*f(eta)+12*eta^4*(diff(f(eta), eta, eta))*(diff(f(eta), eta))-36*eta^3*(diff(f(eta), eta, eta))*f(eta)-24*eta^3*(diff(f(eta), eta))^2+12*eta^2*(diff(f(eta), eta))*f(eta)-36*eta*f(eta)^2-4*eta^3*(diff(f(eta), eta, eta))*(diff(f(eta), eta))-12*eta^2*(diff(f(eta), eta, eta))*f(eta)+12*eta^3*f(eta)*(diff(f(eta), eta))+36*eta^2*f(eta)^2-4*eta^3*(diff(f(eta), eta, eta, eta, eta))-12*eta^3*(diff(f(eta), eta, eta, eta))+12*eta^2*(diff(f(eta), eta, eta))-12*eta*(diff(f(eta), eta))+24*f(eta) = 0};
/
| 4 / d / d / d \\\ / d \
< 4 eta |----- |----- |----- f(eta)||| |----- f(eta)|
| \ deta \ deta \ deta /// \ deta /
\

3 / d / d / d \\\
- 12 eta |----- |----- |----- f(eta)||| f(eta)
\ deta \ deta \ deta ///

4 / d / d \\ / d \
+ 12 eta |----- |----- f(eta)|| |----- f(eta)|
\ deta \ deta // \ deta /

3 / d / d \\
- 36 eta |----- |----- f(eta)|| f(eta)
\ deta \ deta //

2
3 / d \ 2 / d \
- 24 eta |----- f(eta)| + 12 eta |----- f(eta)| f(eta)
\ deta / \ deta /

2
- 36 eta f(eta)

3 / d / d \\ / d \
- 4 eta |----- |----- f(eta)|| |----- f(eta)|
\ deta \ deta // \ deta /

2 / d / d \\
- 12 eta |----- |----- f(eta)|| f(eta)
\ deta \ deta //

3 / d \ 2 2
+ 12 eta f(eta) |----- f(eta)| + 36 eta f(eta)
\ deta /

3 / d / d / d / d \\\\
- 4 eta |----- |----- |----- |----- f(eta)||||
\ deta \ deta \ deta \ deta ////

3 / d / d / d \\\
- 12 eta |----- |----- |----- f(eta)|||
\ deta \ deta \ deta ///

2 / d / d \\ / d \
+ 12 eta |----- |----- f(eta)|| - 12 eta |----- f(eta)|
\ deta \ deta // \ deta /

\
|
+ 24 f(eta) = 0 >
|
/
init4 := { {f(0) = 1, (D(f))(0) = 0, ((D@@2)(f))(0) = 0, ((D@@3)(f))(0.1e-2) = 0} };
{{f(0) = 1, D(f)(0) = 0, @@(D, 2)(f)(0) = 0,

@@(D, 3)(f)(0.001) = 0}}
dsol4 := dsolve(deqn4 union init4, numeric, method=rkf45);

Error, (in dsolve/numeric/process_input) system must be entered as a set/list of expressions/equations

Can maple solve maximization problem like

q := proc (a, b, c) options operator, arrow; .2*b+.1*c end proc;
print(`output redirected...`); # input placeholder
(a, b, c) -> 0.2 b + 0.1 c
w := proc (a, b, c) options operator, arrow; .7*a+.1*c end proc;
print(`output redirected...`); # input placeholder
(a, b, c) -> 0.7 ab + 0.1 c
e := proc (a, b, c) options operator, arrow; .7*a+.2*b*c end proc;
print(`output redirected...`); # input placeholder
(a, b, c) -> 0.7 a + 0.2 b c

with(Optimization)

Maxmize(int(min(100+(.7*a+q)*(1/2), a), q)+int(min(100+(.2*b+w)*(1/2), b), w)+int(min(100+(.1*c+e)*(1/2), c), e)-a-b-c-ab-ac-bc)

Error, (in Optimization:-NLPSolve) cannot convert procedures to piecewise

Thanks alot if you can help me.Urgent! Really appreciate.

Hi there,

I used the following plot command in maple13.

with(plots):

implicitplot(abs(x)+abs(y)=2, x=-2..2, y=-2..2, scaling=constrained)

But the output(square) is not complete at vertices.In fact at the vertex the graph is like a trapezoid.

Any help will be appreciated.

Yegan

> restart;
> with(plots);
> Eq1 := diff(f(eta), eta, eta, eta)+f(eta)*(diff(f(eta), eta, eta))-2*(diff(f(eta), eta))^2-M^2*(diff(f(eta), eta)) = 0;
/ d / d / d \\\ / d / d \\
|----- |----- |----- f(eta)||| + f(eta) |----- |----- f(eta)||
\ deta \ deta \ deta /// \ deta \ deta //

2
/ d \ 2 / d \
- 2 |----- f(eta)| - M |----- f(eta)| = 0
\ deta / \ deta /
> Eq2 := 1+(4/3)*R*(diff(theta(eta), eta, eta))+Pr*(f(eta)*(diff(theta(eta), eta))-(diff(f(eta), eta))*theta(eta)) = 0;
4 / d / d \\
1 + - R |----- |----- theta(eta)||
3 \ deta \ deta //

/ / d \ / d \ \
+ Pr |f(eta) |----- theta(eta)| - |----- f(eta)| theta(eta)| = 0
\ \ deta / \ deta / /
> bcs1 := f(0) = S, (D(f))(0) = 1+L*G, (D(D(f)))(0) = .1, f(6) = 0;
f(0) = S, D(f)(0) = 1 + L G, @@(D, 2)(f)(0) = 0.1, f(6) = 0
> fixedparameter := [S = .1, M = .1];
[S = 0.1, M = 0.1]
> Eq3 := eval(Eq1, fixedparameter);
/ d / d / d \\\ / d / d \\
|----- |----- |----- f(eta)||| + f(eta) |----- |----- f(eta)||
\ deta \ deta \ deta /// \ deta \ deta //

2
/ d \ / d \
- 2 |----- f(eta)| - 0.01 |----- f(eta)| = 0
\ deta / \ deta /
> fixedparameter := [R = .1, Pr = .7];
[R = 0.1, Pr = 0.7]
> Eq4 := eval(Eq2, fixedparameter);
/ d / d \\ / d \
1 + 0.1333333333 |----- |----- theta(eta)|| + 0.7 f(eta) |----- theta(eta)|
\ deta \ deta // \ deta /

/ d \
- 0.7 |----- f(eta)| theta(eta) = 0
\ deta /
> bcs2 := theta(0) = 1+T*B, (D(theta))(6) = B, theta(6) = 0;
theta(0) = 1 + T B, D(theta)(6) = B, theta(6) = 0

> T := .1; B := .1;
0.1
0.1
> L := [0., .1, .2, .3];
[0., 0.1, 0.2, 0.3]
> for k to 4 do R := dsolve(eval({Eq3, Eq4, bcs1, bcs2}, L = L[k]), [f(eta), theta(eta)], numeric, output = listprocedure); Y || k := rhs(R[2]); YL || k := rhs(R[3]) end do;
Error, (in dsolve/numeric/bvp/convertsys) too many boundary conditions: expected 6, got 7
> plot([YL || (1 .. 4)], 0 .. 6, 1 .. -.2, labels = [eta, diff(f(eta), eta)]);

Consider the function

The above definition may result in four cases depening on r and x.

Can Maple calculate automatically all possible cases and the corresponding Maxima, Minima and Values at intervals limits?