Hi,

I would like to apply watson lemma on f(t) = 1/((t+1)*((t/a)-1)), with a a constant, and x tending to infinity.

The problem is that my integral I have to compute is not from 0, but from a....

My integral is : I = int (exp(-x*t)*(t^(λ))*f(t), t=a..∞), with λ>-1, x->∞.

I know that if a=0, and (taylor expansion) f(t) = ∑ b_n*(t^n), n=0..∞, then

I = ∑ b_n*Γ(λ+n+1)/(x^(λ+n+1)), n=0..∞.

Hi,

I'm trying to do get the Inverse of Matrix A, I tried this:

> restart;
> with(LinearAlgebra);
> A := Matrix(4, 4, [[1, 0, 0, 0], [0, 1, 0, 0], [1, l, l^2, l^3], [0, 1, l, l^2]]);
                     Matrix(%id = 83774380)
> B := MatrixInverse(A);
Error, (in LinearAlgebra:-MatrixInverse) singular matrix

 And got an error, could someone help me.

Thanks

I have a matrix m with 9 rows and 4 columns and when I enter the command below I get an error message:

num := product((z-(m[s,1]+I*m[s,2])),s = 1..9);
Error, Matrix index out of range

However, there is no problem if I use brute force:

If I extract the denominator of the following expression

> s:=(1/2/Pi+Q*(1-u^2)/(1+u^2))^2/((1+beta^2*(1/2/Pi+Q*(1-u^2)/(1+u^2))^2)*(1+u^2));

maple expands it automatically

s2:=denom(s);

but the result of solving the expanded denominator

solve(s2=0,u);

is different to the result of solving the non-expanded expression

Now that Maple 15 is out, I thought I should share this little application I made: GoalTracker.mw. It is an application partially inspired by the BMI tracker in Nintendo's WiiFit application; you could easily use it to track a weight loss goal. But it could also be used to track other quantifiable goals. I am posting it here mostly because it takes advantage of two new features in Maple 15.

Ukraine-2011. The State Final Certification in Mathematics

What must be able to solve a graduate of the Ukrainian school in 2011?
31 variant assignments.
Currently:
 1. Assignments reformatted in Maple.
 2. Created an interactive...

of the system {x^2+y^2+z^2-2*x-4*y-6*z+13 = 0, 2*x^2+3*y^2+z^2-4*x-12*y+6*z-2 = 0} with Maple?

PS. Mathematica 7 solves it.

Hi,

I'm currently using a gridded search to find a global minimum.  I have 4 parameters which results in a really large search size (100 steps per parameter).  In order to reduce my computation time, I'd like to use a gradient search instead.  Does anyone have any code?

Thanks

Hill

Hi.i want to draw the picture which is in this SITE http://www.resurs.az/thumbnail.php?file=Qafqaz_Uni_370925279.jpg&size=article_medium  .Please help me...

 

I am very new to Maple and am trying to teach myself until next semester when I will be taking a course.

I am trying to make a GUI based worksheet to display a plot of a vector valued function (in R^2) and its velocity and acceleration vectors. I wrote code in a worksheet and it seems to work, but I am having trouble getting the plot to work when I put the code in a slider (to update continuosly as the value of t changes with the slider). I understand there are differences...

In the following examples I attempt to remove integer multiples of Pi from sin/cos. Nothing works.

Why? How do I make it work?

Thank you.

term1:=cos(Pi*(3*a-2*n));
> term2:=cos(3*Pi*a+2*Pi*n);
> term3:=cos(3*Pi*a-2*Pi*n);

                     term1 := cos(Pi (3 a - 2 n))


       ...

 Work plan for the Russian Maple Application Center in 2011.

 1. Popularization of the new features of Maple 15.
 2. Popularization of educational MAC-articles.

 3. The transformation of the most popular Russian-language Internet maths textbook to the business card of Maple.
 4. Further approval of Maple as the best assistant in preparation for the delivery of the Single State Exam (Russia).
 5. Further approval of Maple...

In the new Maple 15, if any calculation or process requires more than a few seconds, the cursor does not change to the hourglass (or equivalent) symbol. This makes it difficult to tell whether anything is happening and gives the impression that the program has hung.

I suggest that the hourglass (or equivalent) be resurrected whenever anything takes more than a few seconds.

any of the numerical factors that multiply the successive terms in the expansion of an expression of the form  (x + a)^n,  for integral n,  in accordance with the binomial  theorem. These are any terms of the form
               ∑x^(n-k)*a^k*binomial(n,k)

how to get it.

convert((x+a)^n,Sum,x)

but ,i get a anwer that i don't want

Dear all!

I wrote a program but when I run it I get an error as: " can not evaluate the solution further right of ..., maxfun limit exceeded ". I tried some ways to work around it, for example I tried "maxfun=500000" and more. Also I tried "maxfun=0", but they don't work. How can I solve my problem?

O.K. Isolved this problem myself. We can solve such a problem in two different ways. 1.by adding the expression "method=mebdfi" and 2. by adding expression "'stiff=true'".